

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
Algebra 1 notes on graphing linear equations using intercepts. It covers the concepts of x-intercept and y-intercept, and explains how to find them for given linear equations. It also includes examples and exercises for practice.
What you will learn
Typology: Study notes
1 / 2
This page cannot be seen from the preview
Don't miss anything!
Algebra 1 Notes SOL A.6 (4.3) Graphing Using Intercepts Mrs. Grieser
1
Name: _______________________________ Block: _______ Date: _____________ Intercepts An x-intercept is a point where a function crosses the x-axis. The y-intercept is the point where a function crosses the y-axis. A line is a geometric figure determined by two points. When graphing a linear equation, we therefore only need two points. Two relatively easy points to find are the x- and y-intercepts. Recall that the ordinate (y-value) of all points on the x-axis is 0, and that the abscissa (x-value) of all points on the y-axis is 0. Therefore, if we want to find the points where a linear function crosses the x-axis (the x-intercept), we would set the output value (the y-value) to 0 and solve for x, and to find where it crosses the y-axis (the y-intercept), we would set the input value (the x-value) to 0 and solve for y. Example: Find the x- and y-intercepts of 2x + 7y = 28.
Set y = 0, because the ordinate of the point on the x-axis is 0. Then solve for x. 2x + 7(0) = 28 2x = 28 x = 14 The x-intercept is (14, 0).
Set x = 0, because the abscissa of the point on the y-axis is 0. Then solve for y. 2(0) + 7x = 28 7x = 28 x = 4 The y-intercept is (0, 4).
You try: find the x- and y-intercepts for the following linear equations:
**** Remember: set y = 0 to find the x-intercept, and x = 0 to find the y-intercept.**
Algebra 1 Notes SOL A.6 (4.3) Graphing Using Intercepts Mrs. Grieser
2
Once you have the intercepts of a linear equation, you can easily graph the line by plotting and connecting the points. Example: Graph the equation x + 2y = 4. Step 1: Find the intercepts. x-intercept: x + 2(0) = 4 x = 4 x-intercept = (4, 0)
y-intercept: 0 + 2y = 4 y = 2 y-intercept = (0, 2) Step 2: Plot the points and connect them. See the figure to the right.
Example: Find the intercepts from a graph. Given the graph at the right, we can see that the line crosses the x-axis at point (2, 0), and it crosses the y-axis at (0, -1).
Example: Word Problem You borrow $1800 from your parents. To repay the debt, you give them $150 per month. Your debt d (in dollars) is given by the function d = 150t – 1800, where t represents time (in months). a) Find the intercepts of the graph. t-intercept: 150t – 1800 = 0 150t = 1800 t = 12 t-intercept = (12, 0)
d-intercept: 150(0) – 1800 = d d = - d-intercept = (0, -1800)
b) Graph the function and identify the domain and range.