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Thermal Stresses-Advanced Physics-Presentation, Slides of Physics

This presentation is for Physics subject project. It was task assigned by Prof. Adishree Yajnadhar at Central University of Kerala. It includes: Thermal, Stresses, Linear, Stress, Strain, Law, Thermal, Energy, Constant, Matrix

Typology: Slides

2011/2012

Uploaded on 07/17/2012

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7/8/2012 Thermal Stresses 1
Thermal Stresses
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7/8/2012 Thermal Stresses 1

Thermal Stresses

7/8/2012 Thermal Stresses 2

1

E

  E    T 

0   T

Linear stress/strain law with initial thermal strain.

7/8/2012 Thermal Stresses 4

     

      

    

V

0

T

T 0 T

T

T 0

U u dV

D 2

1 u

2

1 u

Strain Energy

7/8/2012 Thermal Stresses 5

         

    

            

 ^ ^ ^ ^ ^ ^  ^ ^ ^ ^ ^ ^ 

    

    

 

      

V

T

T T

T T

V

T

T T

V

T

T T

d B D B d dV 2

1 U

B d D B d dV 2

1 U

B d

D dV 2

1 U

Strain Energy

7/8/2012 Thermal Stresses 7

       

       

^ ^ ^ ^ ^ 

V

T

T T

V

T

T T T

V

T T L

D dV

U d B D dV

U d B D B d dV

Constant

Strain Energy

7/8/2012 Thermal Stresses 8

 

 

     

 

      (^) TV

T

T T

V

L T

L T

B D dV f

d

U

B D B d dV

d

U

d

U

U U U

7/8/2012 Thermal Stresses 10

Thermal Strain Matrix

(one-dimensional bar):

 

 

 

     T

E TA

E TA

f

f f

L

1

L

1 B

D E

T x T

T 2

T 1 T

    

   

 

 

  

  

7/8/2012 Thermal Stresses 11

Thermal Strain Matrix

(two-dimensional element):

 

 

 

 

 

     

 

 

 

  

 

 

 

 

 

   

 

 

 

  

0

T

T 1

PlaneS train

0

T

T

PlaneS tress

T

T

T

T

T

T

xy

y

x T

xy

y

x T

7/8/2012 Thermal Stresses 13



 





m

m

j

j

i

i

T

T

T

T

Et T

f

f

f

f

my

iy

ix

^21

Plane Stress :

7/8/2012 Thermal Stresses 14

Procedure

  1. Evaluate thermal force matrix and treat this as an equivalent nodal force matrix.
  2. Apply: {F}=[K]{d}-{F 0 }.
  3. If only thermal loads are present, then {F 0 }=[K]{d}.
  4. Back-substitute known {d} to obtain element nodal forces, stresses, and strains.

7/8/2012 Thermal Stresses 16

 

 

  

 

  

 

E TA

E TA f

1 1

1 1

L 2

AE k

T

For each element:

7/8/2012 Thermal Stresses 17

 

 

 

 

 

 

 

 

 

 

 

 

  

 

0 1 1

1 2 1

1 1 0

L 2

AE K

E TA

0

E TA

E TA

E TA E TA

E TA

fT

Assembling Global Matrices:

7/8/2012 Thermal Stresses 19

lb

42000

F
F
F
E TA
E TA
E TA
E TA
F
F
F

3 x

2 x

1 x

3 x

2 x

1 x

Reaction Forces:

7/8/2012 Thermal Stresses 20

10500 psi 4 in

42000 lb

2

 

  

Axial Stress: