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Stereochemistry: Understanding Chiral Molecules and Their Isomers, Essays (university) of Mathematics for Architecture

An excerpt from a chemistry textbook by d.m. Collard, focusing on chapter 5 of topic 4: stereochemistry. The three-dimensional structure of organic molecules, recognizing isomers, chirality, and designating configurations. It also includes problems for practice.

What you will learn

  • How can you separate enantiomers using a pure enantiomer of an amine and diastereomeric ammonium carboxylates?
  • What are the differences between enantiomers, diastereomers, and meso compounds?
  • How do you determine the configuration of a stereocenter using the Cahn-Ingold-Prelog system?
  • What is the relationship between the R and S configurations and the dextrorotatory and levorotatory terms?
  • What is the difference between achiral and chiral compounds, and how do you determine if a compound is chiral?

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D.M. Collard 2007
TOPIC 4. STEREOCHEMISTRY
(Chapter 5)
L
OBJECTIVES
1. Discuss the three-dimensional structure of organic molecules
2. Recognize enantiomers, diastereomers, meso compounds
3. Provide R/S designations of stereocenters
4. Calculate optical rotations, enantiomeric excesses
5. Use molecular models to determine the 3D arrangement of atoms in
chiral molecules
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TOPIC 4. STEREOCHEMISTRY

(Chapter 5)

L

OBJECTIVES

  1. Discuss the three-dimensional structure of organic molecules
  2. Recognize enantiomers, diastereomers, meso compounds
  3. Provide R/S designations of stereocenters
  4. Calculate optical rotations, enantiomeric excesses
  5. Use molecular models to determine the 3D arrangement of atoms in chiral molecules

RECOGNIZING ISOMERS

Isomers Compounds with same molecular formula, but different structures

Constitutional Isomers Different connectivity

Stereoisomers Same connectivity, different three dimensional arrangement

Enantiomers Non-superposable mirror images

Diastereomers Stereoisomers which are not enantiomers, includes geometic isomers

S:5.1-

CHIRALITY: ENANTIOMERS

An object (molecule) which has a non-superposable* mirror image is chiral (the opposite of chiral is “achiral”).

  • Important small print: In spite of Solomon and Fryhle’s foonote regarding the dictionary definition of superposable and superimposable (and their preference for the former), most chemists refer to non-superimposability of mirror images as a requirement for chirality. This instructor will undoubtedly use “superimposability” in lecture and on exams.

Prob 5.30,31, 35a,b,f

S:5. 5.5-5.

Problem: Which of the following are identical to the first structure?

H

H 3 C COOHOH

CH 3

HO HCOOH

COOH

H 3 C OHH

COOH

H 3 C HOH

H

HOOC CH

3

OH

COOH

H OHCH^3

Problem: Which of the following are identical to the first structure?

Problem: Which of the following are identical to the first structure?

Designating Configuration

Stereocenters are designated as having either R - or S -configurations
.

  • Assign priorities to the substituents using the Cahn-Ingold-Prelog system (briefly, atoms are ranked in order of atomic number (if isotopes are present, the heavier isotope has higher priority); if two atoms are identical, the next set of attached atoms is considered).
  • View the molecule with the lowest priority (4) substituent pointing away from you.
  • Trace from highest priority (1) to second priority (2), to third (3)
.

Clockwise = R

Counterclockwise = S

e.g. , F

Br H Cl

D
HO CH^3
H

D = deuterium = 2 H; D > H

Ranking Substituents

If the atoms joined to the chiral center are identical, you must consider the set of three atoms connected to them:

A double bond is considered to be two bonds to the next atom:

C(CH 3 ) 3 CH(CH 3 ) 2 CH 2 CH 3 CH 3
C(C,C,C) C(C,C,H) C(C,H,H) C(H,H,H)
CH 2 OH
C(O,H,H)
C(CH 3 ) 3
C(C,C,C)
C CH 2
H
C(C,C,H)
C O
H
C(O,O,H)
CH 2 OH
C(O,H,H)

Orient the molecule so that substituents oriented up and down are pointing away from you and then apply a steamroller.

Converting a Fischer projection back into a 3D tetrahedral representation.

C http://www.r-r-a.org.uk/aandp.html

D (^) AB

CH (^3)

CH 2 CH (^3)

HO H

FISCHER PROJECTIONS

(molecules with one stereocenter)

S:5. Prob: 5.35k-l

L

Problem : Which of the following represent the S -enantiomer of 2-phenyl-1- ethanol, which ones are R?

Me

H

Ph OH

Ph

OH

H Me

OH

Ph

H Me

OH

Ph HMe^ HO^ Me

HPh

Problem : Which of the following are identical to the first structure? [You should be able to work out how Fischer projections can be redrawn without inverting the configuration]

COOH

CH 3

H OH

H

OH

H 3 C COOH

COOH

CH 3

HO H

COOH

CH 3

H OH

CH 3

COOH

HO H

OH

H

HOOC

r otate by 90 o^ rotate by 180 o^ r otate by 270 o

swap hor izontal substit uent s swap vertical substituents

CH 3

COOH

OH

H 3 C H

rotate set of subst ituents

WHY IS STEREOCHEMISTRY

IMPORTANT?

Chirality in Nature

Most biomolecules are chiral and only exist as one enantiomer in nature.

Amino acids Carbohydrates Nucleotides (in proteins) (sugars) (in DNA) e.g. , valine e.g. , glucose e.g. , cytosine

Problem: What is the configuration of each stereocenter (chiral carbon atom) in each of the above compounds?

HO O

OH H

H H H H

N

N

NH 2

O HO

O

H

H

HO

H

HO

H (^) OH

H

OH

H 2 N

O

OH

HCH(CH 3 ) (^2)

S:5.1; 5.4; 5.

ROTATION OF PLANE-POLARIZED LIGHT

Enantiomers have identical physical and chemical properties in the absence of other chiral molecules, except for their influence on plane- polarized light.

Polarimetry

Prob:5.42; 43

S:5.8-5.

Optical Rotation

The observed rotation is: α

The observed specific rotatation is: [α] = α / c · l

where c = concentration of solution (in g/mL) and l = pathlength in dm

(1 dm = 10 cm = 10 -1^ m)

α and [α] depend on solvent, temperature and wavelength of the

polarized light. Generally the sodium D line is used for the light source and the experiment is done at room temperature, 25 °C.

The specific rotation is then noted as

The specific rotation of an optical pure chiral compound is a “property” (like melting point or boiling point)

The specific rotation, [α],of a given sample depends on its “optical

purity”. Only the excess of one enantiomer over the other gives rise to a rotation.

[α] (conc./solvent)

25 D

Optical Purity

The rotation of enantiomers are equal but opposite. If the [α] of the R -

enantiomer of compound A is +100°, the [α] of the S -enantiomer is _____

The [α] of a equal mixture of the R - and S -enantiomers (racemic mixture)

is _____

The % excess amount of one enanatiomer over the other is called the enantiomeric excess (ee). e.g. , 100% R , 0% S : ee = ____ 50% R , 50% S : ee = ____ 70% R , 30% S : ee = ____

Problem : The [α] of the R -enantiomer of compound A is +100°. The [α] of a certain mixture of R - and S -enantiomers of compound A is -50°. What is the ee of this mixture? What is the % R -enantiomer in this mixture?

SYNTHESIS OF CHIRAL MOLECULES

Most syntheses are not enantiospecific: if a reaction forms a stereocenter, it will proceed to give a racemic mixture of two enantiomers. achiral achiral product racemic starting materials → or ← starting materials racemic mixture

Chiral catalysts (such as enzymes) can be used to induce chirality

Chiral starting materials can be transformed to:

Molecules with the same stereochemistry ( e.g. , R → R , “retention of stereochemistry”) Molecules with the opposite stereochemistry ( i.e. , R → S , “inversion”) Racemic mixture ( i.e. , R → [ R/S or (d,l ) or (±)] , “racemization”)

S:5.10; 5.

STEREOISOMERS WITH MORE THAN

ONE STEREOCENTER

Prob: 5.33,34, 35c-e,

S:5.12-

For Fischer projections of compounds with more than one stereocenter,

remember that each represents and consider each

stereocenter one at a time.

` ``

Problem: Complete the Fischer projection on the right to represent the molecule on the left. Consider the configuration of the two carbon atoms independent of one another. Provide a complete name for this compound (including stereochemistry!) Is this compound chiral?

CH 3

CH 3

C C CH (^3)

H 3 C H

BrH

Br

Diastereomers

Problem: Draw all the stereoisomers of CH 3 CH(OH)CH(OH)COOH:

If the sets of substituents on stereogenic centers are different there will be 2 n stereoisomers.

Stereoisomers which are not mirror images of each other are called diastereomers. Diastereomers have different properties from each other (e.g., solubility, mp, bp, polarity). They can be separated by recrystallization, distillation or chromatography.

CH 3

COOH

CH (^3)

COOH

CH 3

COOH

CH (^3)

COOH C C COOH

H 3 C H

HOH

OH

Meso Compounds

If the sets of substituents on stereogenic centers are identical there will be fewer than 2 n^ stereoisomers.

Compounds with stereogenic centers which are not chiral are called meso compounds.

Meso compounds possess a point or plane of symmetry (in at least one conformation)

L

CH 3

CH 3

CH (^3)

Br H

CH (^3) H Br

CH 3

CH 3

CH 3

CH 3 C C CH (^3)

H 3 C H

Br H

Br

SEPARATION OF ENANTIOMERS

Enantiomers have identical physical properties. Racemic mixtures of carboxylic acids can be treated with a pure enantiomer of an amine to form a pair of diastereomeric ammonium carboxylates which has different properties general reaction:

e.g. ,

R' N R O

O H (^) +

H

H R O R'^ N

O H

H

H

Ph O

H

Me H

O H O

Ph

O

H Me

Ph NH 2

Me

H

( S )- A ( R )- A

( R )- B

( R )- B ( R )- B

  • ( S )- A +^ ( R )- A salt salt

S:5.

The pair of diastereomeric ammonium carboxylates can usually be separated by recrystallization (with hard work and luck) and the two acids (and the amine) recovered.

e.g. ,

Ph O

H

Me H

O

H O

Ph

O

H Me

Ph (^) NH 2

Me

H

( S )- A

( R )- B

( R )- B ( R )- B ( S )- A + salt salt

( R )- B ( S )- A salt

( R )- B

salt

HCl (^) HCl

is recovered for reuse

separate by crystallization

( R )- A

( R )- A

( R )- A

RCOO-^ R'NH 3 +^ + HCl RCOOH + R'NH 3 +^ Cl-

acid-base chemistry to convert diastereomeric ammonuim carboxylate to carboxylic acid:

CYCLIC COMPOUNDS

e.g., trans- and cis-1,2-dimethylcyclobutane

e.g., trans-1,2-dimethylcyclohexane

Prob: 5.35h,j,o,p; 37-

CH (^3)

CH (^3)

H CH^3 3 C

CH 3

CH 3

S:5.

TOPIC 4 ON EXAM 2

Types of Questions

  • Recognize enantiomers, diastereomers, meso compounds
  • Provide R/S designations of stereocenters
  • Calculate optical rotations, enantiomeric excesses The problems in the book are good examples of the types of problems on the exam.

Preparing for Exam 2:

  • Work as many problems as possible.
  • Work in groups.
  • Do the “Learning Group Problem” at the end of the chapter.
  • You may bring models to the exam, but are limited to two chiral carbon atoms. YOU MAY USE A SMALL MODEL KIT AND A CALCULATOR DURING EXAM 2. You will NOT have access to these on the final.