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This quiz focuses on confidence intervals and sampling distributions, essential concepts in statistics. It covers topics like constructing confidence intervals for means and proportions, interpreting confidence intervals, determining sample sizes, and understanding the relationship between sample size and confidence interval width. The quiz includes multiple-choice questions and problems that require applying these concepts to real-world scenarios.
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A statistics professor recently graded final exams for students in her introductory statistics course. In a review
That is correct!
A random sample of adults were asked whether they prefer reading an e-book over a printed book. The
preferred reading an e-book.
books. That is correct!
The pages per book in a library are normally distributed with an unknown population mean. A random sample
That is correct! We estimate with 95% confidence that the sample mean is between 237 and 293 pages. We estimate that 95% of the time a book is selected, there will be between 237 and 293 pages. We estimate with 95% confidence that the true population mean is between 237 and 293 pages.
sample size that can be taken? Round up to the nearest integer. That is correct! Answer: 14 dog heights
Clarence wants to estimate the percentage of students who live more than three miles from the school. He
should be polled to create the confidence interval?
Use the table of values above. That is correct!
use ascending order.. Score 516 536 462 461 519 496 517 488 521 HelpCopy to ClipboardDownload CSV That is correct! Answer: (509.30, 519.18)
salary, in thousands of dollars. Round your answers to two decimal places and use increasing order. Salary 71 70 69 65 72 69 72 72 71 HelpCopy to ClipboardDownload CSV That is correct!
sample size that can be taken?
That is correct!
Round your answer to the nearest whole number (percent).
That is correct!
Determine which normal distribution has the smallest standard deviation. That is correct! A B C
proportion of gauges is acceptable? Round your answer to four decimal places. That is correct!
pox vaccine. The school nurse wants to make sure that the school meets all state requirements for vaccinations at public schools. Find the population proportion, as well as the mean and standard deviation of the sampling
Round all answers to 3 decimal places. That is correct!
The lengths of text messages are normally distributed with an unknown population mean. A random
That is correct! We estimate that 95% of text messages have lengths between 23 and 47 characters. We estimate with 95% confidence that the true population mean is between 23 and 47 characters. We estimate with 95% confidence that the sample mean is between 23 and 47 characters.
correct answers.
A normal bell curve labeled Upper A and a normal elongated curve labeled Upper B are centered at the same point. Normal curve Upper B is narrower and above normal curve Upper A. That is correct!
HelpCopy to ClipboardDownload CSV That is correct! Answer: (894.43, 940.21)
the mean, ________. Correctly fill in the blanks in the statement above. That is correct! Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is −0.889. This z-score tells you that x=56 is 0.889 standard deviations to the left of the mean, 40. Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is −1.067. This z-score tells you that x=56 is 1.067 standard deviations to the left of the mean, 40. Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is 1.067. This z-score tells you that x=56 is 1.067 standard deviations to the right of the mean, 40. Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is 0.889. This z-score tells you that x=56 is 0.889 standard deviations to the right of the mean, 40.
the mean, ________. Correctly fill in the blanks in the statement above. That is correct! Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is 0.75. This z-score tells you that x=56 is 0.75 standard deviations to the right of the mean, 62. Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is −0.75. This z-score tells you that x=56 is 0.75 standard deviations to the left of the mean, 62. Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is 0.545. This z-score tells you that x=56 is 0.545 standard deviations to the right of the mean, 62. Suppose Hugo types 56 words per minute in a typing test on Wednesday. The z-score when x=56 is −0.545. This z-score tells you that x=56 is 0.545 standard deviations to the left of the mean, 62.
Lisa has collected data to find that the number of pages per book on a book shelf has a normal distribution.
two decimal places if necessary. That is correct!
Lisa has collected data to find that the number of pages per book on a book shelf has a normal distribution.
two decimal places if necessary. That is correct!