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Sample of Families - Statistical Science - Exam, Exams of Statistics

This is the Exam of Statistical Science which includes Stochastic Differential Equation, Brownian Motion, Solution, Measurable Function, Markov Process, Starting, Bounded Functions, Local Martingale, First Time etc. Key important points are: Sample of Families, Distributed, Components, Conditional, Heredity Study, Frets, Lengths, Sample of Families, Corresponding Quantities, Vector

Typology: Exams

2012/2013

Uploaded on 02/26/2013

dharmanand
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M. PHIL. IN STATISTICAL SCIENCE
Tuesday 7 June, 2005 1:30 to 3:30
APPLIED MULTIVARIATE ANALYSIS
Attempt THREE questions.
There are FOUR questions in total.
The questions carry equal weight.
STATIONERY REQUIREMENTS SPECIAL REQUIREMENTS
Cover sheet None
Treasury Tag
Script paper
You may not start to read the questions
printed on the subsequent pages until
instructed to do so by the Invigilator.
pf3
pf4

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M. PHIL. IN STATISTICAL SCIENCE

Tuesday 7 June, 2005 1:30 to 3:

APPLIED MULTIVARIATE ANALYSIS

Attempt THREE questions. There are FOUR questions in total.

The questions carry equal weight.

STATIONERY REQUIREMENTS SPECIAL REQUIREMENTS

Cover sheet None Treasury Tag Script paper

You may not start to read the questions

printed on the subsequent pages until

instructed to do so by the Invigilator.

1 Suppose the p-dimensional vector X is distributed as Np(μ, V ). Show that if we partition X into components X 1 , X 2 , so that XT^ = (XT 1 , X 2 T ), then the covariance matrix of X 1 conditional on X 2 = x 2 is V 11 − V 12 V 22 − 1 V 21 , where

V =

V 11 V 12

V 21 V 22

In a classic heredity study, Frets (1921) measured the head lengths and head breadths on the first and second adult sons in a sample of families. Let (X 1 , X 2 ) be the head length and breadth of the first son and (Y 1 , Y 2 ) the corresponding quantities for the second son.

Considering these four measurements as the 4-vector ZT^ = (XT^ , Y T^ ) = (X 1 , X 2 , Y 1 , Y 2 ), a reasonable model for the population from which the sample has come is a Normal population with mean vector

μ = (μ 1 , μ 2 , μ 1 , μ 2 )T

and dispersion matrix

V =

a b c c b a c c c c a b c c b a

for some positive a, b, c such that V is positive definite, a > c and b > c.

Obtain

(i) the joint distribution of X 1 − Y 1 and X 2 − Y 2 ;

(ii) the marginal distribution of X 1 − Y 1 ;

and

(iii) the conditional distribution of X 1 − Y 1 given that X 2 − Y 2 = 0.

Comment on the differences between (ii) and (iii)

APPLIED MULTIVARIATE ANALYSIS

3 Fisher’s classic “iris” data consists of a table 150 × 5, of which the first 3 rows are given in the Splus6 output below. There are 3 distinct species, denoted here by “setosa”, “versicolor” and “virginica”, and we wish to construct a classification tree to sort the 150 iris specimens into species according to the values of Sepal Length, Sepal Width, Petal Length and Petal Width. Explain carefully the construction of the Splus object “iris.tr” in the output below, and sketch the resulting classification tree.

iris[1:3,] Sepal.Length Sepal.Width Petal.Length Petal.Width Species 1 5.1 3.5 1.4 0.2 setosa 2 4.9 3.0 1.4 0.2 setosa 3 4.7 3.2 1.3 0.2 setosa iris.tr <- tree(Species~.,iris);summary(iris.tr)

Classification tree: tree(formula = Species ~ ., data = iris) Variables actually used in tree construction: [1] "Petal.Length" "Petal.Width" "Sepal.Length" Number of terminal nodes: 6 Residual mean deviance: 0.1253 = 18.05 / 144 Misclassification error rate: 0.02667 = 4 / 150

iris.tr node), split, n, deviance, yval, (yprob)

  • denotes terminal node
  1. root 150 329.600 setosa ( 0.3333 0.33330 0.33330 )
  2. Petal.Length<2.45 50 0.000 setosa ( 1.0000 0.00000 0.00000 ) *
  3. Petal.Length>2.45 100 138.600 versicolor ( 0.0000 0.50000 0.50000 )
  4. Petal.Width<1.75 54 33.320 versicolor ( 0.0000 0.90740 0.09259 )
  5. Petal.Length<4.95 48 9.721 versicolor ( 0.0000 0.97920 0.02083 )
  6. Sepal.Length<5.15 5 5.004 versicolor ( 0.0000 0.800000.20000 ) *
  7. Sepal.Length>5.15 43 0.000 versicolor ( 0.0000 1.000000.00000 ) *
  8. Petal.Length>4.95 6 7.638 virginica ( 0.0000 0.33330 0.66670 ) *
  9. Petal.Width>1.75 46 9.635 virginica ( 0.0000 0.02174 0.97830 )
  10. Petal.Length<4.95 6 5.407 virginica ( 0.0000 0.16670 0.83330 )*
  11. Petal.Length>4.95 40 0.000 virginica ( 0.0000 0.00000 1.00000 ) *

4 Write brief essays, which should include appropriate sketch graphs, on two of the following topics.

(i) Multivariate Analysis of Variance

(ii) Factor Analysis (iii) Clustering Algorithms.

END OF PAPER

APPLIED MULTIVARIATE ANALYSIS