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◊„àfl¬Íáʸ ÁŸŒ¸‡Ê —
- ©ûÊ⁄ ¬òÊ ß‚ ¬⁄ˡÊÊ ¬ÈÁSÃ∑§Ê ∑§ •ãŒ⁄ ⁄πÊ „Ò– ¡’ •Ê¬∑§Ê ¬⁄ˡÊÊ ¬ÈÁSÃ∑§Ê πÊ‹Ÿ ∑§Ê ∑§„Ê ¡Ê∞, ÃÊ ©ûÊ⁄ ¬òÊ ÁŸ∑§Ê‹ ∑§⁄U äÿÊŸ¬Ífl¸∑§ ¬Îc∆- 1 ∞fl¥ ¬Îc∆- 2 ¬⁄ ∑§fl‹ ŸË‹ / ∑§Ê‹ ’ÊÚ‹ ¬ÊÚߥ≈ ¬Ÿ ‚ Áflfl⁄áÊ ÷⁄¥–
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¬⁄ˡÊÊ ¬ÈÁSÃ∑§Ê ‚¥∑§Ã Test Booklet Code
No. :
¬˝‡ŸÊ¥ ∑§ •ŸÈflÊŒ ◊¥ Á∑§‚Ë •S¬c≈UÃÊ ∑§Ë ÁSÕÁà ◊¥, •¥ª˝¡Ë ‚¥S∑§⁄UáÊ ∑§Ê „Ë •¥ÁÃ◊ ◊ÊŸÊ ¡ÊÿªÊ–
In case of any ambiguity in translation of any question, English version shall be treated as final.
Hindi+English
E
E1 2 Hindi+English
- Which of the following is not an attribute of a population? (1) Sex ratio (2) Natality (3) Mortality (4) Species interaction
- The process of growth is maximum during : (1) Log phase (2) Lag phase (3) Senescence (4) Dormancy
- The roots that originate from the base of the stem are : (1) Fibrous roots (2) Primary roots (3) Prop roots (4) Lateral roots
- Match the following diseases with the causative organism and select the correct option. Column - I Column - II (a) Typhoid (i) Wuchereria (b) Pneumonia (ii) Plasmodium (c) Filariasis (iii) Salmonella (d) Malaria (iv) Haemophilus (a) (b) (c) (d) (1) (i) (iii) (ii) (iv) (2) (iii) (iv) (i) (ii) (3) (ii) (i) (iii) (iv) (4) (iv) (i) (ii) (iii)
- In which of the following techniques, the embryos are transferred to assist those females who cannot conceive? (1) ZIFT and IUT (2) GIFT and ZIFT (3) ICSI and ZIFT (4) GIFT and ICSI
- Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups. (1) The gene (I) has three alleles. (2) A person will have only two of the three alleles. (3) When IA^ and IB^ are present together, they express same type of sugar. (4) Allele ‘i’ does not produce any sugar.
- ÁŸêŸÁ‹Áπà ◊¥ ‚ ∑§ÊÒŸ ∞∑§ ¡Ëfl ‚¥ÅÿÊ ∑§Ê ∞∑§ ªÈáÊ Ÿ„Ë¥ „Ò?
(1) Á‹¥ª •ŸÈ¬Êà (2) ¡ã◊ Œ⁄U (3) ◊ÎàÿÈ Œ⁄U (4) ¡ÊÁà ¬⁄US¬⁄U Á∑˝§ÿÊ
- flÎÁh ∑§Ë ¬˝Á∑˝§ÿÊ •Áœ∑§Ã◊ Á∑§‚ ŒÊÒ⁄UÊŸ „ÊÃË „Ò?
(1) ‹ÊÚª ¬˝ÊflSÕÊ (2) ¬‡øÃÊ ¬˝ÊflSÕÊ (3) ¡ËáʸÃÊ (4) ¬˝‚ÈÁåÃ
- ß ∑§ •ÊœÊ⁄U ‚ ©à¬ÛÊ „ÊŸ flÊ‹Ë ¡«∏Ê¥ ∑§Ê ÄÿÊ ∑§„Ê ¡ÊÃÊ „Ò?
(1) ¤Ê∑§«∏Ê ¡«∏ (2) ¬˝ÊÕÁ◊∑§ ¡«∏ (3) •flSÃ¥÷ ¡«∏ (4) ¬Ê‡fl¸ ¡«∏
- ÁŸêŸ ⁄Uʪʥ ∑§Ê ©Ÿ∑§ ¬ÒŒÊ ∑§⁄UŸ flÊ‹ ¡ËflÊ¥ ∑§ ‚ÊÕ Á◊‹ÊŸ ∑§⁄U
‚„Ë Áfl∑§À¬ ∑§Ê øÿŸ ∑§⁄UÊ– SÃ¥÷ - I SÃ¥÷ - II (a) ≈UÊß»§ÊÚß«U (i) flÈø⁄UÁ⁄UÿÊ (b) ãÿÍ◊ÊÁŸÿÊ (ii) å‹Òí◊ÊÁ«Uÿ◊ (c) »§Êß‹Á⁄U∞Á‚‚ (iii) ‚ÊÀ◊ÊŸ‹Ê (d) ◊‹Á⁄UÿÊ (iv) „Ë◊ÊÁ»§‹‚ (a) (b) (c) (d) (1) (i) (iii) (ii) (iv) (2) (iii) (iv) (i) (ii) (3) (ii) (i) (iii) (iv) (4) (iv) (i) (ii) (iii)
- ÁŸêŸ ◊¥ Á∑§‚ Ã∑§ŸË∑§ ∑§Ë ‚„ÊÿÃÊ ‚ ∞‚Ë ÁSòÊÿÊ° ¡Ê ª÷¸œÊ⁄UáÊ
Ÿ„Ë¥ ∑§⁄U ‚∑§ÃË, ◊¥ ÷˝ÍáÊ ∑§Ê SÕÊŸÊ¥ÃÁ⁄Uà Á∑§ÿÊ ¡ÊÃÊ „Ò? (1) ZIFT ∞fl¥ IUT (2) GIFT ∞fl¥ ZIFT (3) ICSI ∞fl¥ ZIFT (4) GIFT ∞fl¥ ICSI
- ¡ËŸ ‘I’ ¡Ê ABO ⁄UÄà flª¸ ∑§Ê ÁŸÿ¥òÊáÊ ∑§⁄UÃÊ „Ò ©‚∑§ ‚¥Œ÷¸
◊¥ ª‹Ã ∑§ÕŸ ∑§Ê ¬„øÊÁŸ∞– (1) ¡ËŸ (I) ∑§ ÃËŸ ∞‹Ë‹ „Êà „Ò¥– (2) ∞∑§ √ÿÁÄà ◊¥ ÃËŸ ◊¥ ‚ ∑§fl‹ ŒÊ ∞‹Ë‹ „Ê¥ª– (3) ¡’ IA^ ∞fl¥ IB^ ŒÊŸÊ¥ ß∑§_ „Êà „Ò¥, ÿ ∞∑§ ¬˝∑§Ê⁄U ∑§Ë ‡Ê∑¸§⁄UÊ •Á÷√ÿÄà ∑§⁄Uà „Ò¥– (4) ‘i’ ∞‹Ë‹ ∑§Ê߸ ÷Ë ‡Ê∑¸§⁄UÊ ©à¬ÛÊ Ÿ„Ë¥ ∑§⁄UÃÊ–
E1 4 Hindi+English
- Identify the substances having glycosidic bond and peptide bond, respectively in their structure : (1) Chitin, cholesterol
(2) Glycerol, trypsin (3) Cellulose, lecithin (4) Inulin, insulin
- The plant parts which consist of two generations - one within the other :
(a) Pollen grains inside the anther
(b) Germinated pollen grain with two male gametes
(c) Seed inside the fruit
(d) Embryo sac inside the ovule
(1) (a) only (2) (a), (b) and (c) (3) (c) and (d) (4) (a) and (d)
- The product(s) of reaction catalyzed by nitrogenase in root nodules of leguminous plants is/are : (1) Ammonia alone (2) Nitrate alone (3) Ammonia and oxygen
(4) Ammonia and hydrogen
- Identify the correct statement with regard to G 1 phase (Gap 1) of interphase. (1) DNA synthesis or replication takes place. (2) Reorganisation of all cell components takes place.
(3) Cell is metabolically active, grows but does not replicate its DNA. (4) Nuclear Division takes place.
- Cuboidal epithelium with brush border of microvilli is found in :
(1) lining of intestine (2) ducts of salivary glands (3) proximal convoluted tubule of nephron (4) eustachian tube
- ©Ÿ ¬ŒÊÕÊZ ∑§Ê ¬„øÊÁŸ∞, Á¡Ÿ∑§Ë ‚¥⁄UøŸÊ•Ê¥ ◊¥ ∑˝§◊‡Ê—
Ç‹Êß∑§Ê‚ÊßÁ«U∑§ ’¥œ •ÊÒ⁄U ¬å≈UÊß«U ’¥œ ¬Êÿ ¡Êà „Ò¥ —
(1) ∑§ÊßÁ≈UŸ, ∑§Ê‹S≈U⁄UÊÚ‹
(2) ÁÇ‹‚⁄UÊÚ‹, Á≈˛UÁå‚Ÿ
(3) ‚‹È‹Ê¡, ‹Á‚ÁÕŸ
(4) ߟÈÁ‹Ÿ, ߥ‚ÈÁ‹Ÿ
- ¬ÊŒ¬ ∑§Ê fl„ ÷ʪ ∑§ÊÒŸ-‚Ê „Ò Á¡‚◊¥ ŒÊ ¬Ë…∏Ë - ∞∑§ ¬Ë…∏Ë
ŒÍ‚⁄U ∑§ •ãŒ⁄U „ÊÃË „Ò?
(a) ¬⁄Uʪ∑§Ê‡Ê ∑§ •ãŒ⁄U ¬⁄Uʪ∑§áÊ
(b) ŒÊ Ÿ⁄U ÿÈÇ◊∑§Ê¥ flÊ‹Ë •¥∑ȧÁ⁄Uà ¬⁄Uʪ∑§áÊ
(c) »§‹ ∑§ •ãŒ⁄U ’Ë¡
(d) ’Ë¡Êá«U ∑§ •ãŒ⁄U ÷Í˝áÊ-∑§Ê·
(1) ∑§fl‹ (a)
(2) (a), (b) •ÊÒ⁄U (c)
(3) (c) •ÊÒ⁄U (d)
(4) (a) •ÊÒ⁄U (d)
- »§‹ËŒÊ⁄U »§‹Ê¥ flÊ‹ ¬ÊŒ¬Ê¥ ∑§Ë ¡«∏ ª˝ÁãÕ∑§Ê•Ê¥ ◊¥ ŸÊß≈˛UÊÁ¡Ÿ¡
mÊ⁄UÊ ©à¬˝Á⁄Uà •Á÷Á∑˝§ÿÊ ∑§Ê/∑§ ©à¬ÊŒ ∑§ÊÒŸ ‚Ê/‚ „Ò/„Ò¥?
(1) ∑§fl‹ •◊ÊÁŸÿÊ
(2) ∑§fl‹ ŸÊß≈˛U≈U
(3) •◊ÊÁŸÿÊ •ÊÒ⁄U •ÊÚÄ‚Ë¡Ÿ
(4) •◊ÊÁŸÿÊ •ÊÒ⁄U „Êß«˛UÊ¡Ÿ
- •¥Ã⁄UÊflSÕÊ ∑§Ë G 1 ¬˝ÊflSÕÊ (ªÒ¬ 1 ) ∑§ ’Ê⁄U ◊¥ ‚„Ë ∑§ÕŸ ∑§Ê
øÿŸ ∑§⁄UÊ–
(1) «UË.∞Ÿ.∞. ‚¥‡‹·áÊ ÿÊ ¬˝ÁÃ∑ΧÁÃ∑§⁄UáÊ „ÊÃÊ „Ò–
(2) ‚÷Ë ∑§ÊÁ‡Ê∑§Ê •flÿflÊ¥ ∑§Ê ¬ÈŸª¸∆UŸ „ÊÃÊ „Ò–
(3) ∑§ÊÁ‡Ê∑§Ê ©¬Ê¬øÿË ‚Á∑˝§ÿ „ÊÃË „Ò, flÎÁh ∑§⁄UÃË „Ò ‹Á∑§Ÿ DNA ∑§Ë ¬˝ÁÃ∑ΧÁà Ÿ„Ë¥ ∑§⁄UÃË–
(4) ∑§ãŒ˝∑§ Áfl÷Ê¡Ÿ „ÊÃÊ „Ò–
- ‚͡◊Ê¥∑ȧ⁄UÊ¥ ∑§ ’˝È‡Ê ’Ê«¸U⁄U flÊ‹Ë ÉÊŸÊ∑§Ê⁄U ©¬∑§‹Ê ¬ÊÿË ¡ÊÃË „Ò —
(1) •Ê¥òÊ ∑§ •ÊSÃ⁄U ◊¥
(2) ‹Ê⁄U ª˝¥ÁÕ ∑§Ë flÊÁ„∑§Ê ◊¥
(3) flÎÄ∑§ÊáÊÈ ∑§Ë ‚◊ˬSÕ ‚¥flÁ‹Ã ŸÁ‹∑§Ê ◊¥
(4) ÿÍS≈U∑§ËÿŸ ŸÁ‹∑§Ê ◊¥
Hindi+English 5 E
- Which of the following statements about inclusion bodies is incorrect? (1) They are not bound by any membrane. (2) These are involved in ingestion of food particles. (3) They lie free in the cytoplasm. (4) These represent reserve material in cytoplasm.
- Which is the important site of formation of glycoproteins and glycolipids in eukaryotic cells? (1) Endoplasmic reticulum (2) Peroxisomes (3) Golgi bodies (4) Polysomes
- In gel electrophoresis, separated DNA fragments can be visualized with the help of : (1) Acetocarmine in bright blue light (2) Ethidium bromide in UV radiation (3) Acetocarmine in UV radiation (4) Ethidium bromide in infrared radiation
- Identify the wrong statement with reference to transport of oxygen. (1) Binding of oxygen with haemoglobin is mainly related to partial pressure of O 2. (2) Partial pressure of CO 2 can interfere with O 2 binding with haemoglobin. (3) Higher H+^ conc. in alveoli favours the formation of oxyhaemoglobin. (4) Low pCO 2 in alveoli favours the formation of oxyhaemoglobin.
- Ray florets have : (1) Inferior ovary (2) Superior ovary (3) Hypogynous ovary (4) Half inferior ovary
- The specific palindromic sequence which is recognized by EcoRI is : (1) 5' - GAATTC - 3' 3' - CTTAAG - 5' (2) 5' - GGAACC - 3' 3' - CCTTGG - 5' (3) 5' - CTTAAG - 3' 3' - GAATTC - 5' (4) 5' - GGATCC - 3' 3' - CCTAGG - 5'
- •¥ÃÁfl¸c≈U ∑§ÊÿÊ¥ ∑§ Áfl·ÿ ◊¥ ÁŸêŸÁ‹Áπà ◊¥ ‚ ∑§ÊÒŸ ‚Ê ∑§ÕŸ
ª‹Ã „Ò? (1) ÿ Á∑§‚Ë Á¤ÊÀ‹Ë ‚ ÁÉÊ⁄U Ÿ„Ë¥ „ÊÖ (2) ÿ πÊl ∑§áÊÊ¥ ∑§ •¥Ãª˝¸„áÊ ◊¥ ‡ÊÊÁ◊‹ „Êà „Ò¥– (3) ÿ ∑§ÊÁ‡Ê∑§ÊŒ˝√ÿ ◊¥ SflÃ¥òÊ M§¬ ◊¥ „Êà „Ò¥– (4) ÿ ∑§ÊÁ‡Ê∑§ÊŒ˝√ÿ ◊¥ ÁŸÁøà ¬ŒÊÕ¸ ∑§Ê √ÿÄà ∑§⁄Uà „Ò¥–
- ‚È∑§ãŒ˝∑§Ë ∑§ÊÁ‡Ê∑§Ê•Ê¥ ◊¥ Ç‹Êß∑§Ê¬˝Ê≈UËŸ •ÊÒ⁄U Ç‹Êß∑§ÊÁ‹Á¬«U ∑§
ÁŸ◊ʸáÊ ∑§Ê ◊ÈÅÿ SÕ‹ ∑§ÊÒŸ ‚Ê „Ò? (1) •¥ÃŒ˝¸√ÿË ¡ÊÁ‹∑§Ê (2) ¬⁄UÊÄ‚Ë‚Ê◊ (3) ªÊÀ¡Ë ∑§Êÿ (4) ¬Ê‹Ë‚Ê◊
- ¡‹ ß‹Ä≈˛UÊ»§Ê⁄UÁ‚‚ ◊¥, ¬ÎÕ∑§ „È∞ «UË.∞Ÿ.∞. ∑§ πá«UÊ¥ ∑§Ê
Á∑§‚∑§Ë ‚„ÊÿÃÊ ‚ ŒπÊ ¡Ê ‚∑§ÃÊ „Ò? (1) ø◊∑§Ë‹ ŸË‹ ¬˝∑§Ê‡Ê ◊¥ ∞‚Ë≈UÊ∑§ÊÁ◊¸Ÿ ‚ (2) UV ÁflÁ∑§⁄UáÊ ◊¥ ∞ÁÕÁ«Uÿ◊ ’˝Ê◊Êß«U ‚ (3) UV ÁflÁ∑§⁄UáÊ ◊¥ ∞‚Ë≈UÊ∑§ÊÁ◊¸Ÿ ‚ (4) •fl⁄UÄà ÁflÁ∑§⁄UáÊ ◊¥ ∞ÁÕÁ«Uÿ◊ ’˝Ê◊Êß«U ‚
- •ÊÚÄ‚Ë¡Ÿ ∑§ ¬Á⁄Ufl„Ÿ ∑§ ‚¥Œ÷¸ ◊¥ ª‹Ã ∑§ÕŸ ∑§Ê ¬„øÊŸÊ–
(1) •ÊÚÄ‚Ë¡Ÿ ∑§Ë „Ë◊ÊÇ‹ÊÁ’Ÿ ‚ ’¥œÃÊ ◊ÈÅÿ× O 2 ∑§ •Ê¥Á‡Ê∑§ ŒÊ’ ‚ ‚¥’¥ÁœÃ „Ò– (2) CO 2 ∑§Ê •Ê¥Á‡Ê∑§ ŒÊ’ „Ë◊ÊÇ‹ÊÁ’Ÿ ‚ ’¥œŸ flÊ‹Ë O 2 ◊¥ ’ÊœÊ «UÊ‹ ‚∑§ÃÊ „Ò– (3) flÊÿÈ ∑ͧÁ¬∑§Ê ◊¥ H+^ ∑§Ë ©ìÊ ‚Ê¥Œ˝ÃÊ •ÊÚÄ‚Ë„Ë◊ÊÇ‹ÊÁ’Ÿ ’ŸŸ ◊¥ ‚„Êÿ∑§ „ÊÃË „Ò– (4) flÊÿÈ ∑ͧÁ¬∑§Ê ◊¥ ∑§◊ pCO 2 •ÊÚÄ‚Ë„Ë◊ÊÇ‹ÊÁ’Ÿ ’ŸŸ ◊¥ ‚„Êÿ∑§ „ÊÃË „Ò–
- •⁄U-¬Èc¬∑§ ◊¥ ÄÿÊ „ÊÃÊ „Ò?
(1) •œÊflÃ˸ •¥«UʇÊÿ (2) ™§äfl¸flÃ˸ •¥«UʇÊÿ (3) ¡ÊÿÊ¥ªÊœ⁄U •¥«UʇÊÿ (4) •h¸ •œÊflÃ˸ •¥«UʇÊÿ
- ߸∑§Ê •Ê⁄U I mÊ⁄UÊ ¬„øÊŸ ¡ÊŸ flÊ‹Ê ¬ÒÁ‹ã«˛UÊÁ◊∑§ ∑˝§◊ „Ò —
(1) 5' - GAATTC - 3' 3' - CTTAAG - 5' (2) 5' - GGAACC - 3' 3' - CCTTGG - 5' (3) 5' - CTTAAG - 3' 3' - GAATTC - 5' (4) 5' - GGATCC - 3' 3' - CCTAGG - 5'
Hindi+English 7 E
- Which of the following statements are true for the phylum-Chordata? (a) In Urochordata notochord extends from head to tail and it is present throughout their life. (b) In Vertebrata notochord is present during the embryonic period only. (c) Central nervous system is dorsal and hollow. (d) Chordata is divided into 3 subphyla : Hemichordata, Tunicata and Cephalochordata. (1) (d) and (c) (2) (c) and (a) (3) (a) and (b) (4) (b) and (c)
- Match the organism with its use in biotechnology. (a) Bacillus (i) Cloning vector thuringiensis (b) Thermus (ii) Construction of aquaticus first rDNA molecule (c) Agrobacterium (iii) DNA polymerase tumefaciens (d) Salmonella (iv) Cry proteins typhimurium Select the correct option from the following : (a) (b) (c) (d) (1) (ii) (iv) (iii) (i) (2) (iv) (iii) (i) (ii) (3) (iii) (ii) (iv) (i) (4) (iii) (iv) (i) (ii)
- Match the following concerning essential elements and their functions in plants : (a) Iron (i) Photolysis of water (b) Zinc (ii) Pollen germination (c) Boron (iii) Required for chlorophyll biosynthesis (d) Manganese (iv) IAA biosynthesis Select the correct option : (a) (b) (c) (d) (1) (ii) (i) (iv) (iii) (2) (iv) (iii) (ii) (i) (3) (iii) (iv) (ii) (i) (4) (iv) (i) (ii) (iii)
- ‚¥ÉÊ ∑§ÊÚ«¸U≈UÊ ∑§ Á‹∞ ∑§ÊÒŸ ‚ ∑§ÕŸ ‚„Ë „¥Ò?
(a) ÿÍ⁄UÊ∑§ÊÚ«¸U≈UÊ ◊¥ ¬Îc∆U⁄UîÊÈ Á‚⁄U ‚ ¬Í¥¿U Ã∑§ »Ò§‹Ë „ÊÃË „Ò •ÊÒ⁄U ÿ„ ¡ËflŸ ∑§ •¥Ã Ã∑§ ’ŸË ⁄U„ÃË „Ò–
(b) fl≈U˸’˝≈UÊ ◊¥ ¬Îc∆U⁄UîÊÈ ∑§fl‹ ÷˝ÍáÊËÿ ∑§Ê‹ ◊¥ ©¬ÁSÕà „ÊÃË „Ò–
(c) ∑§ãŒ˝Ëÿ Ã¥ÁòÊ∑§Ê Ã¥òÊ ¬Îc∆UËÿ ∞fl¥ πÊπ‹Ê „ÊÃÊ „Ò– (d) ∑§ÊÚ«¸U≈UÊ ∑§Ê ÃËŸ ©¬‚¥ÉÊÊ¥ ◊¥ Áfl÷ÊÁ¡Ã Á∑§ÿÊ „Ò — „◊Ë∑§ÊÚ«¸U≈UÊ, ≈˜UÿÍÁŸ∑§≈UÊ ∞fl¥ ‚»Ò§‹Ê∑§ÊÚ«¸U≈UÊ– (1) (d) ∞fl¥ (c) (2) (c) ∞fl¥ (a) (3) (a) ∞fl¥ (b)
(4) (b) ∞fl¥ (c)
- ¡Ëfl ∑§Ê ©Ÿ∑§ ¡Òfl¬˝ÊÒlÊÁª∑§Ë ◊¥ ©¬ÿʪ ∑§ Á‹∞ ‚È◊Á‹Ã
∑§ËÁ¡∞– (a) ’ÒÁ‚‹‚ ÕÈÁ⁄¥UÁ¡ÁŸÁ‚‚ (i) Ä‹ÊÁŸ∑§ flÄ≈U⁄U (b) Õ◊¸‚ ∞ÄflÁ≈U∑§‚ (ii) ¬˝Õ◊ rDNA •áÊÈ ∑§Ê ÁŸ◊ʸáÊ (c) ∞ª˝Ê’ÒÄ≈UËÁ⁄Uÿ◊ (iii) «Ë.∞Ÿ.∞. ¬ÊÚÁ‹◊⁄U¡ ≈˜UÿÈÁ◊»§Á‚∞¥‚ (d) ‚ÊÀ◊ÊŸ‹Ê (iv) Cry ¬˝Ê≈UËŸ ≈Êß»§ËêÿÈÁ⁄Uÿ◊ ÁŸêŸÁ‹Áπà ◊¥ ‚ ‚„Ë Áfl∑§À¬ øÈÁŸ∞ — (a) (b) (c) (d) (1) (ii) (iv) (iii) (i) (2) (iv) (iii) (i) (ii) (3) (iii) (ii) (iv) (i) (4) (iii) (iv) (i) (ii)
- •ÁŸflÊÿ¸ ÃàflÊ¥ •ÊÒ⁄U ¬ÊŒ¬Ê¥ ◊¥ ©Ÿ∑§ ∑§ÊÿÊZ ∑§ Áfl·ÿ ◊¥ ÁŸêŸÁ‹ÁπÃ
∑§Ê ‚È◊Á‹Ã ∑§ËÁ¡∞ — (a) ‹Ê„ (i) ¡‹ ∑§Ê ¬˝∑§Ê‡Ê •¬ÉÊ≈UŸ
(b) Á¡¥∑§ (ii) ¬⁄Uʪ ∑§Ê •¥∑ȧ⁄UáÊ (c) ’Ê⁄UÊÚŸ (iii) Ä‹Ê⁄UÊÁ»§‹ ∑§ ¡Òfl ‚¥‡‹·áÊ ∑§ Á‹∞ •Êfl‡ÿ∑§ (d) ◊Ò¥ªŸË¡ (iv) •Ê߸.∞.∞. ¡Òfl ‚¥‡‹·áÊ ‚„Ë Áfl∑§À¬ øÈÁŸ∞ — (a) (b) (c) (d) (1) (ii) (i) (iv) (iii) (2) (iv) (iii) (ii) (i) (3) (iii) (iv) (ii) (i) (4) (iv) (i) (ii) (iii)
E1 8 Hindi+English
- Identify the incorrect statement. (1) Heart wood does not conduct water but gives mechanical support. (2) Sapwood is involved in conduction of water and minerals from root to leaf. (3) Sapwood is the innermost secondary xylem and is lighter in colour. (4) Due to deposition of tannins, resins, oils etc., heart wood is dark in colour.
- Match the following :
(a) Inhibitor of catalytic (i) Ricin activity (b) Possess peptide bonds (ii) Malonate (c) Cell wall material in (iii) Chitin fungi (d) Secondary metabolite (iv) Collagen Choose the correct option from the following : (a) (b) (c) (d) (1) (ii) (iv) (iii) (i) (2) (iii) (i) (iv) (ii) (3) (iii) (iv) (i) (ii) (4) (ii) (iii) (i) (iv)
- Meiotic division of the secondary oocyte is completed : (1) Prior to ovulation (2) At the time of copulation (3) After zygote formation (4) At the time of fusion of a sperm with an ovum
- According to Robert May, the global species diversity is about : (1) 1.5 million (2) 20 million (3) 50 million (4) 7 million
- The first phase of translation is : (1) Binding of mRNA to ribosome (2) Recognition of DNA molecule (3) Aminoacylation of tRNA (4) Recognition of an anti-codon
- ª‹Ã ∑§ÕŸ ∑§Ê øÈÁŸ∞–
(1) •¥Ã—∑§Êc∆U ¡‹ ∑§Ê øÊ‹Ÿ Ÿ„Ë¥ ∑§⁄UÃË, ¬⁄UãÃÈ ÿÊ¥ÁòÊ∑§ ‚„ÊÿÃÊ ¬˝ŒÊŸ ∑§⁄UÃË „Ò– (2) ⁄U‚ŒÊM§ ¡«∏ ‚ ¬ûÊË Ã∑§ ¡‹ ∑§ øÊ‹Ÿ ◊¥ •ÊÒ⁄U πÁŸ¡Ê¥ ∑§ øÊ‹Ÿ ◊¥ ‡ÊÊÁ◊‹ „ÊÃË „Ò– (3) ⁄U‚ŒÊM§ ‚’‚ ÷ËÃ⁄UË ÁmÃËÿ∑§ ŒÊM§ „ÊÃÊ „Ò •ÊÒ⁄U ÿ„ •¬ˇÊÊ∑Χà „À∑§ ⁄¥Uª ∑§Ë „ÊÃË „Ò– (4) ≈ÒUÁŸŸ, ⁄UÁ¡Ÿ, ÃÒ‹ •ÊÁŒ ∑§ ¡◊Ê „ÊŸ ∑§ ∑§Ê⁄UáÊ •¥Ã—∑§Êc∆U ª„⁄U ⁄¥Uª ∑§Ë „ÊÃË „Ò–
- ÁŸêŸÁ‹Áπà ∑§Ê ‚È◊Á‹Ã ∑§ËÁ¡∞ —
(a) ©à¬˝⁄U∑§ Á∑˝§ÿÊ ∑§Ê ÁŸ⁄UÊœ∑§ (i) Á⁄UÁ‚Ÿ (b) ¬å≈UÊß«U ’¥œ œÊ⁄U∑§ (ii) ◊Ò‹ÊŸ≈U (c) ∑§fl∑§Ê¥ ◊¥ ∑§ÊÁ‡Ê∑§Ê Á÷ÁûÊ (iii) ∑§ÊßÁ≈UŸ ¬ŒÊÕ¸
(d) ÁmÃËÿ∑§ ©¬Ê¬øÿ¡ (iv) ∑§Ê‹Ò¡Ÿ ÁŸêŸÁ‹Áπà ◊¥ ‚ ‚„Ë Áfl∑§À¬ øÈÁŸ∞ — (a) (b) (c) (d) (1) (ii) (iv) (iii) (i) (2) (iii) (i) (iv) (ii) (3) (iii) (iv) (i) (ii) (4) (ii) (iii) (i) (iv)
- ÁmÃËÿ∑§ •¥«U∑§ ∑§Ê •œ¸‚ÍòÊË Áfl÷Ê¡Ÿ ¬Íáʸ „ÊÃÊ „Ò —
(1) •¥«UÊà‚ª¸ ‚ ¬„‹ (2) ‚¥÷ʪ ∑§ ‚◊ÿ (3) ÿÈÇ◊Ÿ¡ ’ŸŸ ∑§ ’ÊŒ
(4) ‡ÊÈ∑˝§ÊáÊÈ ∞fl¥ •¥«UÊáÊÈ ∑§ ‚¥‹ÿŸ ∑§ ‚◊ÿ
- ⁄UÊ’≈¸U ◊ ∑§ •ŸÈ‚Ê⁄U, Áfl‡fl ◊¥ ¡ÊÁà ÁflÁflœÃÊ ‹ª÷ª Á∑§ÃŸË
„Ò? (1) 1.5 Á◊Á‹ÿŸ (2) 20 Á◊Á‹ÿŸ (3) 50 Á◊Á‹ÿŸ (4) 7 Á◊Á‹ÿŸ
- ≈˛UÊ¥‚‹‡ÊŸ (•ŸÈflÊŒŸ/SÕÊŸÊ¥Ã⁄UáÊ) ∑§Ë ¬˝Õ◊ •flSÕÊ ∑§ÊÒŸ ‚Ë
„ÊÃË „Ò?
(1) ⁄UÊß’Ê‚Ê◊ ‚ mRNA ∑§Ê ’㜟 (2) «UË.∞Ÿ.∞. •áÊÈ ∑§Ë ¬„øÊŸ (3) tRNA ∑§Ê ∞◊ËŸÊ∞‚Ë‹‡ÊŸ (4) ∞∑§ ∞¥≈UË-∑§Ê«UÊÚŸ ∑§Ë ¬„øÊŸ
E1 10 Hindi+English
- From his experiments, S.L. Miller produced amino acids by mixing the following in a closed flask : (1) CH 4 , H 2 , NH 3 and water vapor at 800 8 C (2) CH 3 , H 2 , NH 4 and water vapor at 800 8 C (3) CH 4 , H 2 , NH 3 and water vapor at 600 8 C (4) CH 3 , H 2 , NH 3 and water vapor at 600 8 C
- Embryological support for evolution was disapproved by : (1) Karl Ernst von Baer (2) Alfred Wallace (3) Charles Darwin (4) Oparin
- The process responsible for facilitating loss of water in liquid form from the tip of grass blades at night and in early morning is : (1) Transpiration (2) Root pressure (3) Imbibition (4) Plasmolysis
- Secondary metabolites such as nicotine, strychnine and caffeine are produced by plants for their : (1) Nutritive value (2) Growth response (3) Defence action (4) Effect on reproduction
- The oxygenation activity of RuBisCo enzyme in photorespiration leads to the formation of : (1) 2 molecules of 3-C compound (2) 1 molecule of 3-C compound (3) 1 molecule of 6-C compound (4) 1 molecule of 4-C compound and 1 molecule of 2-C compound
- Bt cotton variety that was developed by the introduction of toxin gene of Bacillus thuringiensis (Bt) is resistant to : (1) Insect pests (2) Fungal diseases (3) Plant nematodes (4) Insect predators
- ∞‚.∞‹. Á◊‹⁄U Ÿ •¬Ÿ ¬˝ÿʪ ◊¥ ∞∑§ ’¥Œ ç‹ÊS∑§ ◊¥ Á∑§‚∑§Ê
Á◊üÊáÊ ∑§⁄U ∞Á◊ŸÊ •ê‹ ©à¬ÛÊ Á∑§ÿ? (1) 8008 C ¬⁄U CH 4 , H 2 , NH 3 •ÊÒ⁄U ¡‹ flÊc¬ (2) 8008 C ¬⁄U CH 3 , H 2 , NH 4 •ÊÒ⁄U ¡‹ flÊc¬ (3) 6008 C ¬⁄U CH 4 , H 2 , NH 3 •ÊÒ⁄U ¡‹ flÊc¬ (4) 6008 C ¬⁄U CH 3 , H 2 , NH 3 •ÊÒ⁄U ¡‹ flÊc¬
- ∑˝§◊ʪà ©ÛÊÁà ∑§ Á‹∞ ÷Í˝áÊËÿ ¬˝◊ÊáÊ ∑§Ê Á∑§‚Ÿ •SflË∑§Ê⁄U
Á∑§ÿÊ ÕÊ? (1) ∑§Ê‹¸ •Ÿ¸S≈U flÊÚŸ ’ÿ⁄U (2) •À»˝§«U flÊ‹‚ (3) øÊÀ‚¸ «UÊÁfl¸Ÿ (4) •Ê¬Á⁄UŸ
- ⁄UÊÁòÊ ◊¥ ÿÊ ¬Íáʸ ¬˝Ê×∑§Ê‹ ◊¥ ÉÊÊ‚ ∑§Ë ¬ÁûÊÿÊ¥ ∑§ ‡ÊË·¸ ‚ ¡‹ ∑§
Œ˝fl •flSÕÊ ◊¥ ÁŸ∑§‹Ÿ ∑§Ê ‚Ȫ◊ ’ŸÊŸ ◊¥ ∑§ÊÒŸ ‚Ë ¬˝Á∑˝§ÿÊ ©ûÊ⁄UŒÊÿË „ÊÃË „Ò? (1) flÊc¬Êà‚¡¸Ÿ (2) ◊Í‹Ëÿ ŒÊ’ (3) •¥Ã—‡ÊÊ·áÊ (4) ¡ËflŒ˝√ÿ∑È¥§øŸ
- ÁmÃËÿ∑§ ©¬Ê¬øÿ¡, ¡Ò‚ Á∑§ ÁŸ∑§Ê≈UËŸ, ÁS≈˛UÄŸËŸ •ÊÒ⁄U ∑Ò§»§ËŸ
∑§Ê ¬ÊҜʥ ∑§ mÊ⁄UÊ •¬Ÿ Á‹∞ ÄÿÊ¥ ©à¬ÊÁŒÃ Á∑§ÿÊ ¡ÊÃÊ „Ò? (1) ¬Ê·áÊ ◊¥ ©¬ÿʪ (2) flÎÁh ¬⁄U ¬˝÷Êfl (3) ⁄UˇÊÊ ¬⁄U •‚⁄U (4) ¬˝¡ŸŸ ¬⁄U ¬˝÷Êfl
- ¬˝∑§Ê‡Ê‡fl‚Ÿ ◊¥ RuBisCo ∞¥¡Êß◊ ∑§Ë •ÊÚÄ‚Ë¡ŸË∑§⁄UáÊ Á∑˝§ÿÊ
‚ Á∑§‚∑§Ê ÁŸ◊ʸáÊ „ÊÃÊ „Ò? (1) 3-C ÿÊÒÁª∑§ ∑§ 2 •áÊÈ (2) 3-C ÿÊÒÁª∑§ ∑§Ê 1 •áÊÈ (3) 6-C ÿÊÒÁª∑§ ∑§Ê 1 •áÊÈ (4) 4-C ÿÊÒÁª∑§ ∑§Ê 1 •áÊÈ •ÊÒ⁄U 2-C ÿÊÒÁª∑§ ∑§Ê 1 •áÊÈ
- Bt ∑§¬Ê‚ ∑§Ë Á∑§S◊ ¡Ê ’ÒÁ‚‹‚ ÕÈÁ⁄¥UÁ¡ÁŸÁ‚‚ ∑§ Áfl· ¡ËŸ
∑§Ê ‚◊ÊÁflc≈U ∑§⁄U∑§ ’ŸÊ߸ ªÿË „Ò, ¬˝ÁÃ⁄UÊœË „Ò — (1) ∑§Ë≈U ¬Ë«∏∑§Ê¥ ‚ (2) ∑§fl∑§Ëÿ ⁄Uʪʥ ‚ (3) ¬ÊŒ¬ ‚ÍòÊ∑ΧÁ◊ ‚ (4) ∑§Ë≈U ¬⁄U÷ˇÊË ‚
Hindi+English 11 E
- Which of the following refer to correct example(s) of organisms which have evolved due to changes in environment brought about by anthropogenic action?
(a) Darwin’s Finches of Galapagos islands.
(b) Herbicide resistant weeds.
(c) Drug resistant eukaryotes.
(d) Man-created breeds of domesticated animals like dogs.
(1) only (a) (2) (a) and (c) (3) (b), (c) and (d) (4) only (d)
- Identify the wrong statement with reference to immunity. (1) When exposed to antigen (living or dead) antibodies are produced in the host’s body. It is called “Active immunity”. (2) When ready-made antibodies are directly given, it is called “Passive immunity”. (3) Active immunity is quick and gives full response. (4) Foetus receives some antibodies from mother, it is an example for passive immunity.
- By which method was a new breed ‘Hisardale’ of sheep formed by using Bikaneri ewes and Marino rams? (1) Out crossing (2) Mutational breeding (3) Cross breeding (4) Inbreeding
- Identify the correct statement with reference to human digestive system. (1) Ileum opens into small intestine. (2) Serosa is the innermost layer of the alimentary canal. (3) Ileum is a highly coiled part. (4) Vermiform appendix arises from duodenum.
- ÁŸêŸ ◊¥ ∑§ÊÒŸ, ∞‚ ¡ËflÊ¥ ∑§ ‚„Ë ©ŒÊ„⁄UáÊÊ¥ ∑§Ê ‚¥ŒÁ÷¸Ã ∑§⁄UÃÊ „Ò
¡Ê ◊ÊŸfl ∑§Ë Á∑˝§ÿÊ•Ê¥ mÊ⁄UÊ flÊÃÊfl⁄UáÊ ◊¥ ’Œ‹Êfl ∑§ ∑§Ê⁄UáÊ Áfl∑§Á‚à „È∞ „Ò?
(a) ªÒ‹Ê¬ÒªÊ mˬ ◊¥ «UÊÁfl¸Ÿ ∑§Ë Á»¥§ø¥
(b) π⁄U¬ÃflÊ⁄UÊ¥ ◊¥ ‡ÊÊ∑§ŸÊ‡ÊË ∑§Ê ¬˝ÁÃ⁄UÊœ
(c) ‚‚Ë◊∑§ãŒ˝∑§Ê¥ ◊¥ ŒflÊßÿÊ¥ ∑§Ê ¬˝ÁÃ⁄UÊœ
(d) ◊ŸÈcÿ mÊ⁄UÊ ’ŸÊÿË ¬Ê‹ÃÍ ¬‡ÊÈ ¡Ò‚ ∑ȧûÊÊ¥ ∑§Ë ŸS‹¥
(1) ∑§fl‹ (a)
(2) (a) ∞fl¥ (c)
(3) (b), (c) ∞fl¥ (d)
(4) ∑§fl‹ (d)
- ¬˝ÁÃ⁄UˇÊÊ ∑§ ‚¥Œ÷¸ ◊¥ ª‹Ã ∑§ÕŸ ∑§Ê ¬„øÊÁŸ∞–
(1) ¡’ ¬⁄U¬Ê·Ë ∑§Ê ‡Ê⁄UË⁄U (¡ËÁflà •ÕflÊ ◊ÎÃ) ¬˝Á០∑§ ‚¥¬∑¸§ ◊¥ •ÊÃÊ „Ò •ÊÒ⁄U ©‚∑§ ‡Ê⁄UË⁄U ◊¥ ¬˝ÁÃ⁄UˇÊË ©à¬ÛÊ „Êà „Ò¥– ß‚ ““‚Á∑˝§ÿ ¬˝ÁÃ⁄UˇÊÊ”” ∑§„à „Ò¥–
(2) ¡’ ’Ÿ ’ŸÊ∞ ¬˝ÁÃ⁄UˇÊË ¬˝àÿˇÊ M§¬ ‚ ÁŒ∞ ¡Êà „Ò¥, ß‚ ““ÁŸÁc∑˝§ÿ ¬˝ÁÃ⁄UˇÊÊ”” ∑§„à „Ò¥–
(3) ‚Á∑˝§ÿ ¬˝ÁÃ⁄UˇÊÊ ¡ÀŒË „ÊÃË „Ò •ÊÒ⁄U ¬Íáʸ ¬˝ÁÃÁ∑˝§ÿÊ ŒÃË „Ò–
(4) ÷˝ÍáÊ ◊ÊÃÊ ‚ ∑ȧ¿U ¬˝ÁÃ⁄UˇÊË ¬˝Êåà ∑§⁄UÃÊ „Ò, ÿ„ ÁŸÁc∑˝§ÿ ¬˝ÁÃ⁄UˇÊÊ ∑§Ê ©ŒÊ„⁄UáÊ „Ò–
- Á∑§‚ ÁflÁœ mÊ⁄UÊ ’Ë∑§ÊŸ⁄UË ∞flË¡ ∞fl¥ ◊Ò⁄UËŸÊ ⁄Uê‚ ‚ ÷«∏ ∑§Ë
Ÿß¸ ŸS‹ “Á„‚Ê⁄U«U‹” ÃÒÿÊ⁄U ∑§Ë ªÿË „Ò?
(1) ’Á„—¬˝¡ŸŸ
(2) ©à¬Á⁄UfløŸ ¬˝¡ŸŸ
(3) ‚¥∑§⁄UáÊ
(4) •¥Ã—¬˝¡ŸŸ
- ◊ÊŸfl ¬ÊøŸ Ã¥òÊ ‚ ‚¥ŒÁ÷¸Ã ‚„Ë ∑§ÕŸ ∑§Ê øÿŸ ∑§⁄UÊ–
(1) ˇÊÈŒ˝Ê¥òÊ ¿UÊ≈UË •Ê¥Ã ◊¥ πÈ‹ÃÊ „Ò–
(2) Á‚⁄UÊ‚Ê •Ê„Ê⁄U ŸÊ‹ ∑§Ê ‚’‚ •ãŒ⁄U flÊ‹Ë ¬⁄Uà „ÊÃË „Ò–
(3) ˇÊÈŒ˝Ê¥òÊ •àÿÊÁœ∑§ ∑È¥§«UÁ‹Ã ÷ʪ „ÊÃÊ „Ò–
(4) ∑ΧÁ◊M§¬ ¬Á⁄U‡ÊÁ·∑§Ê ª˝„áÊË ‚ ©à¬ÛÊ „ÊÃÊ „Ò–
Hindi+English 13 E
- Match the following with respect to meiosis : (a) Zygotene (i) Terminalization
(b) Pachytene (ii) Chiasmata
(c) Diplotene (iii) Crossing over
(d) Diakinesis (iv) Synapsis Select the correct option from the following : (a) (b) (c) (d) (1) (iii) (iv) (i) (ii) (2) (iv) (iii) (ii) (i) (3) (i) (ii) (iv) (iii) (4) (ii) (iv) (iii) (i)
- Which of the following pairs is of unicellular algae? (1) Laminaria and Sargassum (2) Gelidium and Gracilaria (3) Anabaena and Volvox (4) Chlorella and Spirulina
- Which of the following hormone levels will cause release of ovum (ovulation) from the graffian follicle? (1) High concentration of Estrogen (2) High concentration of Progesterone (3) Low concentration of LH (4) Low concentration of FSH
- Match the following columns and select the correct option.
Column - I Column - II
(a) Bt cotton (i) Gene therapy
(b) Adenosine (ii) Cellular defence deaminase deficiency
(c) RNAi (iii) Detection of HIV infection
(d) PCR (iv) Bacillus thuringiensis
(a) (b) (c) (d) (1) (iv) (i) (ii) (iii) (2) (iii) (ii) (i) (iv) (3) (ii) (iii) (iv) (i) (4) (i) (ii) (iii) (iv)
- •h¸‚ÍòÊË Áfl÷Ê¡Ÿ ∑§ ‚¥Œ÷¸ ◊¥ ÁŸêŸÁ‹Áπà ∑§Ê ‚È◊Á‹Ã
∑§ËÁ¡∞ — (a) ÿÈÇ◊¬≈˜U≈U •flSÕÊ (i) ©¬ÊãÃË÷flŸ (b) SÕÍ‹¬≈˜U≈U •flSÕÊ (ii) ∑§Êß∞ï◊≈UÊ (c) Ám¬≈˜U≈U •flSÕÊ (iii) ¡ËŸ ÁflÁŸ◊ÿ (d) ¬Ê⁄UªÁÃ∑˝§◊ (iv) ‚ÍòÊÿÈÇ◊Ÿ («UÊÿÊ∑§ÊߟÁ‚‚) ÁŸêŸÁ‹Áπà ◊¥ ‚ ‚„Ë Áfl∑§À¬ øÈÁŸ∞ — (a) (b) (c) (d) (1) (iii) (iv) (i) (ii) (2) (iv) (iii) (ii) (i) (3) (i) (ii) (iv) (iii) (4) (ii) (iv) (iii) (i)
- ÁŸêŸÁ‹Áπà ◊¥ ‚ ∑§ÊÒŸ ‚Ê ÿÈÇ◊ ∞∑§ ∑§ÊÁ‡Ê∑§Ëÿ ‡ÊÒflÊ‹Ê¥ ∑§Ê
„Ò? (1) ‹ÒÁ◊ŸÁ⁄UÿÊ •ÊÒ⁄U ‚Ê⁄UªÊ‚◊
(2) ¡Á‹Á«Uÿ◊ •ÊÒ⁄U ª˝ÊÁ‚‹Á⁄UÿÊ (3) ∞ŸÊ’ËŸÊ •ÊÒ⁄U flÊÚÀflÊÚÄ‚
(4) Ä‹Ê⁄U‹Ê •ÊÒ⁄U S¬ÊßL§‹ËŸÊ
- ÁŸêŸ ∑§ ∑§ÊÒŸ ª˝Ê»§Ë ¬È≈U∑§ ‚ •¥«UÊáÊÈ ∑§Ê ◊ÊøŸ (•¥«UÊà‚ª¸)
∑§⁄UªÊ?
(1) ∞S≈˛UÊ¡Ÿ ∑§Ë ©ìÊ ‚Ê¥Œ˝ÃÊ (2) ¬˝Ê¡S≈U⁄UÊŸ ∑§Ë ©ìÊ ‚Ê¥Œ˝ÃÊ
(3) LH ∑§Ë ÁŸêŸ ‚Ê¥Œ˝ÃÊ (4) FSH ∑§Ë ÁŸêŸ ‚Ê¥Œ˝ÃÊ
- ÁŸêŸ SÃ¥÷Ê¥ ∑§Ê Á◊‹ÊŸ ∑§⁄U ‚„Ë Áfl∑§À¬ ∑§Ê øÿŸ ∑§⁄UÊ–
SÃ¥÷ - I SÃ¥÷ - II (a) ’Ë≈UË ∑§¬Ê‚ (i) ¡ËŸ ÁøÁ∑§à‚Ê (b) ∞«UËŸÊ‚ËŸ Á«U∞◊ËŸ¡ (ii) ∑§ÊÁ‡Ê∑§Ëÿ ‚È⁄UˇÊÊ ∑§Ë ∑§◊Ë (c) •Ê⁄U.∞Ÿ.∞.•Ê߸ (iii) HIV ‚¥∑˝§◊áÊ ∑§Ê ¬ÃÊ ‹ªÊŸÊ (d) ¬Ë.‚Ë.•Ê⁄U. (iv) ’ÒÁ‚‹‚ ÕÈÁ⁄¥UÁ¡ÁŸÁ‚‚ (a) (b) (c) (d) (1) (iv) (i) (ii) (iii) (2) (iii) (ii) (i) (iv) (3) (ii) (iii) (iv) (i) (4) (i) (ii) (iii) (iv)
E1 14 Hindi+English
- Montreal protocol was signed in 1987 for control of :
(1) Transport of Genetically modified organisms from one country to another (2) Emission of ozone depleting substances
(3) Release of Green House gases
(4) Disposal of e-wastes
- Which of the following is correct about viroids? (1) They have RNA with protein coat.
(2) They have free RNA without protein coat.
(3) They have DNA with protein coat. (4) They have free DNA without protein coat.
- The ovary is half inferior in : (1) Brinjal
(2) Mustard
(3) Sunflower (4) Plum
- The enzyme enterokinase helps in conversion of : (1) protein into polypeptides
(2) trypsinogen into trypsin
(3) caseinogen into casein (4) pepsinogen into pepsin
- Match the trophic levels with their correct species examples in grassland ecosystem.
(a) Fourth trophic level (i) Crow
(b) Second trophic level (ii) Vulture
(c) First trophic level (iii) Rabbit
(d) Third trophic level (iv) Grass
Select the correct option : (a) (b) (c) (d)
(1) (ii) (iii) (iv) (i)
(2) (iii) (ii) (i) (iv) (3) (iv) (iii) (ii) (i)
(4) (i) (ii) (iii) (iv)
- ‚Ÿ˜ 1987 ◊¥ ◊ÊÚÁã≈˛Uÿ‹ ¬˝Ê≈UÊ∑§ÊÚ‹ Á∑§‚ ¬⁄U ÁŸÿ¥òÊáÊ ∑§ Á‹∞
„SÃÊˇÊÁ⁄Uà Á∑§ÿÊ ªÿÊ ÕÊ?
(1) ∞∑§ Œ‡Ê ‚ ŒÍ‚⁄U Œ‡Ê ◊¥ •ÊŸÈfl¥Á‡Ê∑§Ã— M§¬Ê¥ÃÁ⁄Uà ¡ËflÊ¥ ∑§ ¬Á⁄Ufl„Ÿ ∑§ Á‹∞
(2) •Ê$¡ÊŸ ∑§Ê ˇÊÁà ¬„È°øÊŸ flÊ‹ ¬ŒÊÕÊZ ∑§Ê ©à‚¡¸Ÿ (3) „Á⁄Uà ªÎ„ ªÒ‚Ê¥ ∑§Ê ¿UÊ«∏ŸÊ
(4) e-flS≈U (e-∑ͧ«∏Ê ∑§⁄U∑§≈U) ∑§Ê ÁŸ¬≈UÊŸ
- flÊÿ⁄UÊß«UÊ¥ ∑§ Áfl·ÿ ◊¥, ÁŸêŸÁ‹Áπà ◊¥ ‚ ∑§ÊÒŸ ‚Ê ∑§ÕŸ ‚„Ë
„Ò?
(1) ©Ÿ◊¥ •Ê⁄U.∞Ÿ.∞. ∑§ ‚ÊÕ ¬˝Ê≈UËŸ •Êfl⁄UáÊ „ÊÃÊ „Ò– (2) ©Ÿ◊¥ ¬˝Ê≈UËŸ •Êfl⁄UáÊ ∑§ Á’ŸÊ SflÃ¥òÊ •Ê⁄U.∞Ÿ.∞. „ÊÃÊ „Ò– (3) ©Ÿ◊¥ ¬˝Ê≈UËŸ •Êfl⁄UáÊ ∑§ ‚ÊÕ «UË.∞Ÿ.∞. „ÊÃÊ „Ò–
(4) ©Ÿ◊¥ ¬˝Ê≈UËŸ •Êfl⁄UáÊ ∑§ Á’ŸÊ SflÃ¥òÊ «UË.∞Ÿ.∞. „ÊÃÊ „Ò–
- •h¸ •œÊflÃ˸ •¥«UʇÊÿ Á∑§‚◊¥ ¬ÊÿÊ ¡ÊÃÊ „Ò?
(1) ’Ò¥ªŸ (2) ‚⁄U‚Ê¥
(3) ‚Í⁄U¡◊ÈπË (4) •Ê‹Í’ÈπÊ⁄UÊ
- ∞¥≈U⁄UÊ∑§Êߟ¡ Á∑§‚∑§Ê ’Œ‹Ÿ ◊¥ ‚„ÊÿÃÊ ∑§⁄UÃÊ „Ò?
(1) ¬˝Ê≈UËŸ ∑§Ê ¬Êڋˬå≈UÊß«U ◊¥ (2) Á≈˛UÁå‚ŸÊ¡Ÿ ∑§Ê Á≈˛UÁå‚Ÿ ◊¥
(3) ∑Ò§‚ËŸÊ¡Ÿ ∑§Ê ∑Ò§‚ËŸ ◊¥ (4) ¬Áå‚ŸÊ¡Ÿ ∑§Ê ¬Áå‚Ÿ ◊¥
- ÉÊÊ‚ ÷ÍÁ◊ ¬ÊÁ⁄UÃãòÊ ◊¥ ¬Ê·Ë SÃ⁄UÊ¥ ∑§ ‚ÊÕ ¡ÊÁÃÿÊ¥ ∑§ ‚„Ë
©ŒÊ„⁄UáÊ ∑§Ê ‚È◊Á‹Ã ∑§ËÁ¡∞– (a) øÃÈÕ¸ ¬Ê·Ë SÃ⁄U (i) ∑§ÊÒflÊ (b) ÁmÃËÿ ¬Ê·Ë SÃ⁄U (ii) Áªh (c) ¬˝Õ◊ ¬Ê·Ë SÃ⁄U (iii) π⁄UªÊ‡Ê (d) ÃÎÃËÿ ¬Ê·Ë SÃ⁄U (iv) ÉÊÊ‚
‚„Ë Áfl∑§À¬ øÈÁŸ∞ — (a) (b) (c) (d) (1) (ii) (iii) (iv) (i) (2) (iii) (ii) (i) (iv) (3) (iv) (iii) (ii) (i) (4) (i) (ii) (iii) (iv)
E1 16 Hindi+English
- Which of the following is not an inhibitory substance governing seed dormancy?
(1) Gibberellic acid
(2) Abscisic acid
(3) Phenolic acid
(4) Para-ascorbic acid
- Name the enzyme that facilitates opening of DNA helix during transcription.
(1) DNA ligase
(2) DNA helicase
(3) DNA polymerase
(4) RNA polymerase
- Which of the following would help in prevention of diuresis?
(1) More water reabsorption due to undersecretion of ADH
(2) Reabsorption of Na+^ and water from renal tubules due to aldosterone
(3) Atrial natriuretic factor causes vasoconstriction
(4) Decrease in secretion of renin by JG cells
- In relation to Gross primary productivity and Net primary productivity of an ecosystem, which one of the following statements is correct?
(1) Gross primary productivity is always less than net primary productivity.
(2) Gross primary productivity is always more than net primary productivity.
(3) Gross primary productivity and Net primary productivity are one and same.
(4) There is no relationship between Gross primary productivity and Net primary productivity.
- ÁŸêŸÁ‹Áπà ◊¥ ‚ ∑§ÊÒŸ ∞∑§ ’Ë¡ ¬˝‚ÈÁåà ÁŸÿ¥ÁòÊà ∑§⁄UŸ flÊ‹Ê
ÁŸ⁄UÊœ∑§ ¬ŒÊÕ¸ Ÿ„Ë¥ „Ò?
(1) Á¡’⁄UÁ‹∑§ •ê‹
(2) ∞é‚ËÁ‚∑§ •ê‹
(3) Á»§ŸÊÁ‹∑§ •ê‹
(4) ¬Ò⁄UÊ-∞S∑§ÊÚÁ’¸∑§ •ê‹
- •ŸÈ‹πŸ ∑§ ‚◊ÿ «UË.∞Ÿ.∞. ∑§Ë ∑È¥§«U‹Ë ∑§Ê πÊ‹Ÿ ◊¥ ∑§ÊÒŸ‚Ê
∞¥¡Êß◊ ◊ŒŒ ∑§⁄UÃÊ „Ò?
(1) «UË.∞Ÿ.∞. ‹Êߪ$¡
(2) «UË.∞Ÿ.∞. „Ò‹Ë∑§$¡
(3) «UË.∞Ÿ.∞. ¬ÊÚ‹Ë◊⁄U$¡
(4) •Ê⁄U.∞Ÿ.∞. ¬ÊÚÁ‹◊⁄U$¡
- ÁŸêŸ ◊¥ ∑§ÊÒŸ ◊ÍòÊflÎÁh ∑§Ê ⁄UÊ∑§Ÿ ◊¥ ‚„ÊÿÃÊ ∑§⁄UªÊ?
(1) ADH ∑§ •À¬dfláÊ ‚ •Áœ∑§ ¡‹ ∑§Ê ¬ÈŸ⁄UÊfl‡ÊÊ·áÊ
(2) ∞À«UÊS≈U⁄UÊŸ ∑§ ∑§Ê⁄UáÊ flÎÄ∑§ ŸÁ‹∑§Ê ‚ Na+^ ∞fl¥ ¡‹ ∑§Ê ¬ÈŸ⁄UÊfl‡ÊÊ·áÊ
(3) ∞Á≈˛Uÿ‹ ŸÁ≈˛UÿÈ⁄UÁ≈U∑§ ∑§Ê⁄U∑§ mÊ⁄UÊ flÊÁ„∑§Ê•Ê¥ ∑§Ê ‚¥∑§ËáʸŸ „ÊŸÊ
(4) JG ∑§ÊÁ‡Ê∑§Ê•Ê¥ mÊ⁄UÊ ⁄UÁŸŸ ∑§Ê dÊfláÊ ∑§◊ „ÊŸÊ
- ∞∑§ ¬ÊÁ⁄UÃãòÊ ◊¥ ‚∑§‹ ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ •ÊÒ⁄U Ÿ≈U ¬˝ÊÕÁ◊∑§
©à¬ÊŒ∑§ÃÊ ∑§ ‚¥’㜠◊¥, ÁŸêŸÁ‹Áπà ◊¥ ‚ ∑§ÊÒŸ ‚Ê ∑§ÕŸ ‚„Ë „Ò?
(1) ‚∑§‹ ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ ‚ŒÒfl Ÿ≈U ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ ‚ ∑§◊ „ÊÃË „Ò–
(2) ‚∑§‹ ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ ‚ŒÒfl Ÿ≈U ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ ‚ •Áœ∑§ „ÊÃË „Ò–
(3) ‚∑§‹ ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ •ÊÒ⁄U Ÿ≈U ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ ∞∑§ „Ë „Ò •ÊÒ⁄U •Á÷ÛÊ „Ò–
(4) ‚∑§‹ ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ •ÊÒ⁄U Ÿ≈U ¬˝ÊÕÁ◊∑§ ©à¬ÊŒ∑§ÃÊ ∑§ ’Ëø ∑§Ê߸ ‚ê’㜠Ÿ„Ë¥ „Ò–
Hindi+English 17 E
- Match the following columns and select the correct option. Column - I Column - II (a) Placenta (i) Androgens
(b) Zona pellucida (ii) Human Chorionic Gonadotropin (hCG) (c) Bulbo-urethral (iii) Layer of the ovum glands
(d) Leydig cells (iv) Lubrication of the Penis (a) (b) (c) (d) (1) (iv) (iii) (i) (ii) (2) (i) (iv) (ii) (iii) (3) (iii) (ii) (iv) (i) (4) (ii) (iii) (iv) (i)
- Strobili or cones are found in : (1) Salvinia (2) Pteris (3) Marchantia (4) Equisetum
- Some dividing cells exit the cell cycle and enter vegetative inactive stage. This is called quiescent stage (G 0 ). This process occurs at the end of : (1) M phase (2) G 1 phase (3) S phase (4) G 2 phase
- Flippers of Penguins and Dolphins are examples of : (1) Adaptive radiation (2) Convergent evolution (3) Industrial melanism (4) Natural selection
- If the distance between two consecutive base pairs is 0.34 nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is 6.6× 109 bp, then the length of the DNA is approximately : (1) 2.0 meters (2) 2.5 meters (3) 2.2 meters (4) 2.7 meters
- ÁŸêŸ SÃ¥÷Ê¥ ∑§Ê Á◊‹ÊŸ ∑§⁄U ‚„Ë Áfl∑§À¬ ∑§Ê øÿŸ ∑§⁄UÊ–
SÃ¥÷ - I SÃ¥÷ - II (a) •¬⁄UÊ (i) ∞¥«˛UÊ¡Ÿ (b) $¡ÊŸÊ ¬ÀÿÈÁ‚«UÊ (ii) ◊ÊŸfl ¡⁄UÊÿÈ ªÊŸÒ«UÊ≈˛UÊÁ¬Ÿ (c) ’À’Ê-ÿÍ⁄UÕ˝‹ ª˝¥ÁÕÿÊ° (iii) •¥«UÊáÊÈ ∑§Ë ¬⁄Uà (d) ‹ËÁ«Uª ∑§ÊÁ‡Ê∑§Ê∞° (iv) Á‡Ê‡Ÿ ∑§Ê SŸ„Ÿ (a) (b) (c) (d) (1) (iv) (iii) (i) (ii) (2) (i) (iv) (ii) (iii) (3) (iii) (ii) (iv) (i) (4) (ii) (iii) (iv) (i)
- S≈˛UÊÁ’‹Ê߸ ÿÊ ‡Ê¥∑ȧ Á∑§‚◊¥ ¬Êÿ ¡Êà „Ò¥?
(1) ‚ÊÁÀflÁŸÿÊ (2) ≈UÁ⁄U‚ (3) ◊Ê∑Z§Á‡ÊÿÊ (4) ßÄflË‚Ë≈U◊
- ∑ȧ¿U Áfl÷ÊÁ¡Ã „Ê ⁄U„Ë ∑§ÊÁ‡Ê∑§Êÿ¥ ∑§ÊÁ‡Ê∑§Ê ø∑˝§áÊ ‚ ’Ê„⁄U
ÁŸ∑§‹ ¡ÊÃË „Ò¥ •ÊÒ⁄U ∑§ÊÁÿ∑§ ÁŸÁc∑˝§ÿÃÊ •flSÕÊ ◊¥ ¬˝fl‡Ê ∑§⁄U ¡ÊÃË „Ò– ß‚ ‡Êʥà •flSÕÊ (G 0 ) ∑§„Ê ¡ÊÃÊ „Ò– ÿ„ ¬˝Á∑˝§ÿÊ Á∑§‚∑§ •ãà ◊¥ „ÊÃË „Ò?
(1) M ¬˝ÊflSÕÊ (2) G 1 ¬˝ÊflSÕÊ (3) S ¬˝ÊflSÕÊ (4) G 2 ¬˝ÊflSÕÊ
- ¬¥ÁÇflŸ ∞fl¥ «UÊÚ‹Á»§Ÿ ∑§ ¬ˇÊ ©ŒÊ„⁄UáÊ „Ò —
(1) •ŸÈ∑ͧ‹Ë ÁflÁ∑§⁄UáÊ ∑§Ê (2) •Á÷‚Ê⁄UË Áfl∑§Ê‚ ∑§Ê (3) •ÊÒlÊÁª∑§ ◊Ò‹ÁŸí◊ ∑§Ê (4) ¬˝Ê∑ΧÁÃ∑§ fl⁄UáÊ ∑§Ê
- ÿÁŒ ŒÊ ‹ªÊÃÊ⁄U ˇÊÊ⁄U ÿÈÇ◊Ê¥ ∑§ ’Ëø ∑§Ë ŒÍ⁄UË 0.34 nm „Ò •ÊÒ⁄U
∞∑§ S߬ÊÿË ∑§ÊÁ‡Ê∑§Ê ∑§Ë DNA ∑§Ë Ám∑È¥§«U‹Ë ◊¥ ˇÊÊ⁄U ÿÈÇ◊Ê¥ ∑§Ë ∑ȧ‹ ‚¥ÅÿÊ 6.6× 109 bp „Ò– Ã’ DNA ∑§Ë ‹ê’Ê߸ „ÊªË ‹ª÷ª —
(1) 2.0 ◊Ë≈U⁄U (2) 2.5 ◊Ë≈U⁄U (3) 2.2 ◊Ë≈U⁄U (4) 2.7 ◊Ë≈U⁄U
Hindi+English 19 E
- Match the following columns and select the correct option.
Column - I Column - II
(a) Pituitary gland (i) Grave’s disease
(b) Thyroid gland (ii) Diabetes mellitus
(c) Adrenal gland (iii) Diabetes insipidus
(d) Pancreas (iv) Addison’s disease
(a) (b) (c) (d)
(1) (iv) (iii) (i) (ii)
(2) (iii) (ii) (i) (iv)
(3) (iii) (i) (iv) (ii)
(4) (ii) (i) (iv) (iii)
- Select the correct statement.
(1) Glucocorticoids stimulate gluconeogenesis.
(2) Glucagon is associated with hypoglycemia.
(3) Insulin acts on pancreatic cells and adipocytes.
(4) Insulin is associated with hyperglycemia.
- Which one of the following is the most abundant protein in the animals?
(1) Haemoglobin
(2) Collagen
(3) Lectin
(4) Insulin
- Experimental verification of the chromosomal theory of inheritance was done by :
(1) Mendel
(2) Sutton
(3) Boveri
(4) Morgan
- ÁŸêŸ SÃ¥÷Ê¥ ∑§Ê Á◊‹ÊŸ ∑§⁄U ‚„Ë Áfl∑§À¬ ∑§Ê øÿŸ ∑§⁄UÊ–
SÃ¥÷ - I SÃ¥÷ - II
(a) ¬ËÿÍ· ª˝¥ÁÕ (i) ª˝fl‚ ⁄Uʪ
(b) ÕÊÿ⁄UÊÚß«U ª˝¥ÁÕ (ii) «UÊÿÊÁ’≈UË¡ ◊Á‹≈U‚
(c) •ÁœflÎÄ∑§ ª˝¥ÁÕ (iii) «UÊÿÊÁ’≈UË¡ ßã‚ËÁ¬«U‚
(d) •ÇãÿʇÊÿ (iv) ∞«UË‚Ÿ ⁄Uʪ
(a) (b) (c) (d)
(1) (iv) (iii) (i) (ii)
(2) (iii) (ii) (i) (iv)
(3) (iii) (i) (iv) (ii)
(4) (ii) (i) (iv) (iii)
- ‚„Ë ∑§ÕŸ ∑§Ê øÿŸ ∑§⁄UÊ–
(1) Ç‹Í∑§Ê∑§ÊÚÁ≈¸U∑§ÊÚß«U Ç‹Í∑§ÊÁŸÿÊÁ¡ŸÁ‚‚ ∑§Ê ¬˝Á⁄Uà ∑§⁄Uà „Ò¥–
(2) Ç‹Í∑§ªÊÚŸ „Ê߬ÊÇ‹Êß‚ËÁ◊ÿÊ ‚ ‚¥’¥ÁœÃ „Ò–
(3) ߥ‚ÈÁ‹Ÿ •ÇãÿʇÊÿË ∑§ÊÁ‡Ê∑§Ê•Ê¥ ∞fl¥ ∞«UˬʂÊß≈UÊ¥ ¬⁄U Á∑˝§ÿÊ ∑§⁄UÃÊ „Ò–
(4) ߥ‚ÈÁ‹Ÿ „Ê߬⁄UÇ‹Êß‚ËÁ◊ÿÊ ‚ ‚¥’¥ÁœÃ „Ò–
- ÁŸêŸ ◊¥ ∑§ÊÒŸ‚Ë ¬˝Ê≈UËŸ ¡ãÃÈ•Ê¥ ◊¥ ’„ÈÃÊÿà ‚ „ÊÃË „Ò?
(1) „Ë◊ÊÇ‹ÊÁ’Ÿ
(2) ∑§Ê‹¡Ÿ
(3) ‹ÒÁÄ≈UŸ
(4) ߥ‚ÈÁ‹Ÿ
- fl¥‡ÊʪÁà ∑§ ªÈáÊ‚ÍòÊ Á‚hÊãà ∑§Ê ¬˝ÊÿÊÁª∑§ ¬˝◊ÊáÊŸ Á∑§‚Ÿ
Á∑§ÿÊ ÕÊ?
(1) ◊¥«U‹
(2) ‚≈UŸ
(3) ’Êfl⁄UË
(4) ◊ÊÚª¸Ÿ
E1 20 Hindi+English
- Match the following columns and select the correct option. Column - I Column - II
(a) Floating Ribs (i) Located between second and seventh ribs
(b) Acromion (ii) Head of the Humerus
(c) Scapula (iii) Clavicle
(d) Glenoid cavity (iv) Do not connect with the sternum (a) (b) (c) (d) (1) (ii) (iv) (i) (iii) (2) (i) (iii) (ii) (iv) (3) (iii) (ii) (iv) (i) (4) (iv) (iii) (i) (ii)
- The number of substrate level phosphorylations in one turn of citric acid cycle is : (1) Zero (2) One (3) Two (4) Three
- Dissolution of the synaptonemal complex occurs during : (1) Pachytene (2) Zygotene (3) Diplotene (4) Leptotene
- Bilaterally symmetrical and acoelomate animals are exemplified by : (1) Ctenophora (2) Platyhelminthes (3) Aschelminthes (4) Annelida
- The body of the ovule is fused within the funicle at : (1) Hilum (2) Micropyle (3) Nucellus (4) Chalaza
- ÁŸêŸ SÃ¥÷Ê¥ ∑§Ê Á◊‹ÊŸ ∑§⁄U ‚„Ë Áfl∑§À¬ ∑§Ê øÿŸ ∑§⁄UÊ–
SÃ¥÷ - I SÃ¥÷ - II
(a) å‹ÊflË ¬‚Á‹ÿÊ° (i) ŒÍ‚⁄UË ∞fl¥ ‚ÊÃflË¥ ¬‚‹Ë ∑§ ’Ëø ÁSÕà „ÊÃË „Ò¥
(b) ∞∑˝§ÊÁ◊ÿŸ (ii) sÍ◊⁄U‚ ∑§Ê ‡ÊË·¸
(c) S∑Ò§¬È‹Ê (iii) Ä‹Áfl∑§‹ (d) Ç‹ËŸÊÚÿ«U ªÈ„Ê (iv) ©⁄UÊÁSÕ ‚ Ÿ„Ë¥ ¡È«∏ÃË (a) (b) (c) (d) (1) (ii) (iv) (i) (iii) (2) (i) (iii) (ii) (iv) (3) (iii) (ii) (iv) (i) (4) (iv) (iii) (i) (ii)
- Á‚Á≈˛U∑§ •ê‹ ø∑˝§ ∑§ ∞∑§ ÉÊÈ◊Êfl ◊¥ ∑§Êÿ¸Œ˝fl SÃ⁄U »§ÊS»§ÊÁ⁄U‹‡ÊŸÊ¥
∑§Ë ‚¥ÅÿÊ ÄÿÊ „ÊÃË „Ò?
(1) ‡ÊÍãÿ
(2) ∞∑§
(3) ŒÊ
(4) ÃËŸ
- Á‚Ÿå≈UÊŸË◊‹ ‚Áê◊üÊ ∑§Ê ÁflÉÊ≈UŸ „ÊÃÊ „Ò —
(1) SÕÍ‹¬^ ∑§ ŒÊÒ⁄UÊŸ
(2) ÿÈÇ◊¬^ ∑§ ŒÊÒ⁄UÊŸ
(3) Ám¬^ ∑§ ŒÊÒ⁄UÊŸ
(4) ßȬ^ ∑§ ŒÊÒ⁄UÊŸ
- Ám¬Ê‡fl¸ ‚◊Á◊Áà ∞fl¥ •ªÈ„Ëÿ ¡ãÃÈ•Ê¥ ∑§ ©ŒÊ„⁄UáÊ Á∑§‚ ‚¥ÉÊ ◊¥
„Ò¥?
(1) ≈UËŸÊ»§Ê⁄UÊ
(2) å‹≈UË„ÒÁÀ◊¥ÕË¡
(3) ∞S∑§„ÒÁÀ◊¥ÕË¡
(4) ∞ŸÁ‹«UÊ
- ’Ë¡Êá«U ∑§Ê Á¬¥«U, ’Ë¡Êá«U flΥà ‚ ∑§„Ê° ¬⁄U ‚¥‹Áÿà „ÊÃÊ „Ò?
(1) ŸÊÁ÷∑§Ê
(2) ’Ë¡Êá«UmÊ⁄U
(3) ’Ë¡Êá«U∑§Êÿ
(4) ÁŸ÷ʪ
