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Linear and Nonlinear Spring Elements: Equations of Motion and Static Equilibrium, Study notes of Physics

Information on the dynamics and statics of linear and nonlinear spring elements. It covers the calculation of static deflection, the equation of motion, and the free body diagram for various spring configurations. The document also includes notes on the assumptions made and the significance of the static equilibrium position.

Typology: Study notes

2021/2022

Uploaded on 09/27/2022

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1
Linear spring element
Fs
Free length
l
Fs
s
static deflection
F
Applied force on spring
deflection
K=dF/d
Fs
s
Notes:
a) Spring element is regarded as massless
b) K = stiffness coefficient is constant
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1

Linear spring element

F

s

Free length

l

F

s

s static deflection

F

Applied force on spring

deflection K =d

F /d

F

s

s

Notes: a)

Spring element is regarded as massless b)

K

= stiffness coefficient is constant

2

Linear spring + added weight

W

Free length

l

W

s staticdeflection

F

static deflection

K =d

F /d

W

s

Notes: a)

Block has weight

W= Mg

b)

Block is regarded as a point mass

W=F

s^

= K

s

Balance of static forces

W Fs

Reaction force from spring

4

Equation of motion

F

spring

= K

( X+

s^ )

Notes:

Motions from SEP

Freelength l

W+F

s^ +X

SEP (t)

FBD:
X

W+F Fspring

M

M Ax = W+F - F

spring

M Ax = W+F – K(X+

s^ )

M Ax = ( W-K

s^ ) +F – KX

M Ax = +F – KXM Ax + K X= F

(t)

2

2

X

d^

X

A^

X

d t

^

^

1

Nonlinear spring element

F

s

Free length

l

F

s

s static deflection

F

Applied force on spring

static deflection

F

s

s

Notes: a)

Spring element is massless b)

Force vs. deflection curve is NONlinear c)

K

1 and

K

3 are material parameters

3

1

3

F^

K^

K ^

^

3

1

3

F

K

K ^

3

Nonlinear spring + weight + force

F

(t)

W

Free length

l

W+F

s^ +X

SEP (t)

F

Reaction force from spring

deflection

W+F

s

X+

s

Notes: a)

Coordinate

X

describing motion has

origin at

Static Equilibrium Position

(SEP)

b)

For free body diagram, assume stateof motion, for example

X

(t)^ >

c)

Then,

state

Newton’s equation of

motion d)

Assume no lateral (side motions)

Free Body diagram

W+F Fspring

F

(t)

M

M Ax = W+F - F

spring

acceleration

4

Equation of motion Notes: a)

Motions from SEP

Freelength l

W+F

s^ +X

SEP (t)

FBD:
X

W+F Fspring

M

2 2 X

d^

X

A^

X

d t ^

^



^

^

^

(^3) 

1

3

spring

s^

s

F^
K^
X^
K^
X

^
^
^

( ) t^

spring

M X

F

W

F

^



^

^

^

( )^

1

3

t^

s^

s

M X

F^

W

K^

X^

K

X

^

^

^

^

^



Expand RHS:

^

^

^

3

2

2

3

( )^

1

3

t^

s^

s^

s^

s

M X

F^

W

K^

X^

K^

X^

X^

X

^

^

^

^

^

^

^

^

^

^

^

^

^

^

3

2

2

3

( )

1

3

1

3

3

3

3

t^

s^

s^

s^

s

M X

F^

W

K

K

K

K

X^

K^

X^

X

^

^

^

^

^

^

^

^

 Cancel terms from force balance at SEP to get

^

^

^

2

2

3

1

3

3

( )

s^

s^

t

M X

K

K

X

K

X

X

F

6

Linear equation of motion Freelength l

W+F

s^ +X

(t)

SEP FBD:
X

W+F Fspring

M

( )

e^

t

M X

K

X

F



^

2 

1

3 3

e^

s

K

K

K

^

3 

1

3

2

1

3 3

s

spring

e^

s

d^

K^

K

dF

K^

K^

K

d^

d

^

^

^

^

^

^

^

F 

deflection

W

s^

X

K

e

s

deflection

Stiffness(linear)