For the bromination of acetanilide: 0.5 g of acetanilide, 2 mL of glacial acetic acid, 3.7 mL of 1.0 M
bromine in acetic acid was used to create bromoacetanilide Determine the limiting reagents (show all
work) and calculate the percent yield ?
Ans) To determine the limiting reagent, we need to compare the number of moles of acetanilide and
bromine in acetic acid.
First, let's calculate the number of moles of bromine in acetic acid:
We can see that the number of moles of bromine in acetic acid and acetanilide is the same, meaning
that neither reagent is in excess, and they are both limiting reagents.
To calculate the theoretical yield, we need to calculate the number of moles of bromoacetanilide that
can be formed. Since both reactants are limiting, the reaction will go to completion, and all of the
bromine in acetic acid and acetanilide will be used.
The balanced chemical equation for the reaction is:
Acetanilide + Br2 -> bromoacetanilide + HBr + HOAc
From the balanced equation, we can see that 1 mole of acetanilide reacts with 1 mole of Br2 to produce
1 mole of Bromo acetanilide.
So the theoretical yield of Bromo acetanilide is:
N(Bromo acetanilide) = n(acetanilide) = 0.0037 mol
