Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Engineering Mathematics keynotes, Summaries of Engineering Mathematics

A list of topics related to engineering mathematics, including basic calculus, ordinary differential equations, vector calculus, linear algebra, probability and statistics, and complex calculus. The document also includes examples and properties of limits, as well as rules for differentiation. It is a useful resource for engineering students who need to design against static load.

Typology: Summaries

2022/2023

Available from 02/15/2023

amloop
amloop 🇮🇳

1 document

1 / 65

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
EngineeringEngineering
MathematicsMathematics
Engineering
Mathematics
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19
pf1a
pf1b
pf1c
pf1d
pf1e
pf1f
pf20
pf21
pf22
pf23
pf24
pf25
pf26
pf27
pf28
pf29
pf2a
pf2b
pf2c
pf2d
pf2e
pf2f
pf30
pf31
pf32
pf33
pf34
pf35
pf36
pf37
pf38
pf39
pf3a
pf3b
pf3c
pf3d
pf3e
pf3f
pf40
pf41

Partial preview of the text

Download Engineering Mathematics keynotes and more Summaries Engineering Mathematics in PDF only on Docsity!

EngineeringEngineering

MathematicsMathematics

Engineering

Mathematics

Design Against Static Load

1. Basic Calculus ....................................................................................................................... 1 .1 – 1. 16

2. Ordinary Differential Equation ............................................................................................. 1 .17 – 1. 25

3. Vector Calculus ..................................................................................................................... 1.26 – 1. 34

4. Linear Algebra ...................................................................................................................... 1.35 – 1.

5. Probability and Statistics ...................................................................................................... 1.47 – 1. 58

6. Complex Calculus ................................................................................................................. 1.59 – 1.

ENGINEERING

MATHEMATICS

INDEX

Fig. 1.

(b) Concept of differentiability

A continuous function f ( x ) is said to be differentiable at x = a , if 𝑙𝑖𝑚

𝑥→𝑎

𝑓(𝑥)−𝑓(𝑎)

𝑥−𝑎

exists, that is, RHL and LHL exist at a point

under consideration in 𝑓 (𝑥).

𝑥=𝑎

𝑥→𝑎

𝑓(𝑥)−𝑓(𝑎)

𝑥−𝑎

𝑓 (𝑎) = 𝑡𝑎𝑛 𝜃, where 𝜃 is the angle made by the tangent to the curve at x=a with x – axis.

(c) Some Standard Derivatives

(i)

𝑑

𝑑𝑥

𝑛

𝑛− 1

(ii)

𝑑

𝑑𝑥

(iii)

𝑑

𝑑𝑥

(iv)

𝑑

𝑑𝑥

2

(v)

𝑑

𝑑𝑥

2

(vi)

𝑑

𝑑𝑥

(vii)

𝑑

𝑑𝑥

(viii)

𝑑

𝑑𝑥

− 1

1

√ 1 −𝑥

2

(ix)

𝑑

𝑑𝑥

− 1

− 1

√ 1 −𝑥

2

(x)

𝑑

𝑑𝑥

− 1

1

1 +𝑥

2

(xi)

𝑑

𝑑𝑥

− 1

− 1

1 +𝑥

2

(xii)

𝑑

𝑑𝑥

− 1

1

|𝑥|√𝑥

2

− 1

(xiii)

𝑑

𝑑𝑥

− 1

− 1

|𝑥|

√ 𝑥

2

− 1

; | x | > 1

(xiv)

𝑑

𝑑𝑥

𝑎

1

𝑥 𝑙𝑜𝑔 𝑒

𝑎

(xv)

𝑑

𝑑𝑥

𝑒

1

𝑥

(xvi)

𝑑

𝑑𝑥

𝑥

𝑥

𝑒

(xvii)

𝑑

𝑑𝑥

𝑥

𝑥

(xviii)

𝑑

𝑑𝑥

|𝑥|

𝑥

(xix)

𝑑

𝑑𝑥

𝑥

𝑥

𝑒

(xx)

𝑑

𝑑𝑥

(d) Product rule of differentiation

(i)

𝑑

𝑑𝑥

(ii) 𝑑(𝑢𝑣𝑤) = 𝑢𝑣𝑤 + 𝑢𝑣 𝑤 + 𝑢 𝑣𝑤

(e) Quotient rule of differentiation

𝑑

𝑑𝑥

𝑓(𝑥)

𝑔(𝑥)

𝑔(𝑥).𝑓 (𝑥)−𝑓(𝑥).𝑔 (𝑥)

(𝑔

( 𝑥

) )

2

(f) Logarithmic differentiation:

Taking log might help in differentiation of a function. For example if

u

y = v

then we can take log both side and

differentiable to get

dy

dx

(g) Differentiation in parametric from :

If we write x and y in term of find variable ‘t’ that is x = f(t), y = (t), then

dy dy dt

dx dx dt

(h) Greatest Integer function / step function / integer part function

𝑓(𝑥) = [𝑥] = 𝑛, ∀ 𝑛 ≤ 𝑥 < 𝑛 + 1 where, 𝑛 ∈ 𝑍

𝑥→𝑎

[𝑥] = ∄ if a is an integer ( ∄ = do not exist)

L.H.L. = 𝑙𝑖𝑚

𝑥→𝑎

[𝑥] = 𝑎 − 1
R.H.L. = 𝑙𝑖𝑚

𝑥→𝑎

[𝑥] = 𝑎

(j) Some Standard Limits

(i) 𝑙𝑖𝑚

𝑥→ 0

𝑠𝑖𝑛 𝑥

𝑥

(ii) 𝑙𝑖𝑚

𝑥→ 0

𝑡𝑎𝑛 𝑥

𝑥

(iii) 𝑙𝑖𝑚

𝑥→ 0

1 −𝑐𝑜𝑠 𝑎𝑥

𝑥

2

𝑎

2

2

(iv) 𝑙𝑖𝑚

𝑥→

𝑠𝑖𝑛 𝑥

𝑥

(v) 𝑙𝑖𝑚

𝑥→

𝑐𝑜𝑠 𝑥

𝑥

(vi) 𝑙𝑖𝑚

𝑥→ 0

𝑏/𝑥

𝑎𝑏

(vii) 𝑙𝑖𝑚

𝑥→

𝑎

𝑥

𝑏𝑥

𝑎𝑏

(viii) 𝑙𝑖𝑚

𝑥→ 0

𝑎

𝑥

+𝑏

𝑥

2

1 /𝑥

(ix) 𝑙𝑖𝑚

𝑥→ 0

1

𝑥

  • 2

𝑥

  • 3

𝑥

+....+𝑛

𝑥

𝑛

1 /𝑥

𝑛

(x) 𝑙𝑖𝑚

𝑥→ 0

𝑎

𝑥

− 1

𝑥

𝑒

𝑥→ 0

𝑒

𝑥

− 1

𝑥

(xi) 𝑙𝑖𝑚

𝑥→ 0

1

𝑥

1.2 Mean Value Theorems

1.2.1 Lagrange’s Mean Value Theorem (LMVT):

If 𝑓(𝑥) is continuous in [a, b] and it is differentiable in (a, b) then ∃ at least one point ‘c’ such that c  (a, b) and

Here 𝑓 (𝑐) slope of tangent to f ( x ) at x = c.

Tangent at x = c is parallel to the line connecting the points A and B

Fig.1. 3. LMVT

1.2.2 Rolle’s Mean Value Theorem

If 𝑓(𝑥) is continuous in [ a , b ] and differentiable in (a, b) and f ( a ) = f ( b ) then  at least one-point c  ( a , b ) such that 𝑓 (𝑐) = 0.

Fig. 1. 4. Rolle’s mean value

1.2.3 Cauchy’s Mean Value Theorem

If f ( x ) and g ( x ) are continuous in [ a , b ] and differentiable in ( a , b ) then  at least one value of ‘c’ such that c  ( a , b ) and

𝑔

( 𝐶

)

𝑓

( 𝐶

)

𝑔

( 𝑏

) −𝑔

( 𝑎

)

𝑓

( 𝑏

) −𝑓

( 𝑎

)

1.3 Increasing and Decreasing Functions

1.3.1 Increasing Functions

A function f ( x ) is said to be increasing, if 𝑓

1

2

1

2

Or

A function f ( x ) is said to be increasing, if f ( x ) increases as x increases.

For a function 𝑓(𝑥) to be increasing at the point x=a, 𝑓

Example:

e

x

, log e

x → Monotonically increasing functions

sin x in (0, /2) → non-monotonic functions

1.3.2 Decreasing Functions

A function f ( x ) is said to be a decreasing function, if 𝑓

1

2

1

2

A function 𝑓

is said to be decreasing function, if 𝑓

decreases as x increases.

Example: 𝑒

−𝑥

→Monotonically decreasing function, sin 𝑥 in (

𝜋

2

1.4. Concept of Maxima and Minima

Let f ( x ) be a differentiable function, then to find the maximum (or) minimum of f ( x ).

(1) Find f ( x ) and equate to zero.

  • Finding the expansion of e

x

about x = 0

𝑥

0

𝑥

0

𝑥

1

1!

2

1

2!

3

1

3!

𝑥

𝑥

1!

𝑥

2

2!

𝑥

3

3!

1.6 Integral Calculus

If F ( x ) is anti-derivative of f ( x ). That is, continuous and differentiable in ( a , b ), then we write ∫

𝑥=𝑏

𝑥=𝑎

𝐹(𝑎). Here f ( x ) is integrand

If 𝑓(𝑥) > 0 ∀𝑎 ≤ 𝑥 ≤ 𝑏, 𝑡ℎ𝑒𝑛 ∫

𝑏

𝑎

represents the shaded area in the given figure.

y = f ( ) x

x=a x=b

Fig.1. 6. Integration of continuous function

1.6.1 Mean Value Theorem of Integration

If f (x) is continuous in [ a , b ] and differentiable in ( a , b ) then ‘’ atleast one-point c ( a , b ) such that

∫ 𝑓

( 𝑥

)

𝑏

𝑎

𝑑𝑥

( 𝑏−𝑎

)

Fig. 1. 7. Mean value of integration

1.7. Newton-Leibnitz Rule

If f ( x ) is continuously differentiable and ( x ), ( x ) are two functions for which the 1

st

derivative exists, then

𝜓(𝑥)

𝜙(𝑥)

Example:

𝑑

𝑑𝑥

𝑥

2

𝑥

2

2

1.8. Some Standard Integrals

𝑛

𝑥

𝑛+ 1

𝑛+ 1

1

𝑥

𝑒

𝑓 (𝑥)

𝑓(𝑥)

𝑒

𝑠𝑖𝑛 𝑥

𝑐𝑜𝑠 𝑥

𝑒

𝑒

𝑐𝑜𝑠 𝑥

𝑠𝑖𝑛 𝑥

𝑒

𝑒

𝑠𝑒𝑐 𝑥(𝑠𝑒𝑐 𝑥+𝑡𝑎𝑛 𝑥)

(𝑠𝑒𝑐 𝑥+𝑡𝑎𝑛 𝑥)

𝑒

𝑒

𝑥

𝑎

𝑥

𝑙𝑜𝑔 𝑒

𝑎

1

𝑥.𝑙𝑜𝑔 𝑒

𝑎

𝑎

𝑥

𝑒

𝑥

1

2

2

𝑓

( 𝑥

)

√𝑓(𝑥)

15. If f ( x ), g ( x ) are two functions. that are differentiable, then

𝑑𝑥 − ∫[𝑓 ′
]𝑑𝑥 + 𝐶

Fig.1. 8. Length of the curve

(b) The length of the arc of the curve x = f ( ) y between the points where y = a and y = b, is

2

b

a

dx

s dy

dy

(c) The length of the arc of the curve x = f t ( ), y = f t ( ) between the points where t = a and t = b, is

2 2

b

a

dx dy

s dt

dt dt

(d) The length of the arc of the curve r = f ( ), between the points where  =  and  = , is

2

2

dr

s r d

d

 

 

= +   

 

    

 

1.11 Surface Area of Solid generated by revolving a curve about a fixed axis.

Elemental Surface Area

𝑑𝐴 = 2 𝜋𝑦 × 𝑑𝑠 = 2 𝜋𝑦𝑑𝑠

 Total surface area = A = ∫

𝑥=𝑏

𝑥=𝑎

𝑑𝑦

𝑑𝑥

2

Fig.1. 9. Surface area

1.12 Volume of the solid

A. The volume of the solid obtained by revolving the curve y = f ( x ) between the lines x = a and x = b is given by

2

𝑥=𝑏

𝑥=𝑎

Fig. 1. 10. Volume of the solid

B. Revolution about the y-axis. Interchanging x and y in the above formula, we see that the volume of the solid generated

by the revolution, about y-axis, of the area, bounded by the curve

x = f ( ), y the y-axis and the abscissa y = a, y = b is

2

b

a

 x dy

.

1.13 Gamma Function

The integral ∫

−𝑥

𝑛− 1

0

𝑑𝑥, (𝑛 > 0 ) is called Gamma function of n. It is denoted by Γ𝑛 = ∫

−𝑥

𝑛− 1

0

Note :

/

0

sin cos

m n

m n

x xdx

m n

Where (x) is called the gamma function.

1.13.1 Properties of Gamma Function

(i) Γ𝑛 = (𝑛 − 1 )! (ii) Γ(𝑛 + 1 ) = (𝑛)!

(iii) Γ(𝑛 + 1 ) = 𝑛Γ𝑛 (iv) Γ (

1

2

1.14 Beta Function

The function  ( m , n ) = ∫ 𝑥

𝑚− 1

𝑛− 1

1

0

𝑑𝑥 ( m , n > 0) is called  function of m and n.

Example: 𝑓

3

2

2

3

3

2

2

3

3

3

2

2

3

3

is a homogenous function of degree ‘3’.

(d) Euler’s Theorem

If f ( x , y ) is a homogeneous function of degree ‘ n ’ then

(i) 𝑥.

𝜕𝑓

𝜕𝑥

𝜕𝑓

𝜕𝑦

(ii) 𝑥

2

𝜕

2

𝑓

𝜕𝑥

2

𝜕

2

𝑓

𝜕𝑥𝜕𝑦

2

𝜕

2

𝑓

𝜕𝑦

2

If f ( x , y ) = g ( x , y ) + h ( x , y ) + ( x , y ) where g ( x , y ), h ( x , y ) and ( x , y ) are homogenous functions of degrees m, n and

p respectively, then

𝜕𝑓

𝜕𝑥

𝜕𝑓

𝜕𝑦

2

𝜕

2

𝑓

𝜕𝑥

2

𝜕

2

𝑓

𝜕𝑥𝜕𝑦

2

𝜕

2

𝑓

𝜕𝑦

2

(e) Total derivative:

(i) If u = f(x, y) and if x = (t), y = v(t) then..

du u dx u dy

dt x dt y dt

(ii) If u be a function of x and y, where y is a function of x, then.

du u u dy

dx x y dx

(iii) If u = f(x, y) and

1 1 2

x = f ( , t t )

and

2 1 2

y = f ( t , t ),

then

1 1 1

u u x u y

t x t y t

and

2 2 2

u u x u y

t x t y t

(iv) If x and y are connected by an equation of the form f(x, y) = 0, then

dy f x

dx f y

(f) Concept of Maxima and Minima in Two Variables

If f ( x , y ) is a two-variable differentiable function, then to find the maxima (or) minima.

Step-1: Calculate 𝑝 =

𝜕𝑓

𝜕𝑥

and 𝑞 =

𝜕𝑓

𝜕𝑦

and equate p = 0, q = 0

Let ( x 0

, y 0

) be a stationary point.

Step- 2 : Calculate r , s , t where 𝑟 =

𝜕

2

𝑓

𝜕𝑥

2

(𝑥

0

,𝑦

0

)

𝜕

2

𝑓

𝜕𝑥.𝜕𝑦

(𝑥

0

,𝑦

0

)

𝜕

2

𝑓

𝜕𝑦

2

(𝑥

0

,𝑦

0

)

Case (i): If 𝑟𝑡 − 𝑠

2

0 and r > 0, then the function f ( x , y ) has minimum at ( x 0

, y 0

) and the minimum value is f ( x 0

, y 0

Case (ii): If 𝑟𝑡 − 𝑠

2

0 and r < 0, then the function f ( x , y ) has maximum at ( x 0

, y 0

) and the maximum value is

f ( x 0

, y 0

Case (iii): If 𝑟𝑡 − 𝑠

2

< 0 ; then we cannot comment on the existence of maxima and minima.

Such stationary points where 𝑟𝑡 − 𝑠

2

= 0 are called saddle points.

(g) Concept of Constraint Maxima and Minima (Method of Lagrange’s unidentified multipliers).

If f ( x , y , z ) is a continuous and differentiable function, such that the variables x , y and z are related/constrained by the

equation ( x , y , z ) = C then to calculate the extreme value of f ( x , y , z ) using Lagrange’s Method of unidentified multipliers.

Step-1: Form the function F ( x , y , z ) = f ( x , y , z ) + {( x , y , z ) – C}, where 𝜆 is a multiplier.

Step-2: Calculate

𝜕𝐹

𝜕𝑥

𝜕𝐹

𝜕𝑦

and

𝜕𝐹

𝜕𝑧

and equate them to zero

Step- 3 : Equate the values of  from the above 3 equations and obtain the relation between the variables x , y and z.

Step- 4 : Substitute the relation between x , y and z in ( x , y , z ) = C and get the values of x , y , z. Let they be ( x 0

, y 0

, z 0

Step-5: Calculate f ( x 0

, y 0

, z 0

The value f ( x 0

, y 0

, z 0

) is the extreme value of f ( x , y , z ).

(h) Multiple Integrals

If f (x, y ) is continuous and differentiable at every point within a region ‘ R ’ bounded by some curves is given by

𝑅

If there is a double integral,

𝑦=𝜓(𝑥)

𝑦=𝜙(𝑥)

𝑥=𝑏

𝑥=𝑎

[Let ( x ) > ( x )]

Then I = area of the region bounded by the curves, y = ( x ); y = ( x ), x = a and x = b if f ( x , y ) = 1

Value of x – co-ordinate of centroid of the region bounded by y = ( x ); y = ( x ); x = a , x = b if f ( x , y ) = x

(i) Change of Orders of Integration

𝑦=𝜓(𝑥)

𝑦=𝜙(𝑥)

𝑥=𝑏

𝑥=𝑎

𝑥= (𝑦)

𝑥=𝑔(𝑦)

𝑦=𝑑

𝑦=𝑐

In change of order of Integration, the order of the Integrating variables changes and the limits as well.

Note : When limits are constants, the order of integration does not matter,

y d y d x b x b

y c x a x a y c

f x y dxdy f x y dydx

= = = =

= = = =

   

1.17 Jacobian of the Transformation

(i) The Jacobian of the transformation, ( )

1 2

x = f u v , , y = f ( , ) u v is defined as,

u v

u v

x x x y

J

u v y y

ORDINARY DIFFERENTIAL

EQUATION

2.1 Differential Equation

The equation involving differential coefficients is called a Differential Equation (DE).

2

𝑑𝑦

𝑑𝑥

2

𝜕

2

𝑇

𝜕𝑥

2

𝜕𝑇

𝜕𝑥

2

𝜕

2

𝑢

𝜕𝑥

2

2

𝜕

2

𝑢

𝜕𝑦

2

2.1.1 Ordinary Differential Equations (ODE)

The DEs involving only one independent variable is called ordinary differential equation.

Example:

2

𝑑𝑦

𝑑𝑥

2

−𝑥

𝑑𝑦

𝑑𝑥

2

𝑥

2.1.2 Partial Differential Equations

The DEs involving two (or) more independent variables are called Partial Differential Equations (PDEs).

Example:

𝜕

2

𝑢

𝜕𝑥

2

2

𝜕

2

𝑢

𝜕𝑡

2

𝜕

2

𝑢

𝜕𝑥

2

𝜕

2

𝑢

𝜕𝑦

2

1

𝐾

𝜕𝑢

𝜕𝑡

𝜕

2

𝑢

𝜕𝑥

2

𝜕

2

𝑢

𝜕𝑦

2

2.1.3 Order of a Differential Equation

The order of the highest derivative that occurs in a DE is called order of a DE.

Example:

𝑑

2

𝑦

𝑑𝑥

2

𝑑𝑦

𝑑𝑥

3

− 𝑦 = 0 → Order = 2

𝑑𝑦

𝑑𝑥

𝑑

2

𝑦

𝑑𝑥

2

𝑑

3

𝑦

𝑑𝑥

3

2

𝑥

→ Order = 3

𝜕

2

𝑢

𝜕𝑥

2

1

𝐶

2

𝜕

2

𝑢

𝜕𝑡

2

→ Order = 2

𝜕

2

𝑢

𝜕𝑥

2

1

𝛼

𝜕𝑢

𝜕𝑡

→ Order = 2

2.1.4 Degree of a Differential Equation

The Degree of the highest order derivative that occurs in a DE, when the DE is free from fractional (or) radical powers.

Example:

(1) The Degree of the DE (

𝑑

2

𝑦

𝑑𝑥

2

1

𝑑𝑦

𝑑𝑥

3

− 3 𝑦 = 0 is 1.

(2) The Degree of the DE (

𝑑

2

𝑦

𝑑𝑥

2

1

𝑑𝑦

𝑑𝑥

3

  • 4 𝑦 = 0 is 2

𝑑

2

𝑦

𝑑𝑥

2

2

𝑑𝑦

𝑑𝑥

3

2

𝑑

2

𝑦

𝑑𝑥

2

2

𝑑𝑦

𝑑𝑥

3

(3) It is not possible every time that we can find the degree of a given differential equation. The degree of any differential

equation can be found, when it is in the form of a polynomial; otherwise, the degree cannot be defined.

Example degree of the DE is not defined

2 2

2 2

cos 5

d y d y

x

dx dx

2.2. Formation of Differential Equations

If a solution y = f ( x ) contains n arbitrary constants in it, then differentiate y for n times and calculate 𝑦 , 𝑦", 𝑦 ′′′ ,.... 𝑦

(𝑛)

So, from

the ( n + 1) equations available, try to eliminate the arbitrary constants in y = f ( x )

  • The different equation formed for the solution, 𝑦 = 𝐶 1

𝐾 1

𝑥

2

𝐾 2

𝑥

where C 1

, C

2

are arbitrary constants is

𝑑

2

𝑦

𝑑𝑥

2

1

2

𝑑𝑦

𝑑𝑥

1

2

  • If the solution is 𝑦 = 𝐶

1

𝐾

1

𝑥

2

𝐾

2

𝑥

3

𝐾

3

𝑥

where C 1

, C

2

, C

3

are arbitrary constants, then the DE is 𝑦′′′ −

1

2

3

1

2

2

3

3

1

1

2

3

2.2.1 First Order DE

The general form of a 1

st

order DE is given by

𝑑𝑦

𝑑𝑥

If

𝑑𝑦

𝑑𝑥

𝑀(𝑥,𝑦)

𝑁(𝑥,𝑦)