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Organic Chemistry Final Exam - CHEM 231A (December 13, 2001), Exams of Organic Chemistry

The final exam questions for organic chemistry chem 231a, held on december 13, 2001. The exam covers topics such as base identification, basicity ordering, nucleophilicity, reaction prediction, and stereochemistry. Students are required to explain their reasoning and provide mechanisms for certain questions.

Typology: Exams

Pre 2010

Uploaded on 08/18/2009

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Name:
Organic Chemistry - CHEM 231A
Final Exam
December 13, 2001
1. Consider the following molecules: (30 points)
1a. What is a base? What factors are involved in making a base a strong base? (8 points)
1b. Circle the MOST basic atom(s) for each molecule. (2 points)
1c. Arrange the molecules in the order from most basic to least basic. (4 points)
Most Basic ____ > ____ > ____ > ____ > ____ Least Basic
1d. Thoroughly explain your reasoning behind the ordering of the molecules. Include a discussion
of why the characteristics for each specific molecule help us understand the basicity for EACH
molecule. Discussing them in order may be appropriate. (10 points)
1e. Which of the above molecules are also nucleophiles? Explain Briefly. (6 points)
O
O
N
Br O
O
AB
CDE
pf3
pf4
pf5

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Name:

Organic Chemistry - CHEM 231A

Final Exam December 13, 2001

  1. Consider the following molecules: (30 points)

1a. What is a base? What factors are involved in making a base a strong base? (8 points)

1b. Circle the MOST basic atom(s) for each molecule. (2 points)

1c. Arrange the molecules in the order from most basic to least basic. (4 points)

Most Basic ____ > ____ > ____ > ____ > ____ Least Basic

1d. Thoroughly explain your reasoning behind the ordering of the molecules. Include a discussion of why the characteristics for each specific molecule help us understand the basicity for EACH molecule. Discussing them in order may be appropriate. (10 points)

1e. Which of the above molecules are also nucleophiles? Explain Briefly. (6 points)

O

O

N Br (^) O

O

A B C^ D E

  1. Predict the MAJOR product for the following reactions and briefly explain your answer. (5 @ 8 pts = 40 points)

2a.

OH

H 2 SO 4 / CH 3 OH Reflux

2b.

O S

O

O

NaCN (1 eq) / Et 2 O

2c.

O - K +

CH 2 Cl 2

[1R,2R,4S]1-bromo-2-ethyl-4-methylcyclohexane

2d.

  1. Na / Et 2 O
  2. CH 3 Br

[4R,5S]3-isopropyl-2,5-dimethyl hept-2-en-4-ol

2e.

Br 2 / hν

3f. If the reaction is changed to investigate the following molecule, only one racemic product is formed:

Cl 2 / hν One Racemic Product

What is the product? Explain briefly why it is the only product formed. (7 points)

  1. Consider the following problem: (40 points)

O

Optical Rotation = + 75

H 2 O Basic or Acidic Conditions

HO (^) OH

4a. The optical rotation of pure [2R] 2-methyl butanoxirane is +98º. What is the optical purity of the starting material in the above reaction? How much of each enantiomer is present? Show your work. (7 points)

4b. The above reaction occurs rapidly at pH 3 and at pH 10, but not at all at pH 7. Explain these results. (8 points)

4c. If the reaction is conducted using oxygen-18 water instead of normal oxygen-16 water, the product formed under acidic conditions (compound A) is different than the product formed under basic conditions (Compound B). Both molecules have the same molecular formula. What are the two different products? (8 points)

4d. Write a mechanism that accounts for the formation of each product. (12 points)

4e. What is the optical purity for the product formed under acidic conditions? For the product formed under basic conditions? Explain briefly. (5 points)

O

Optical Rotation = + 75

H 218 O

Acidic Conditions

O

Optical Rotation = + 75

H 218 O

Basic Conditions

Compound A C 5 H 12 O 18 O

Compound B C 5 H 12 O 18 O