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MATH 225N Week 5 Assignment / MATH225 Week 5 Assignment : Central Limit Theorem for Means( 2024-2025):Chamberlain College of Nursing
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Likewise, when the distribution is normal the mean of the sampling distribution is equal to the mean of the population μx ¯= μ =100 grams. Question A head librarian for a large city is looking at the overdue fees per user system-wide to determine if the library should extend its lending period. The average library user has $19.67 in fees, with a standard deviation of $7.02. The data is normally distributed and a sample of 72 library users is selected at random from the population. Select the expected mean and standard deviation of the sampling distribution from the options below. Correct answer: σx ¯=$0. μx ¯=$19. The standard deviation of the sampling distribution is σx ¯= σn −−√=$7.0272−−√=$0. When the distribution is normal, the mean of the sampling distribution is equal to the mean of the population μx ¯= μ =$19..
To find the Standard Deviation of the sampling distribution, we divide the population standard deviation by the square root of the sample size: σx ¯= σn −−√=$24,500150−−−√=$2,000.
We are given population mean μ =13 and population standard deviation σ =5 , and want to find the mean and standard error of the sampling distribution, μx ¯ and σx ¯ for samples of size n =. By the Central Limit Theorem, the means of the two distributions are the same: μx ¯= μ = To find the Standard Deviation of the sampling distribution, we divide the population standard deviation by the square root of the sample size: σx ¯= σn −−√=545−−√≈
takes a random sample of 35 years to create a statistical study. Identify each of the following, rounding to the nearest hundredth when necessary: We are given population mean μ =150 and population standard deviation σ =18 , and want to find the mean and standard error of the sampling distribution, μx ¯ and σx ¯ for samples of size n =. By the Central Limit Theorem, the means of the two distributions are the same: μx ¯= μ = To find the Standard Deviation of the sampling distribution, we divide the population standard deviation by the square root of the sample size: σx ¯= σn −−√=18/35−−√≈3.
B has the larger standard deviation. Remember that the mean of a normal distribution is the x -value of its central point (the top of the "hill"). Therefore, a distribution with a larger mean will be centered farther to the right than a distribution with a smaller mean. Because B is farther to the right than A , the mean of B is greater than the mean of A. Remember that the standard deviation tells how spread out the normal distribution is. So a high standard deviation means the graph will be short and spread out. A low standard deviation means the graph will be tall and skinny. Because B is shorter and more spread out than A , we find that B has the larger standard deviation.
Because A and B are centered at the same point, their means are equal. Remember that the standard deviation tells how spread out the normal distribution is. So a high standard deviation means the graph will be short and spread out. A low standard deviation means the graph will be tall and skinny. Because B is shorter and more spread out than A , we find that B has the larger standard deviation.
A figure consists of two curves labeled Upper A and Upper B. Curve Upper A is shorter and more spread out than curve Upper B, and the curve Upper B is taller and farther to the right than curve Upper A. Correct answer: B has the larger mean. A has the larger standard deviation. Remember that the mean of a normal distribution is the x -value of its central point (the top of the "hill"). Therefore, a distribution with a larger mean will be centered farther to the right than a distribution with a smaller mean. Because B is farther to the right than A , the mean of B is greater than the mean of A. Remember that the standard deviation tells how spread out the normal distribution is. So a high standard deviation means the graph will be short and spread out. A low standard deviation means the graph will be tall and skinny. Because A is shorter and more spread out than B , we find that A has the larger standard deviation.
A figure consists of three curves along a horizontal axis, labeled Upper A, Upper B and Upper C. Curve Upper A is farthest to the left from the center, curve Upper B is evenly spread out to the right from the center, and curve Upper C is tall and the least spread out. C Remember that the standard deviation tells how spread out the normal distribution is. So a high standard deviation means the graph will be short and spread out. A low standard deviation means the graph will be tall and skinny. The distribution that is the tallest and least spread out is C , so that has the smallest standard deviation.
A curve labeled B rises to a maximum and then falls. A curve labeled A rises to a maximum below and to the right of A and then falls. A curve labeled C rises to a maximum to the right of and below the maximum of A. B Remember that the mean of a normal distribution is the x -value of its central point (the top of the "hill"). Therefore, a distribution with a larger mean will be centered farther to the right than a distribution with a smaller mean. The distribution that is farthest to the left is B , so that has the smallest mean.
We are given population mean μ =170 and population standard deviation σ =45 , and want to find the mean and standard error of the sampling distribution, μx ¯ and σx ¯ for samples of size n =. By the Central Limit Theorem, the means of the two distributions are the same: μx ¯= μ = To find the Standard Deviation of the sampling distribution, we divide the population standard deviation by the square root of the sample size: σx ¯= σn −−√=45/31−−√≈