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CHAPTER 1
1.1 Write a program that will print your mailing address in the following form :
First line : Name Second line : Door No, Street Third line : City, Pin code
Algorithm: -
Algorithm to print your mailing address.
Step 1 : Display your Name and Go to new line. Step 2 : Display your Door No and Street and Go to new line. Step 3 : Display your City and Pin Code.
Flowchart:-
Program: -
// Write a program that will print your mailing //address in the following form: //First line : Name //Second line : Door No, Strret //Third line : City, Pin Code //Date : 11/03/201 3
START
Display your Name & Go to new line Display your Door No and Street & go to new line Display your City and Pin Code
END
#include<stdio.h> #include<conio.h>
void main() { clrscr(); printf("Name :-- HEMANT TRIVEDI\n"); printf("Door No :-- 103 , Street :-- Aradhna \n"); printf("City :-- Bhavnagar , Pin Code :-- 364001 "); getch(); }
Output:--
Name :-- HEMANT TRIVEDI | Door No:-- 103 Street:- Aradhna City:-- Bhavnagar, Pin Code:-- 364001
1.2 Modify the above program to provide border lines to the address.
Algorithm: -
Algorithm to provide border lines to address.
Step 1 : Display ------------------------------------------------- line and Go to new line. Step 2 : Display ------------------------------------------------- line and Go to new line. Step 3 : Display ||, your Name, || and Go to new line. Step 4 : Display ||, your Door No and Street, || and Go to new line. Step 5 : Display ||, your City, Pin Code, || and Go to new line. Step 6 : Display ------------------------------------------------- line and Go to new line. Step 7 : Display ------------------------------------------------- line.
Flowchart :-
START
Display ------------ & go to new line Display ------------ & go to new line
A
printf(" -----------------------------------------------\n"); printf(" -----------------------------------------------\n"); printf("|| Name :-- HEMANT TRIVEDI ||\n"); printf("|| Door No :-- 103 , Street :-- Aradhana ||\n"); printf("|| City :-- Bhavnagar , Pin Code :-- 364001 ||\n"); printf(" -----------------------------------------------\n"); printf(" -----------------------------------------------\n"); getch(); }
Output:-
|| Name :-- HEMANT TRIVEDI || || Door No:-- 103 , Street:- Aradhana || ||City:-- Bhavnagar, Pin Code:-- 364001 ||
1.3 Write a program using one print statement to print the pattern of asterisks as shown below :
Algorithm: -
Algorithm to print the pattern of pattern of asterisks.
Step 1: Display * and go to new line Step 2: Display * * and go to new line. Step 3: Display * * * and go to new line. Step 4: Display * * * * Flowchart:-
Program :-
START
Display * & Go to new line Display * * & go to new line Display * * * & go to new line Display * * * *
END
//Write a program using one print statement to //print the pattern of asterisks as shown below :
//* //* * //* * * //* * * *
#include<stdio.h> #include<conio.h> void main() { clrscr(); printf("* \n* * \n* * * \n* * * *"); getch(); }
Output: -
1.4 Write a program that will print the following figure using suitable charactes.
| | | | | | >>------------------- | |
Algorithm:--
Algorithm to print the figure using suitable characters.
Step 1: Display ---------- and spaces Step 2: Display ---------- and Go to new line Step 3: Display | | and spaces Step 4: Display | | and go to new line Step 5: Display | | Step 6: Display >>----------- Step 7: Display | | and go to new line Step 8: Display ---------- and spaces Step 9: Display ----------
printf("-------------"); printf(" ") printf("-------------"); getch(); }
Output :--
| | | | | | >>-------------------> | |
1.5 Given the radius of a circle, write a program to compute and display its area. Use a symbolic constant to define the π value and assume a suitable value for radius.
Algorithm:--
Algorithm to compute the area of circle.
Step 1: Store 3.14 to varable PIE. Step 2: Store 4 to variable Rad. Step 3: Compute the area of circle and assign it to variable Area. Area = PIE * Rad * Rad Step 4: Display the variable.
Flowchart:--
Program :--
//Given the radius of a circle, write a program to compute
START
PIE = 3.
Rad = 4
Area=PIERadRad
Display Area
END
//and display its area. Use a symbolic constant to define the //PIE value and assume a suitable value for radius.
#include<stdio.h> #include<conio.h>
#Define PIE 3.
void main() { clrscr();
float Rad,Area; Rad=4; Area=PIERadRad; printf("Area of a circle is--> %f",Area); getch(); }
Output:--
Area of a circle is 50.
1.6 Write a program to output the following multiplication table.
5 * 1 = 5 * 2 = 5 * 3 =
.. .. .. 5 * 10 =
Algorithm:--
Algorithm to print multiplication table.
Step 1: Display 5 * 1 = 5 and go to new line Step 2: Display 5 * 2 = 10 and go to new line Step 3: Display 5 * 3 = 15 and go to new line Step 4: Display 5 * 4 = 20 and go to new line Step 5: Display 5 * 5 = 25 and go to new line Step 6: Display 5 * 6 = 30 and go to new line Step 7: Display 5 * 7 = 35 and go to new line Step 8: Display 5 * 8 = 40 and go to new line Step 9: Display 5 * 9 = 45 and go to new line Step 10: Display 5 * 10 = 50 and go to new line
Flowchart:--
Output:--
1.7 Given two integers 20 and 10, write a program that uses a function add() to add these two numbers and sub() to find the difference of these two numbers and then display the sum and difference in the following form:
20 + 10 = 30 20 – 10 = 10
Algorithm:--
Step 1: Display First Number 20. Step 2: Display Second Number 10. Step 3: Call function add(20,10) to add these two numbers and store result in variable Sum. Step 4: Call function sub(20,10) to Subtract these two numbers and store result in variable Diff. Step 5: Display 20 + 10 = Step 6: Display Sum and go to new line. Step 7: Display 20 – 10 = Step 6: Display Diff.
Flowchart:--
Program:--
//Given two integers 20 and 10, write a program that //uses a function add() to add these two numbers and //sub() to find the difference of these two numbers //and then display the sum and difference in the following form:
//20 + 10 = 30 //20 - 10 = 10
#include<stdio.h> #include<conio.h>
void main() { clrscr();
int Sum,Diff; printf("First Number 20\n"); printf("Second Number 10\n");
Sum=20+10; Diff=20-10;
printf("20 + 10 = %d\n", Sum);
Display First Number 20 Display Second Number 10
Sum=20+ Diff=20-
Display 20 + 10 = and Sum & go to new line Display 20 - 10 = and Diff
START
END
Program:--
//Given the values of three variables a, b and c, //write a program to compute and display the values of x, where
//X= a / (b - c)
//Execute your program for the following values:
//(a) a=250, b==85,c= //(b) a=300, b=70, c=
//Comment on the output in each case.
#include<stdio.h> #include<conio.h>
void main() { clrscr();
int a,b,c; float x; a=250; b=85; c=25; x=a/(b-c);
printf("x = %f\n",x);
A
a= b= c=
x= a / (b – c)
Display X
START
T
a=300; b=70; c=70; x=a/(b-c);
printf("x = %f\n",x);
getch(); }
Output:--
x=4. Divide error
1.9 Relationship between Celsius and Fahrenheit is governed by the formula
F = (9C/5)+ Write a program to convert the temperature (a) from Celsius to Fahrenheit and (b) from Fahrenheit to Celsius.
Algorithm:--
Algorithm to convert from Celsius to Fahrenheit and from Fahrenheit to Celsius.
Step 1: Store 0 to F & C. Step 2: Store 200 to C. Step 3: Compute ((9c)/5)+32 and store the result in F. Step 4: Display F. Step 5: Store 300 to F. Step 6: Compute ((F-32)5)/9 and store the result in C. Step 7: Display C.
float F,C; clrscr();
C=200; F=(((9*C)/5)+32);
printf("Celsius = %f to Fahrenheit = %f\n",C,F);
F=300; C=((F-32)*5)/9;
printf("Fahrenheit = %f to Celsius = %f\n",F,C);
getch(); }
Output:--
Celsius =200.000000 to Fahrenheit = 392. Fahrenheit = 300.000000 to Celsius = 148.
1.10 Area of a triangle is given by the formula
A=sqrt(S(S-a)(S-b)(S-c)) Where a, b and c are sides of the triangle and 2S=a+b+c. Write a program to compute the area of the triangle given the values of a, b and c.
Algorithm:--
Algorithm to compute the area of a triangle.
Step 1: Store 0 to a, b ,c and S. Step 2: Store 20, 30 and 40 to a, b and c respectively. Step 3: Compute (a+b+c)/2 and store the result in S. Step 4: Compute sqrt(S(S-a)(S-b)*(S-c)) and store the result in Area. Step 5: Display Area.
Flowchart:--
Program:--
//Area of a triangle is given by the formula
//A=sqrt(S(S-a)(S-b)(S-c)) //Where a, b and c are sides of the triangle and 2S=a+b+c. //Write a program to compute the area of the triangle //given the values of a, b and c.
#include<stdio.h> #include<conio.h> #include<math.h>
void main() {
int a,b,c; float S,Area; a=b=c=S=0;
clrscr();
a=20;
START
a= b= c= S=
a= b= c=
S= (a+b+c)/c
Area=sqrt(S(S-a)(S-b)*(S-c))
END
//Distance between two points (x1,y1) and (x2,y2) is governed by the formula
//D2 = (x2-x1)2+(y2-y1)
//Write a program to compute D given the coordinates of the points.
#include<stdio.h> #include<conio.h> #include<math.h>
void main() {
int x1,x2,y1,y2; float D; D=0; x1=20; x2=30; y1=40; y2=50;
clrscr();
D=sqrt((x2-x1)(x2-x1)+ (y2-y1) (y2-y1));
printf("Distance between to points is= %f",D);
getch(); }
Output:--
Distance between twoo points is = 14.
1.12 A point on the circumference of a circle whose center is (0, 0) is (4, 5). Write a program to compute perimeter and area of the circle.
Algorithm:--
Algorithm to compute perimeter and area of the circle.
Step 1: Store the coordinate of origin O1 and O2 to 0, 0 respectively. Step 2: Store the coordinate of point x1 and y1 to 4, 5 respectively. Step 3: Compute sqrt((x1-O1)(x1-O1)+ (y1-O2) (y1-O2)) and store the result in Rad. Step 4: Compute 2PIERad and store the result in Circum. Step 5: Compute PIERadRad and store the result in Area. Step 6: Display Circum & Area.
Flowchart:--
Program:--
//A point on the circumference of a circle whose center is (0, 0) is (4, 5). Write //a program to compute perimeter and area of the circle.
#include<stdio.h> #include<conio.h> #include<math.h>
#define PIE 3.
void main() {
int O1,O2,x1,y2; float Rad,Circum,Area;
clrscr();
Rad=sqrt((x1-O1)(x1-O1)+ (y1-O2) (y1-O2))); Circum=2PIERad; Area=PIERadRad;
printf("Circumference is= %f \n Area is= %f",Circum,Area);
getch(); }
O1=
O2=
x1= x2=
Rad= sqrt((x1-O1)(x1-O1)+ (y1-O2) (y1-O2)) Circum=2PIERad Area= PIERadRad
Display Circum Display Area
START
START
