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Series-A 2 KAU-
MECHANICAL ENGINEERING
PAPER - --- I
1. The product of mass and velocity is known as (a) Impulse (b) Momentum (c) Power (d) Work 2. The co-efficient of friction depends on (a) Area of contact (b) Shape of surfaces (c) Strength of surfaces (d) Nature of surfaces 3. Angle of friction is the (a) Angle between normal reaction and the resultant of normal reaction and the limiting frictional force (b) Ratio of limiting friction and normal reaction (c) Ratio of static and dynamic friction (d) None of the above 4. A machine is one that (a) transfer motion (b) does useful work (c) have relative motion between links (d) have a number of members 5. The ratio of linear stress to the linear strain is called (a) Modulus of rigidity (b) Modulus of elasticity (c) Bulk modulus (d) Poisson’s ratio 6. Limiting force of friction is defined as the frictional force which exists when a body (a) is moving with maximum velocity (b) is stationary (c) just begins to slide over the surface (d) None of these 7. If the bulk modulus is K, modulus of Elasticity is E and Poisson’s ratio is
m
, then which
of the following is true?
(a) E = 3K (^)
m (b)^ E = 3K^
m
(c) E = 3K
m (d)^ E = 3K^
m
8. The value of Poisson’s ratio is always (a) more than 1 (b) 1 (c) less than 1 (d) None of these 9. The velocity ratio of Weston’s differential pulley is : (Where R : Radius of bigger pulley r : Radius of smaller pulley)
(a)
2R
R – r (b)^
2r R – r (c)^
R
R – r (d)^
R
2R – r
10. In first system of pulley, the mechanical advantage is equal to (where n : no. of pulleys) (a) 2 n–1^ (b) 2 n^ (c) n (d) 2 n^ – 1 11. Bow’s notation is used to indicate (a) forces (b) moment (c) pressure (d) velocity 12. In thin cylindrical shell, the value of circumferential stress as compared to the longitudinal stress is (a) Equal (b) Double (c) Triple (d) None of these
KAU-05 3 Series-A
´ÖîÛêú×®ÖÛú»Ö †×³ÖμÖÓ¡ÖÞÖ
¯ÖÏ¿®Ö-¯Ö¡Ö---- I
1. ¦ü¾μÖ´ÖÖ®Ö ¾Ö ÝÖ×ŸÖ Ûêú ÝÖãÞÖ®Ö ÛúÖê ÛúÆüŸÖê Æïü
(a) †Ö¾ÖêÝÖ (b) ÃÖÓ¾ÖêÝÖ (c) ¿Ö׌ŸÖ (d) ÛúÖμÖÔ
2. ‘ÖÂÖÔÞÖ ÛúÖ ÝÖãÞÖÖÓÛú ×®Ö³ÖÔ¸ü ÆüÖêŸÖÖ Æîü
(a) ÃÖ´¯ÖÛÔú õÖê¡Ö ¯Ö¸ü (b) ÃÖŸÖÆüÖë Ûêú †ÖÛúÖ¸ü ¯Ö¸ü
(c) ÃÖŸÖÆüÖë Ûúß ÃÖÖ´Ö£μÖÔ ¯Ö¸ü (d) ÃÖŸÖÆüÖë Ûúß ¯ÖÏÛéú×ŸÖ ¯Ö¸
3. ‘ÖÂÖÔÞÖ ÛúÖêÞÖ ÆüÖêŸÖÖ Æîü
(a) †×³Ö»Ö´²Ö ¯ÖÏןÖ×ÛÎúμÖÖ †Öî¸ü “Ö¸ü´Ö ‘ÖÂÖÔÞÖ ²Ö»Ö ¾Ö †×³Ö»Ö´²Ö ¯ÖÏןÖ×ÛÎúμÖÖ Ûúß ¯Ö׸üÞÖÖ´Öß ¯ÖÏןÖ×ÛÎúμÖÖ Ûêú ²Öß“Ö ÛúÖ ÛúÖêÞÖ
(b) “Ö¸ü´Ö ‘ÖÂÖÔÞÖ ²Ö»Ö †Öî¸ü †×³Ö»Ö´²Ö ¯ÖÏןÖ×ÛÎúμÖÖ ÛúÖ †®Öã¯ÖÖŸÖ
(c) ãÖîןÖÛú †Öî¸ü ÝÖןÖÛú ‘ÖÂÖÔÞÖ ÛúÖ †®Öã¯ÖÖŸÖ
(d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
4. ´Ö¿Öß®Ö ¾ÖÆü Æîü •ÖÖê
(a) ÝÖ×ŸÖ Ã£ÖÖ®ÖÖ®ŸÖ׸üŸÖ Ûú¸üŸÖß Æîü … (b) ˆ¯ÖμÖÖêÝÖß ÛúÖμÖÔ Ûú¸üŸÖß Æîü …
(c) Ø»ÖÛúÖë Ûêú ´Ö¬μÖ ¯Ö¸üïָü ÝÖ×ŸÖ ÆüÖêüŸÖß Æîü … (d) Ûú‡Ô Ø»ÖÛú (´Öê´²Ö¸ü) ÆüÖêŸÖê Æïü …
5. ¸êüÜÖßμÖ ¯ÖÏ×ŸÖ²Ö»Ö ‹¾ÖÓ ¸êüÜÖßμÖ ×¾ÖÛéú×ŸÖ ÛúÖ †®Öã¯ÖÖŸÖ ÛúÆü»ÖÖŸÖÖ Æîü
(a) ¥üœÌüŸÖÖ ÝÖãÞÖÖÓÛú (b) ¯ÖÏŸμÖÖã֟ÖÖ ÝÖãÞÖÖÓÛú
(c) †ÖμÖŸÖ®Ö ¯ÖÏŸμÖÖã֟ÖÖ ÝÖãÞÖÖÓÛú (d) ¯¾ÖÖÃÖÖë †®Öã¯ÖÖŸÖ
6. ÃÖß´ÖÖÓŸÖ ‘ÖÂÖÔÞÖ ²Ö»Ö ¯Ö׸ü³ÖÖ×ÂÖŸÖ Æîü, ¾ÖÆü ‘ÖÂÖÔÞÖ ²Ö»Ö Ûúß †¾ÖãÖÖ ×•ÖÃÖ ¯Ö¸ü ‹Ûú د֛ü
(a) ÃÖ¾ÖÖÔ׬ÖÛú ¾ÖêÝÖ ÃÖê ‘Öæ´ÖŸÖÖ Æîü … (b) ×ãָü ÆüÖêŸÖÖ Æîü …
(c) ÃÖŸÖÆü ¯Ö¸ü ÃÖ¸üÛú®ÖÖ ¿Öãºþ Ûú¸üŸÖÖ Æîü … (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà …
7. μÖפü K †ÖμÖŸÖ®Ö ¯ÖÏŸμÖÖã֟ÖÖ ÝÖãÞÖÖÓÛú, E ¯ÖÏŸμÖÖã֟ÖÖ ÝÖãÞÖÖÓÛú ŸÖ£ÖÖ ¯¾ÖÖÃÖÖë †®Öã¯ÖÖŸÖ
m Æîü, ŸÖÖê ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ÃÖÆüß Æîü^?
(a) E = 3K
m (b)^ E = 3K^
m
(c) E = 3K (^)
m (d)^ E = 3K^
m
8. ¯¾ÖÖÃÖÖë †®Öã¯ÖÖŸÖ ÛúÖ ´ÖÖ®Ö ÃÖ¤îü¾Ö ÆüÖêŸÖÖ Æîü
(a) ‹Ûú ÃÖê †×¬ÖÛú (b) ‹Ûú (c) ‹Ûú ÃÖê Ûú´Ö (d) ‡®Ö´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
9. ¾ÖêÙü®Ö Ûúß ¾μÖÖÃÖÖÓŸÖ¸üß ×‘Ö¸ü®Öß ÛúÖ ¾ÖêÝÖÖ®Öã¯ÖÖŸÖ ÆüÖêŸÖÖ Æîü
(•ÖÆüÖÑ R : ²Ö›Ìüß ×‘Ö¸ü®Öß Ûúß ×¡Ö•μÖÖ Æîü;
r : ”ûÖê™üß ×‘Ö¸ü®Öß Ûúß ×¡Ö•μÖÖ Æîü)
(a)
2R
R – r (b)^
2r R – r (c)^
R
R – r (d)^
R
2R – r
10. ¯ÖÏ£Ö´Ö ×‘Ö¸ü®Öß ŸÖ®¡Ö ´Öë μÖÖ×®¡ÖÛú »ÖÖ³Ö ×®Ö´®Ö Ûêú ²Ö¸üÖ²Ö¸ü ÆüÖêŸÖÖ Æîü :
(•ÖÆüÖÑ ‘n’ בָü®Öß Ûúß ÃÖÓÜμÖÖ Æîü)
(a) 2 n–1^ (b) 2 n^ (c) n (d) 2 n^ – 1
11. ²ÖÖê (Bow’s) ÃÖÓÛêúŸÖ®Ö ×®Ö´®Ö ‡Ó×ÝÖŸÖ Ûú¸üŸÖÖ Æîü :
(a) ²Ö»Ö (b) †Ö‘ÖæÞÖÔ (c) ¤üÖ²Ö (d) ¾ÖêÝÖ
12. ¯ÖŸÖ»Öê ²Öê»Ö®ÖÖÛúÖ¸ü ÜÖÖê»Ö ´Öë ˆŸ¯Ö®®Ö ¯Ö׸ü¬ÖßμÖ ¯ÖÏ×ŸÖ²Ö»Ö ÛúÖ ´ÖÖ®Ö †®Öã¤îü¬μÖÔ ¯ÖÏ×ŸÖ²Ö»Ö Ûúß ŸÖã»Ö®ÖÖ ´Öë ÆüÖêŸÖÖ Æîü
(a) ²Ö¸üÖ²Ö¸ü (b) ¤üÖê ÝÖã®ÖÖ (c) ŸÖß®Ö ÝÖã®ÖÖ (d) ‡®Ö´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
KAU-05 5 Series-A
13. ÃÖ¯Öá ‘ÖÂÖÔÞÖ ÛúÖ ´ÖÖ®Ö ²Öê»Ö®Ö ‘ÖÂÖÔÞÖ Ûúß ŸÖã»Ö®ÖÖ ´Öë ÆüÖêŸÖÖ Æîü
(a) †×¬ÖÛú (b) Ûú´Ö (c) ²Ö¸üÖ²Ö¸ü (d) ¤üÖê ÝÖã®ÖÖ
14. †Ö‘ÖæÞÖÔ Ûúß ‡ÛúÖ‡Ô ÆüÖêŸÖß Æîü
(a) ®μÖæ™ü®Ö/´Öß™¸ü (b) ®μÖæ™ü®Ö-´Öß™¸ü (c) ®μÖæ™ü®Ö/´Öß™ü¸ü^2 (d) ®μÖæ™ü®Ö-´Öß™ü¸ü/ÃÖêÛúÞ›ü
15. ÃÖß´ÖÖÓŸÖ ‘ÖÂÖÔÞÖ ²Ö»Ö ¾Ö ÃÖÖ´ÖÖ®μÖ ¯ÖÏןÖ×ÛÎúμÖÖ ÛúÖ †®Öã¯ÖÖŸÖ ÆüÖêŸÖÖ Æîü
(a) ‘ÖÂÖÔÞÖ ÝÖãÞÖÖÓÛú (b) ‘ÖÂÖÔÞÖ ÛúÖ ÛúÖêÞÖ
(c) ׸ü¯ÖÖê•Ö (Repose) ÛúÖêÞÖ (d) ‘ÖÂÖÔÞÖ ¯ÖÏןָüÖê¬Ö
16. ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ÃÖß ‡ÛúÖ‡Ô ‰ú•ÖÖÔ Ûúß ‡ÛúÖ‡Ô ®ÖÆüà Æîü?
(a) ®μÖæ™ü®Ö-´Öß™ü¸ü (b) ×Ûú»ÖÖê Ûîú»ÖÖê¸üß (c) ¾ÖÖ™ü (d) ¾ÖÖ™ü ‘ÖÞ™üÖ
17. ÃÖÓÝÖÖ´Öß ¾Ö ÃÖ´ÖŸÖ»ÖßμÖ ²Ö»ÖÖë Ûúß ¯Ö׸ü×ãÖ×ŸÖ Ûúß ÃÖÖ´μÖÖ¾ÖãÖÖ Ûúß ¤ü¿ÖÖ Æîü
(a) ∑H = 0; ∑V = 0; ∑M = 0 (b) ∑H = 0; ∑V = 0 (c) ∑H = 0; ∑V ≠ 0 (d) ∑H = 0; ∑M = 0
18. ×ÛúÃÖß ×¯ÖÞ›ü ÛúÖ •Ö›ÌüŸ¾Ö †Ö‘ÖæÞÖÔ ×®Ö´®Ö ¯Ö¸ü ×®Ö³ÖÔ¸ü ®ÖÆüà Ûú¸üŸÖÖ Æîü :
(a) ׯÖÞ›ü ÛúÖ ¦ü¾μÖ´ÖÖ®Ö (b) ׯÖÞ›ü ´Öë ¦ü¾μÖ´ÖÖ®Ö ×¾ÖŸÖ¸üÞÖ
(c) ׯÖÞ›ü Ûêú “ÖÛÎúßμÖ †õÖ (d) ׯÖÞ›ü Ûúß ÛúÖêÞÖßμÖ ÝÖןÖ
19. ‹Ûú ׯÖÞ› ÃÖ¸ü»Ö †Ö¾ÖŸÖÔ ÝÖ×ŸÖ ´Öë †×¬ÖÛúŸÖ´Ö ÝÖ×ŸÖ ¯ÖÏÖ¯ŸÖ Ûú¸üŸÖÖ Æîü, •Ö²Ö †ÖμÖÖ´Ö ÆüÖêŸÖÖ Æîü
(a) †×¬ÖÛúŸÖ´Ö (b) †×¬ÖÛúŸÖ´Ö ŠúÞÖÖŸ´ÖÛú
(c) ¿Öæ®μÖ (d) †ÖîÃÖŸÖ
20. ‹Ûú 9 m Ûúß »Ö´²ÖÖ‡Ô ¾ÖÖ»Öß ¯ÖæÞÖÔŸÖ: (×ÃÖ´¯Ö»Öß) ÃÖÆüÖ¸êü ¾ÖÖ»Öß ²Öß´Ö AB, ×ÃÖ¸êü A ÃÖê 6 m Ûúß ¤æü¸üß ŸÖÛú 10 kN/m ÛúÖ
‹ÛúÃÖ´ÖÖ®Ö ºþ¯Ö ÃÖê ×¾ÖŸÖ׸üŸÖ ³ÖÖ¸ü ¬ÖÖ¸üÞÖ Ûúß Æãü‡Ô Æîü … A ŸÖ£ÖÖ B ¯Ö¸ü ¯ÖÏןÖ×ÛÎúμÖÖ ²Ö»Ö ŒμÖÖ Æïü?
(a) 40 N ŸÖ£ÖÖ 20 N (b) 60 N ŸÖ£ÖÖ 20 N
(c) 20 N ŸÖ£ÖÖ 60 N (d) 30 N ŸÖ£ÖÖ 15 N
21. ‹Ûú ´Ö¿Öß®Ö ÃÖê 900 N Ûêú ³ÖÖ¸ü ÛúÖê ˆšüÖ®Öê Ûêú ×»Ö‹ 100 N ÛúÖ ¯ÖÏμÖÖÃÖ »ÖÝÖÖμÖÖ ÝÖμÖÖ … ¯ÖÏμÖÖÃÖ «üÖ¸üÖ ŸÖμÖ Ûúß ÝÖμÖß ¤æü¸üß
100 cm Æîü … ³ÖÖ¸ü ÛúÖê 10 cm ¤æü¸üß ŸÖÛú ˆšüÖμÖÖ ÝÖμÖÖ … ´Ö¿Öß®Ö Ûúß ¤üõÖŸÖÖ ŒμÖÖ Æîü?
(a) 80% (b) 90% (c) 70% (d) 60%
22. ¿Öã¨ü ±Ïêú´Ö Ûêú ×»Ö‹, •ÖÖê›ÌüÖë Ûúß ÃÖÓÜμÖÖ (j) ŸÖ£ÖÖ ÃÖ¤üÃμÖÖë Ûúß ÃÖÓÜμÖÖ (n) ¤ü¿ÖÖÔ‡Ô •ÖÖŸÖß Æîü
(a) n = 2j – 3 (b) j = 2n – 3 (c) n = j – 3 (d) j = n – 3
23. ‹Ûú 100 N ³ÖÖ¸ü ÛúÖ ×¯ÖÞ›ü ÜÖã¸ü¤ãü¸üß õÖî×ŸÖ•Ö ŸÖ»Ö ¯Ö¸ü ¸üÜÖÖ Æîü … ÃÖŸÖÆüÖë Ûêú ²Öß“Ö ‘ÖÂÖÔÞÖ ÝÖãÞÖÖÓÛú ŒμÖÖ ÆüÖêÝÖÖ, μÖפü 60 N
ÛúÖ õÖî×ŸÖ•Ö ²Ö»Ö ׯÖÞ›ü ÛúÖê õÖî×ŸÖ•Ö ŸÖ»Ö ¯Ö¸ü ÃÖ¸üÛúÖ ¤êüŸÖÖ Æîü?
(a) 0.3 (b) 0.4 (c) 0.5 (d) 0.
24. ŸÖß®Ö ÃÖ´ÖÖ®ÖÖ®ŸÖ¸ü ²Ö»Ö F 1 , F 2 ŸÖ£ÖÖ F 3 ‹Ûú »Ö™Ëüšêü ¯Ö¸ü ×“Ö¡Ö Ûêú †®ÖãÃÖÖ¸ü ÛúÖμÖÔ¸üŸÖ Æîü ŸÖ£ÖÖ »Ö™ËüšüÖ ÃÖÓŸÖã»Ö®Ö Ûúß †¾ÖãÖÖ ´Öë
Æîü … μÖפü ²Ö»Ö F 1 = 250 N ŸÖ£ÖÖ ²Ö»Ö F 3 = 1000 N Æïü †Öî¸ü F 1 †Öî¸ü F 2 Ûêú ²Öß“Ö Ûúß ¤æü¸üß = 1.0 m Æîü, ŸÖ²Ö
F 2 †Öî¸ü F 3 Ûêú ´Ö¬μÖ ¤æü¸üß ŒμÖÖ ÆüÖêÝÖß?
(a) 0.50 m (b) 0.25 m (c) 0.75 m (d) 0.15 m
Series-A 6 KAU-
25. A weight of 1000 N is supported by two chains as shown in Figure. What will be the tension in Chain-1 and Chain-2 respectively?
(a) 500 N; 866 N (b) 500 N; 433 N (c) 1000 N; 866 N (d) 1000 N; 433 N
26. Four forces P, 2P, 3P and 4P act along the sides, taken in order of a square ABCD. The resultant force is (a) zero (b) 2 2 P (c) 2P (d) 5 P 27. Two forces of equal magnitude ‘P’ act at an angle 120° to each other. What will be their resultant?
(a) 2P (b) P (c) 2 P (d)
P
28. Jet engine works on the principle of (a) conservation of energy (b) conservation of linear momentum (c) Earth’s gravity (d) None of these 29. Young’s modulus of elasticity for a perfectly rigid body is (a) zero (b) unity (c) infinity (d) cannot be known 30. Which of the following concurrent forces cannot have a resultant of 4N? (a) 2N and 4N (b) 2N and 6N (c) 2N and 8N (d) All of these 31. Factor of safety is the ratio of (a) breaking stress to working stress (b) endurance limit to yield stress (c) elastic limit to ultimate stress (d) ultimate stress to working stress 32. The working surface above the pitch surface of the gear tooth is termed as (a) Addendum (b) Dedendum (c) Face (d) Flank 33. The height of Watt’s governor is proportional to (where N : rpm of balls)
(a) N (b) N^2 (c)
N (d)^
N^2
34. Crowning on pulleys helps (a) in increasing velocity ratio. (b) for automatic adjustment of belt so that belt runs centrally. (c) increase the belt life. (d) decrease initial tension.
Series-A 8 KAU-
35. For a governor running at constant speed, the force acting on the sleeve is (a) constant (b) minimum (c) maximum (d) zero 36. For maximum power to be transmitted by the belt, the maximum permissible tension in the belt is (a) equal to centrifugal tension (b) twice the centrifugal tension (c) thrice the centrifugal tension (d) four-times the centrifugal tension 37. The factor that decides the size of the cam is (a) prime circle (b) pitch circle (c) base circle (d) pitch curve 38. Sensitiveness of governor is defined as
(a)
Range of speed Mean speed (b)^
Mean speed Range of speed (c) Mean speed × Range of speed (d) None of these
39. Cam converts the rotary motion into (a) rotary motion (b) translatory motion (c) both rotary and translatory motions (d) None of these 40. The creep in a belt drive is due to (a) material of the pulleys (b) material of the belt (c) unequal size of pulleys (d) unequal tensions and slackness of the belt 41. Backlash in gears is (a) Addendum + Dedendum (b) Circular pitch + Tooth thickness (c) Space width between two teeth – Tooth thickness (d) None of the above 42. In spur gears (a) Both shafts are parallel. (b) Teeth are straight. (c) Teeth are parallel to axis. (d) All of these. 43. Angle moved by the cam during which follower remains at its highest position is called (a) Angle of dwell (b) Angle of descent (c) Angle of ascent (d) Angle of action 44. For a watt governor, what will be the angular speed corresponding to the height of 10 cm, if g = 10 m/sec^2? (a) 1 rad/sec (b) 7.29 rad/sec (c) 10.0 rad/sec (d) 3.15 rad/sec 45. The Brinell hardness is calculated by : (Where F is load in N, D is steel ball diameter and d is indentation diameter in millimetres.)
(a)
F
πD ( D – D^2 – d^2 )^
(b)
F
πD D^2 – d^2
(c)
2F
πD ( D – D^2 – d^2 )^
(d)
2F
πD^2
KAU-05 9 Series-A
35. ‹Ûú †×¬Ö×®ÖμÖ®¡ÖÛú •ÖÖê ‹Ûú ×®ÖμÖŸÖ ÝÖ×ŸÖ ÃÖê ‘Öæ´Ö ¸üÆüÖ Æîü, Ûêú ûÖß¾Ö ¯Ö¸ü ÛúÖμÖÔ¸üŸÖ ²Ö»Ö ÆüÖêÝÖÖü
(a) ×®ÖμÖŸÖ (b) ®μÖæ®ÖŸÖ´Ö (c) †×¬ÖÛúŸÖ´Ö (d) ¿Öæ®μÖ
36. ×ÛúÃÖß ¯Ö™Ëü™êü (²Öê»™ü) Ûêú «üÖ¸üÖ †×¬ÖÛúŸÖ´Ö ¿Ö׌ŸÖ ÃÖÓ“ÖÖ×»ÖŸÖ Ûú¸ü®Öê Ûêú ×»Ö‹, ¯Ö™Ëü™êü ´Öë †×¬ÖÛúŸÖ´Ö þÖßÛéúŸÖ ŸÖ®ÖÖ¾Ö ÆüÖêÝÖÖ
(a) †¯ÖÛêú®¦üßμÖ ŸÖ®ÖÖ¾Ö Ûêú ²Ö¸üÖ²Ö¸ü (b) †¯ÖÛêú®¦üßμÖ ŸÖ®ÖÖ¾Ö ÛúÖ ¤üÖê ÝÖã®ÖÖ
(c) †¯ÖÛêú®¦üßμÖ ŸÖ®ÖÖ¾Ö ÛúÖ ŸÖß®Ö ÝÖã®ÖÖ (d) †¯ÖÛêú®¦üßμÖ ŸÖ®ÖÖ¾Ö ÛúÖ “ÖÖ¸ü ÝÖã®ÖÖ
37. Ûîú´Ö Ûêú †ÖÛúÖ¸ü ÛúÖ ×®Ö¬ÖÖÔ¸üÞÖ Ûú¸ü®Öê ¾ÖÖ»ÖÖ ÛúÖ¸üÛú Æîü
(a) ¯ÖÏÖ‡´Ö ¾Öé¢Ö (b) ×¯Ö“Ö ¾Öé¢Ö (c) ²ÖêÃÖ ¾Öé¢Ö (d) ×¯Ö“Ö ¾ÖÛÎú
38. †×¬Ö×®ÖμÖ®¡ÖÛú Ûúß ÃÖÓ¾Öê¤ü®Ö¿Ö߻֟ÖÖ ¯Ö׸ü³ÖÖ×ÂÖŸÖ ÆüÖêŸÖß Æîü
(a)
ÝÖ×ŸÖ Ûêú ¯Ö¸üÖÃÖ
†ÖîÃÖŸÖ ÝÖ×ŸÖ (b)^
†ÖîÃÖŸÖ ÝÖןÖ
ÝÖ×ŸÖ Ûêú ¯Ö¸üÖÃÖ
(c) †ÖîÃÖŸÖ ÝÖ×ŸÖ × ÝÖ×ŸÖ Ûêú ¯Ö¸üÖÃÖ (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
39. Ûîú´Ö ¾Öé¢ÖßμÖ ÝÖ×ŸÖ ÛúÖê ¯Ö׸ü¾ÖÙŸÖŸÖ Ûú¸üŸÖÖ Æîü
(a) ¾Öé¢ÖßμÖ ÝÖ×ŸÖ ´Öë (b) ¸êüÜÖßμÖ ÝÖ×ŸÖ ´Öë
(c) ¸êüÜÖßμÖ ÝÖ×ŸÖ ‹¾ÖÓ ¾Öé¢ÖßμÖ ÝÖ×ŸÖ ¤üÖê®ÖÖë ´Öë (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
40. ²Öê»™ü ›ÒüÖ‡¾Ö ´Öë ´Ö®¤ü ×¾Öºþ¯ÖÞÖ ÛúÖ ÛúÖ¸üÞÖ ÆüÖêŸÖÖ Æîü
(a) בָü®Öß ÛúÖ ¯Ö¤üÖ£ÖÔ (b) ¯Ö™Ëü™êü ÛúÖ ¯Ö¤üÖ£ÖÔ
(c) בָü×®ÖμÖÖë Ûêú †ÃÖ´ÖÖ®Ö †ÖÛúÖ¸ü (d) ¯Ö™Ëü™üÖë ´Öë †ÃÖ´ÖÖ®Ö ŸÖ®ÖÖ¾Ö ‹¾ÖÓ œüß»ÖÖ¯Ö®Ö
41. ×ÝÖμÖ¸üÖë ´Öë ²ÖîÛú»Öî¿Ö Æîü
(a) ‹›êüÞ›ü´Ö + ×›ü›êüÞ›ü´Ö
(b) ÃÖ¸üÛãú»Ö¸ü ×¯Ö“Ö + ¤üÖÑŸÖÖë Ûúß ´ÖÖê™üÖ‡Ô
(c) ¤üÖê ¤üÖÑŸÖÖë Ûêú ´Ö¬μÖ Ã¯ÖêÃÖ Ûúß “ÖÖî›ÌüÖ‡Ô – ¤üÖÑŸÖÖë Ûúß ´ÖÖê™üÖ‡Ô
(d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
42. ïָü ×ÝÖμÖ¸ü ´Öë
(a) ¤üÖê®ÖÖë ¿ÖÖ°™ü ÃÖ´ÖÖ®ÖÖ®ŸÖ¸ü Æîü … (b) ¤üÖÑŸÖ ÃÖ߬Öê ÆüÖêŸÖê Æïü …
(c) ¤üÖÑŸÖ †õÖ Ûêú ÃÖ´ÖÖ®ÖÖ®ŸÖ¸ü ÆüÖêŸÖê Æïü … (d) ˆ¯Ö¸üÖêŒŸÖ ÃÖ³Öß
43. Ûîú´Ö «üÖ¸üÖ ¯Öæ¸üÖ ×ÛúμÖÖ ÝÖμÖÖ ÛúÖêÞÖ ×•ÖÃÖ ¯Ö¸ü ±úÖò»ÖÖê¾Ö¸ü ˆ““ÖŸÖ´Ö Ã£ÖÖ®Ö ¯Ö¸ü ×ãָü ÆüÖêŸÖÖ Æîü
(a) ›Ëü¾Öê»Ö (Dwell) ÛúÖêÞÖ (b) ×›üÃÖë™ü (Descent) ÛúÖêÞÖ
(c) ‹êÃÖë™ü (Ascent) ÛúÖêÞÖ (d) ‹Œ¿Ö®Ö ÛúÖêÞÖ
44. ¾ÖÖ™ü †×¬Ö×®ÖμÖ®¡ÖÛú ÛúÖ 10 cm ‰Ñú“ÖÖ‡Ô Ûêú ÃÖ´ÖÛúõÖ ÛúÖêÞÖßμÖ ¾ÖêÝÖ ŒμÖÖ ÆüÖêÝÖÖ, μÖפü g = 10 m/sec^2 Æîü?
(a) 1 rad/sec (b) 7.29 rad/sec (c) 10.0 rad/sec (d) 3.15 rad/sec
45. ²ÖÎß®Öê»Ö ÛúšüÖê¸üŸÖÖ Ûúß ÝÖÞÖ®ÖÖ ÆüÖêŸÖß Æîü
(•ÖÆüÖÑ F ³ÖÖ¸ü ®μÖæ™ü®Ö ´Öë, D Ùüᯙ ²ÖÖò»Ö ÛúÖ ¾μÖÖÃÖ ŸÖ£ÖÖ d ¤ÓüŸÖã¸üŸÖÖ ÛúÖ ¾μÖÖÃÖ ×´Ö»Öß´Öß™ü¸ü ´Öë Æîü …)
(a)
F
πD (^ D – D^2 – d^2 )^
(b)
F
πD D^2 – d^2
(c)
2F
πD ( D – D^2 – d^2 )^
(d)
2F
πD^2
KAU-05 11 Series-A
46. ³ÖÖ¯Ö ¾ÖÖ»Öê ‡Ó•Ö®Ö Ûêú ׯÖÙü®Ö, ׯÖÙü®Ö ¸üÖò›ü ŸÖ£ÖÖ ÛÎúÖòÃÖ Æêü›ü ×´Ö»ÖÛú¸ü ²Ö®ÖÖŸÖê Æïü
(a) ‹Ûú Ø»ÖÛú (Ûú›Ìüß) (b) ¤üÖê Ø»ÖÛú (Ûú×›ÌüμÖÖÑ)
(c) ŸÖß®Ö Ø»ÖÛú (Ûú×›ÌüμÖÖÑ) (d) ÛúÖê‡Ô Ø»ÖÛú ®ÖÆüà ²Ö®ÖÖŸÖê Æïü …
47. ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ˆ““ÖŸÖ¸ü μÖãÝ´Ö Æîü?
(a) ¯Ö™Ëü™üÖ ‹¾ÖÓ ×‘Ö¸ü®Öß (b) ™üÙ®ÖÝÖ μÖãÝ´Ö (c) ÃÛÎæú μÖãÝ´Ö (d) ÃÖ¸üÛú®Ö μÖãÝ´Ö
48. ‹Ûú μÖÖî×ÝÖÛú (compound) ×ÝÖμÖ¸ü ™Òêü®Ö ´Öë
(a) ¯ÖÏŸμÖêÛú ¿ÖÖ°™ü ¯Ö¸ü ×ÃÖ±Ôú ‹Ûú ×ÝÖμÖ¸ü ÆüÖêŸÖÖ Æîü … (b) ‹Ûú ¿ÖÖ°™ü ¯Ö¸ ü‹Ûú ÃÖê •μÖÖ¤üÖ ×ÝÖμÖ¸ü ÆüÖêŸÖê Æïü …
(c) ›ÒüևؾÖÝÖ ¿ÖÖ°™ü ¯Ö¸ü ÛúÖê‡Ô ×ÝÖμÖ¸ü ®ÖÆüà … (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà …
49. ”ûÖê™êü †Ö®ŸÖ׸üÛú ¤üÆü®Ö ‡Ó•Ö®ÖÖë Ûêú †ÖμÖ»Ö ¯Ö´¯ÖÖë ´Öë ÛúÖî®Ö ÃÖê ×ÝÖμÖ¸ü ‡ÃŸÖê´ÖÖ»Ö ×ÛúμÖê •ÖÖŸÖê Æïü?
(a) ïָü ×ÝÖμÖ¸ü (b) ÛÎúÖòÛü Æêü»ÖßÛú»Ö ×ÝÖμÖ¸ü
(c) ×ÝÖμÖ¸ü ™Òêü®Ö (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
50. ¯ÖÏןÖÛêú®¦ü•Ö ×ÝÖμÖ¸ü ´Öë ¤ü²ÖÖ¾Ö ÛúÖêÞÖ
(a) ¤üÖÑŸÖ Ûêú †ÖÛúÖ¸ü ¯Ö¸ü ×®Ö³ÖÔ¸ü Æîü … (b) ×ÝÖμÖ¸ü Ûêú †ÖÛúÖ¸ü ¯Ö¸ü ×®Ö³ÖÔ¸ü Æîü …
(c) ¿Öæ®μÖ ÆüÖêŸÖÖ Æîü … (d) ÃÖ¤üÖ ×ãָü ÆüÖêŸÖÖ Æîü …
51. †×¬ÖÛúŸÖ´Ö ¿Ö׌ŸÖ ¯ÖÖ¸êüÂÖÞÖ ÆêüŸÖã ²Öê»™ü Ûúß ÝÖ×ŸÖ Æîü
(•ÖÆüÖÑ m = ²Öê»™ü ÛúÖ ¦ü¾μÖ´ÖÖ®Ö (×ÛúÝÖÏÖ ¯ÖÏ×ŸÖ ´Öß. »Ö´²ÖÖ‡Ô ´Öë), T = ŸÖ®ÖÖ¾Ö)
(a)
T
3m (b)^
T
4m (c)^
T
5m (d)^
T
6m
52. ×ÝÖμÖ¸ü ÛúÖ †ÖÛúÖ¸ü †Ö´ÖŸÖÖî¸ü ¯Ö¸ü ×®Ö´®Ö «üÖ¸üÖ ×®Ö¬ÖÖÔ׸üŸÖ ÆüÖêŸÖÖ Æîü :
(a) ¯ÖÏê¿Ö¸ü ÛúÖêÞÖ (b) ×¯Ö“Ö ÃÖÛÔú»Ö ¾μÖÖÃÖ (c) ÃÖ¸üÛãú»Ö¸ü ×¯Ö“Ö (d) ›üÖμÖ´Öê™Òü»Ö ׯ֓Ö
53. ‹Ûú Ûîú´Ö †Öî¸ü ±úÖò»ÖÖꆸü ¸ü“Ö®ÖÖŸÖÓ¡Ö ²Ö®ÖÖŸÖÖ Æîü
(a) ÜÖã»ÖÖ μÖãÝ´Ö (b) ÃÛÎæú μÖãÝ´Ö (c) ²Ö®¤ü μÖãÝ´Ö (d) ÝÖÖê»ÖßμÖ μÖãÝ´Ö
54. ¾ÖÖ™ü †×¬Ö×®ÖμÖ®¡ÖÛú Ûúß ‰Ñú“ÖÖ‡Ô ÆüÖêŸÖß Æîü
(a) ¾ÖêÝÖ ÛúÖ ÃÖ߬ÖÖ ÃÖ´ÖÖ®Öã¯ÖÖŸÖß (b) (¾ÖêÝÖ)^2 ÛúÖ ÃÖ߬ÖÖ ÃÖ´ÖÖ®Öã¯ÖÖŸÖß
(c) ¾ÖêÝÖ ÛúÖ ¾μÖãŸÛÎú´ÖÖ®Öã¯ÖÖŸÖß (d) (¾ÖêÝÖ)^2 ÛúÖ ¾μÖãŸÛÎú´ÖÖ®Öã¯ÖÖŸÖß
55. ¯ÖÖê™Ôü¸ü †×¬Ö×®ÖμÖ®¡ÖÛú ÛúÖê ¾ÖÝÖáÛéúŸÖ ×ÛúμÖÖ •ÖÖŸÖÖ Æîü
(a) ‡®ÖÙ¿ÖμÖÖ ™üÖ‡¯Ö †×¬Ö×®ÖμÖ®¡ÖÛú (b) ¯Öë›ãü»Ö´Ö ™üÖ‡¯Ö †×¬Ö×®ÖμÖ®¡ÖÛú
(c) ÃÖê®™Òüß°μÖæÝÖ»Ö †×¬Ö×®ÖμÖ®¡ÖÛú (d) ´ÖéŸÖ ³ÖÖ¸ ™üÖ‡¯Ö †×¬Ö×®ÖμÖ®¡ÖÛú
56. ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ÃÖÖ ‘ÖÂÖÔÞÖ Œ»Ö“Ö ®ÖÆüà Æîü?
(a) ×›üÃÛú μÖÖ ¯»Öê™ü Œ»Ö“Ö (b) ÛúÖê®Ö Œ»Ö“Ö
(c) ÃÖê®™Òüß°μÖæÝÖ»Ö Œ»Ö“Ö (d) •Ö²Ö›ÌüÖ Œ»Ö“Ö
57. ÝÖן֯ÖÖ»ÖÛú “ÖÛÎú ´Öë †×¬ÖÛúŸÖ´Ö ‰ú•ÖÖÔ - ˆ““ÖÖ¾Ö“Ö®Ö ×®Ö´®Ö Ûêú ²Ö¸üÖ²Ö¸ü Æîü :
•ÖÆüÖÑ : I = ÝÖן֯ÖÖ»ÖÛú “ÖÛÎú ÛúÖ •Ö›ÌüŸ¾Ö †Ö‘ÖæÞÖÔ
E = ÝÖן֯ÖÖ»ÖÛú “ÖÛÎú Ûúß ´Ö¬μÖ ÝÖ×ŸÖ•Ö ‰ú•ÖÖÔ
CS = ¾ÖêÝÖ ˆ““ÖÖ¾Ö“Ö®Ö ÛúÖ ÝÖãÞÖÖÓÛú
ω = ´Ö¬μÖ ÛúÖêÞÖßμÖ ¾ÖêÝÖ
ω 1 + ω 2 2 (a) Iω (ω 1 – ω 2 ) (b) Iω^2 CS
(c) 2ECS (d) ˆ¯Ö¸üÖêŒŸÖ ÃÖ³Öß
Series-A 12 KAU-
58. The product of circular pitch and diametral pitch is equal to
(a) 1 (b) 1.57 (c) π (d) Infinite
59. Axial thrust is minimum in case of (a) Spur gear (b) Bevel gear (c) Mitre gear (d) Double helical gear 60. Which of the following brakes is commonly used in motor cars? (a) Band Brake (b) Shoe Brake (c) Band and Block Brake (d) Internal Expanding Shoe Brake 61. Outside diameter of a hollow shaft is twice its inside diameter. Ratio of torque carrying capacity to that of a solid shaft of same outside diameter and same material is (a) 3/4 (b) 15/16 (c) 1/2 (d) 1/ 62. For a shaft transmitting power ‘P’ at rpm N, the diameter of shaft would be proportional to
(a) (^)
P
N
1/ (b) (^)
P
N
1/ (c) (^)
P
N
2/ (d) (^)
P
N
3
63. A dead load is one that (a) remains constant (b) varies with time (c) cannot be determined (d) whose value is zero 64. What is the unit of strain? (a) Centimetre (b) Millimetre (c) Micron (d) None of these 65. Which of the following statements is correct? (a) Stress is proportional to strain. (b) Stress is force per unit area. (c) Within elastic limit, the ratio of stress to strain is called Young’s modulus. (d) All of the above 66. Spring index is (a) Ratio of coil diameter to wire diameter. (b) Load required to produce unit deflection. (c) Its capability of storing energy. (d) None of the above 67. When two springs (each having stiffness constant K) are connected in series, the equivalent stiffness will be
(a) K (b) 2K (c)
K
2 (d)^
K
68. In a beam, the point of contraflexure is a point where (a) Shear force is maximum. (b) Shear force is zero. (c) Bending moment changes its sign. (d) Bending moment is maximum. 69. Spiral springs are used in (a) Cycles (b) Scooters (c) Watches (d) Railway Wagons
Series-A 14 KAU-
70. For perfectly elastic body, the value of co-efficient of restitution is (a) zero (b) 0.5 (c) 1 (d) between 0 and 1 71. Hoop stress in thin walled cylinder is (a) longitudinal tensile stress (b) radial stress (c) circumferential tensile stress (d) compressive stress 72. Slow plastic deformation of metals under a constant stress at high temperature is known as (a) Fatigue (b) Plastic deformation (c) Creep (d) Endurance 73. The fatigue life of a part can be improved by (a) Electroplating (b) Polishing (c) Coating (d) Shot peening 74. Flow stress corresponds to (a) Fluid in motion (b) Breaking point (c) Plastic deformation of solids (d) Rupture stress 75. Moment of inertia of a solid sphere is (Where M = mass of the solid sphere r = radius of the sphere)
(a) Mr^2 (b)
3 Mr
(^2) (c) 2 5 Mr
(^2) (d) 1 2 Mr
2
The above stress-strain diagram is for (a) Ductile material (b) Brittle material (c) Soft material (d) None of these
77. The longitudinal joint of a boiler shell is always a (a) Lap joint (b) Butt joint (c) Lozenge joint (d) Diamond joint 78. Strain is defined as the ratio of (a) change in volume to original volume. (b) change in length to original length. (c) change in lateral dimension to original lateral dimension. (d) All of the above 79. Necking phenomenon in stress-strain is observed for (a) Brittle materials (b) Ductile materials (c) Both brittle as well as ductile materials (d) None of the above
KAU-05 15 Series-A
70. ¯ÖæÞÖÔ ¯ÖÏŸμÖÖÃ£Ö ×¯ÖÞ›ü Ûêú ×»ÖμÖê ¯ÖÏŸμÖÖ¾ÖãÖÖ®Ö ÝÖãÞÖÖÓÛú ÆüÖêŸÖÖ Æîü
(a) ¿Öæ®μÖ (b) 0.5 (c) 1 (d) ¿Öæ®μÖ ¾Ö ‹Ûú Ûêú ²Öß“Ö
71. ¯ÖŸÖ»Öß ¤üß¾ÖÖ¸ü ¾ÖÖ»Öê ²Öê»Ö®Ö ´Öë ¯Ö׸ü¬ÖßμÖ ¯ÖÏ×ŸÖ²Ö»Ö Æîü
(a) †®Öã¤îü¬μÖÔ ŸÖ®ÖÖ¾Ö ¯ÖÏ×ŸÖ²Ö»Ö (b) ס֕μÖßμÖ ¯ÖÏןֲֻÖ
(c) ¯Ö׸ü¬ÖßμÖ ŸÖ®ÖÖ¾Ö ¯ÖÏ×ŸÖ²Ö»Ö (d) ÃÖ´¯Öß›ü®Ö ¯ÖÏןֲֻÖ
72. ¬ÖÖŸÖã ÛúÖ ×®ÖμÖŸÖ ¯ÖÏ×ŸÖ²Ö»Ö Ûêú †¬Öß®Ö ˆ““Ö ŸÖÖ¯Ö´ÖÖ®Ö ¯Ö¸ü ¬Öß´ÖÖ ¯»ÖÖ×ÙüÛú ×¾Öºþ¯ÖÞÖ •ÖÖ®ÖÖ •ÖÖŸÖÖ Æîü
(a) ÁÖÖÓ×ŸÖ (b) ÃÖã‘Ö™ËüμÖ ×¾Öºþ¯ÖÞÖ (c) ´ÖÓ¤ü ×¾Öºþ¯ÖÞÖ (d) ÃÖÆü®Ö ÃÖÖ´Ö£μÖÔ
73. ×ÛúÃÖß ‘Ö™üÛú Ûúß ÁÖÖÓ×ŸÖ †ÖμÖã ²ÖœÌüÖ‡Ô •ÖÖ ÃÖÛúŸÖß Æîü
(a) ×¾ÖªãŸÖ »Öê¯Ö®Ö ÃÖê (b) “ÖÛúÖÃÖ®Ö ÃÖê (c) »Öê¯Ö®Ö ÃÖê (d) ÝÖã×»ÖÛúÖ ¯ÖÏõÖê¯ÖÞÖ ÃÖê
74. ¯ÖϾÖÖÆü ¯ÖÏ×ŸÖ²Ö»Ö ×®Ö´®Ö Ûêú ÃÖãÃÖÓÝÖŸÖ ÆüÖêŸÖÖ Æîü :
(a) ÝÖ×ŸÖ ´Öë ¦ü¾Ö (b) ×¾Ö“”êû¤ü®Ö ײ֮¤ãü
(c) šüÖêÃÖ ´Öë ¯»ÖÖ×ÙüÛú ×¾Öºþ¯ÖÞÖ (d) ÃÖÓ×¾Ö¤üÖ¸ü ¯ÖÏןֲֻÖ
75. šüÖêÃÖ ÝÖÖê»Öê ÛúÖ •Ö›ÌüŸ¾Ö †Ö‘ÖæÞÖÔ ÆüÖêŸÖÖ Æîü :
(•ÖÆüÖÑ : ÝÖÖê»Öê Ûúß ×¡Ö•μÖÖ r Æîü …
†Öî¸ü ¦ü¾μÖ´ÖÖ®Ö M Æîü …)
(a) Mr^2 (b)
3 Mr
(^2) (c) 2 5 Mr
(^2) (d) 1 2 Mr
2
76.
¯ÖϤüÙ¿ÖŸÖ ¯ÖÏןֲֻÖ-×¾ÖÛéú×ŸÖ †Ö¸êüÜÖ Æîü
(a) ®Ö´Ö®ÖßμÖ ¯Ö¤üÖ£ÖÔ Ûêú ×»Ö‹ (b) ³ÖÓÝÖã¸ü ¯Ö¤üÖ£ÖÔ Ûêú ×»Ö‹
(c) ®Ö´ÖÔ ¯Ö¤üÖ£ÖÔ Ûêú ×»Ö‹ (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
77. †®Öã¤îü¬μÖÔ •ÖÖê›Ìü ×ÛúÃÖß ³Öß ²ÖÖòμÖ»Ö¸ü ¿Öê»Ö ´Öë ÃÖ¤îü¾Ö
(a) »Öî¯Ö •¾ÖÖ‡Ó™ü ÆüÖêŸÖÖ Æîü … (b) ²Ö™ü •¾ÖÖ‡Ó™ü ÆüÖêŸÖÖ Æîü …
(c) »ÖÖò•Öê®•Ö •¾ÖÖ‡Ó™ü ÆüÖêŸÖÖ Æîü … (d) ›üÖμÖ´Ö®›ü •¾ÖÖ‡Ó™ü ÆüÖêŸÖÖ Æîü …
78. ‘×¾ÖÛéúן֒ †®Öã¯ÖÖŸÖ Ûêú ºþ¯Ö ´Öë ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúß •ÖÖŸÖß Æîü
(a) †ÖμÖŸÖ®Ö ´Öë ¯Ö׸ü¾ÖŸÖÔ®Ö ‹¾ÖÓ ¯ÖÏÖ¸ü×´³ÖÛú †ÖμÖŸÖ®Ö ÛúÖ †®Öã¯ÖÖŸÖ
(b) »Ö´²ÖÖ‡Ô ´Öë ¯Ö׸ü¾ÖŸÖÔ®Ö ‹¾ÖÓ ¯ÖÏÖ¸ü×´³ÖÛú »Ö´²ÖÖ‡Ô ÛúÖ †®Öã¯ÖÖŸÖ
(c) ¯ÖÖÙ¿¾ÖÛú ×¾Ö´ÖÖ ´Öë ¯Ö׸ü¾ÖŸÖÔ®Ö ‹¾ÖÓ ¯ÖÏÖ¸ü×´³ÖÛú ¯ÖÖÙ¿¾ÖÛú ×¾Ö´ÖÖ ÛúÖ †®Öã¯ÖÖŸÖ
(d) ˆ¯Ö¸üÖêŒŸÖ ÃÖ³Öß
79. ¯ÖÏןֲֻÖ-×¾ÖÛéú×ŸÖ †Ö¸êüÜÖ ´Öë ®ÖêØÛúÝÖ (Necking) ¯ÖÖμÖÖ •ÖÖŸÖÖ Æîü
(a) ³ÖÓÝÖã¸ü ¯Ö¤üÖ£ÖÔ ´Öë (b) ŸÖ®μÖ ¯Ö¤üÖ£ÖÔ ´Öë
(c) ³ÖÓÝÖã¸ü ‹¾ÖÓ ŸÖ®μÖ ¯Ö¤üÖ£ÖÔ ¤üÖê®ÖÖë ´Öë (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
KAU-05 17 Series-A
80. ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ÃÖÖ ¯Ö¤üÖ£ÖÔ †×¬ÖÛú ¯ÖÏŸμÖÖÃ£Ö Æîü?
(a) ¸ü²Ö¸ü (b) ¯»ÖÖ×ÙüÛú (c) ¯ÖßŸÖ»Ö (d) ‡Ã¯ÖÖŸÖ
81. ‹Ûú †ÖμÖÖŸÖÖÛúÖ¸ü ¾Ö סֳÖã•Ö ו֮ÖÛúÖ †Ö¬ÖÖ¸ü ¾Ö ‰Ñú“ÖÖ‡Ô ‹Ûú ²Ö¸üÖ²Ö¸ü Æîü, Ûêú •Ö›ÌüŸ¾Ö †Ö‘ÖæÞÖÖí ÛúÖ †®Öã¯ÖÖŸÖ ˆ®ÖÛêú †Ö¬ÖÖ¸üÖë Ûêú
ÃÖÖ¯ÖêõÖ ÆüÖêÝÖÖ
(a) 2 : 1 (b) 3 : 1 (c) 4 : 1 (d) 5 : 1
82. ‹Ûú ßִ³Ö Ûêú ¤üÖê®ÖÖë ”ûÖê¸ü ÛúÖê •Ö›Ìü Ûú¸ü®Öê Ûúß ¤ü¿ÖÖ ´Öë ¯ÖϳÖÖ¾Öß »Ö´²ÖÖ‡Ô Æîü
(a) þÖμÖÓ Ûúß »Ö´²ÖÖ‡Ô (b) »Ö´²ÖÖ‡Ô ÛúÖ ¤ãüÝÖã®ÖÖ
(c) þÖμÖÓ Ûúß »Ö´²ÖÖ‡Ô ÛúÖ †Ö¬ÖÖ (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
83. ×ÛúÃÖß ¯Ö¤üÖ£ÖÔ Ûúß ×¾Ö¿ÖêÂÖŸÖÖ •ÖÖê †Ö‘Ö™ËüμÖ ³ÖÖ¸ü Ûêú ¯ÖÏ×ŸÖ ±ÏêúŒ“Ö¸ü ¯ÖÏןָüÖê¬ÖÛú Ûêú ºþ¯Ö ´Öë •ÖÖ®ÖÖ •ÖÖŸÖÖ Æîü
(a) ¯ÖÏŸμÖÖã֟ÖÖ (b) ÃÖÆü®Ö¿Ö߻֟ÖÖ (c) ¯ÖÏןָüÖê¬Ö®Ö õÖ´ÖŸÖÖ (d) “Öß´Ö›Ìü¯Ö®Ö
84. ‹Ûú ¯ÖÏÖÃÖ ¬Ö¸ü®Ö וÖÃÖÛêú †®ŸÖ ´Öë ‹Ûú ÃÖÓÛêú×®¦üŸÖ ³ÖÖ¸ü »ÖÝÖÖ Æãü†Ö Æîü, ÛúÖ ²ÖÓÛú®Ö †Ö‘ÖæÞÖÔ †Ö¸êüÜÖ ÆüÖêÝÖÖ
(a) †ÖμÖŸÖÖÛúÖ¸ü (b) ‘Ö®ÖßμÖ ¯Ö¸ü¾Ö»ÖμÖ (c) סֳÖã•Ö (d) ¯Ö¸ü¾Ö»ÖμÖ
85. ×ÛúÃÖß ÛúÖ™ü ¯Ö¸ü ®Ö´Ö®Ö †Ö‘ÖæÞÖÔ †×¬ÖÛúŸÖ´Ö ÆüÖêŸÖÖ Æîü, •ÖÆüÖÑ ÛúŸÖÔ®Ö ²Ö»Ö
(a) †×¬ÖÛúŸÖ´Ö Æîü … (b) ®μÖæ®ÖŸÖ´Ö Æî …ü (c) דÖÅ®Ö ²Ö¤ü»ÖÖ¾Ö Ûú¸üŸÖÖ Æîü … (d) ¿Öæ®μÖ ÆüÖêŸÖÖ Æîü …
86. •Ö²Ö ‹Ûú ŸÖÖ¸ü ÛúÖê ÜÖà“ÖÛú¸ü »Ö´²ÖÖ‡Ô ¤üÖê ÝÖã®Öß Ûú¸ü ¤üß •ÖÖŸÖß Æîü, ŸÖÖê †®Öã¤îü¬μÖÔ ×¾ÖÛéú×ŸÖ ÆüÖêŸÖß Æîü
(a) 0.5 (b) 1.0 (c) 1.5 (d) 2.
87. †×¬ÖÛúŸÖ´Ö ®Ö´Ö®Ö †Ö‘ÖæÞÖÔ ÃÖÆü®Ö Ûú¸ü®Öê Ûêú ×»Ö‹ ¬Ö¸ü®Ö ÛúÖ ÃÖ²ÖÃÖê ×´ÖŸÖ¾μÖμÖß †®Öã¯ÖÏãÖ-ÛúÖ™ü Æîü
(a) ¾ÖÝÖÖÔÛúÖ¸ü (b) ¾Öé¢ÖÖÛúÖ¸ü (c) †ÖμÖŸÖÖÛúÖ¸ü (d) †Ö‡Ô-ÛúÖ™ü (ÃÖꌿ֮Ö)
88. †ÖμÖ»Ö¸ü ¾μÖÖÛãÓú“Ö®Ö ×ÃÖ¨üÖ®ŸÖ »ÖÖÝÖæ ÆüÖêŸÖÖ Æîü
(a) ”ûÖê™êü ÛúÖò»Ö´Ö ¯Ö¸ü (b) »Ö´²Öê ÛúÖò»Ö´Ö ¯Ö¸ü
(c) ´Ö¬μÖ´Ö »Ö´²Öê ÛúÖò»Ö´Ö ¯Ö¸ü (d) ˆ¯Ö¸üÖêŒŸÖ ÃÖ³Öß ¯Ö¸ü
89. ‹Ûú »Ö´²ÖÖ ÃŸÖ´³Ö †ÃÖ±ú»Ö ÆüÖêŸÖÖ Æîü
(a) ¤ü»Ö®Ö ÃÖê (b) ŸÖ®ÖÖ¾Ö ÃÖê (c) ÛúŸÖÔ®Ö ÃÖê (d) ¾μÖÖÛãÓú“Ö®Ö ÃÖê
90. ŸÖ®ÖãŸÖÖ †®Öã¯ÖÖŸÖ ×®Ö´®Ö ÛúÖ †®Öã¯ÖÖŸÖ Æîü :
(a) †×¬ÖÛúŸÖ´Ö ÃÖÖ‡•Ö ÛúÖò»Ö´Ö †Öî¸ü ×®Ö´®ÖŸÖ´Ö ÃÖÖ‡•Ö ÛúÖò»Ö´Ö
(b) ÛúÖò»Ö´Ö Ûúß “ÖÖî›ÌüÖ‡Ô ‹¾ÖÓ ÛúÖò»Ö´Ö Ûúß ÝÖÆü¸üÖ‡Ô
(c) ÛúÖò»Ö´Ö Ûúß ¯ÖϳÖÖ¾Öß »Ö´²ÖÖ‡Ô ‹¾ÖÓ ÛúÖò»Ö´Ö Ûúß ®μÖæ®ÖŸÖ´Ö ‘ÖæÞÖÔ®Ö ×¡Ö•μÖÖ
(d) ÛúÖò»Ö´Ö Ûúß ¯ÖϳÖÖ¾Öß »Ö´²ÖÖ‡Ô ‹¾ÖÓ ÛúÖò»Ö´Ö Ûúß “ÖÖî›ÌüÖ‡Ô
91. ×®Ö´®Ö×»Ö×ÜÖŸÖ ´Öë ÃÖê ÛúÖî®Ö ÃÖÖ »ÖÖêÆêü Ûêú ¿Öã¨ü ºþ¯Ö Ûêú ×®ÖÛú™ü Æîü?
(a) œü»Ö¾ÖÖÑ »ÖÖêÆüÖ (b) ׯ֙ü¾ÖÖÑ »ÖÖêÆüÖ (c) ¬ÖæÃÖ¸ »ÖÖêÆüÖ (d) ´Öé¤ãü ‡Ã¯ÖÖŸÖ
92. ×®Ö´®Ö ÛúÖ²Ö洞 ̪üᯙ ´Öë ÛúÖ²ÖÔ®Ö ÛúÖ ¯ÖÏ×ŸÖ¿ÖŸÖ ÆüÖêŸÖÖ Æîü
(a) 1.0% (b) 0.15% (c) 0.87% (d) 0.50%
93. ±ú»ÖÛú Ûêú×®¦üŸÖ ‘Ö®Ö ÃÖÓ¸ü“Ö®ÖÖ Ûúß ÃÖ´Ö®¾ÖμÖ ÃÖÓÜμÖÖ Æîü :
(a) 4 (b) 8 (c) 12 (d) 16
94. 18/8 Ùêü®Ö»ÖêÃÖ Ã™üᯙ ´Öë ÆüÖêŸÖÖ Æîü
(a) 18% ×®Ö×Ûú»Ö, 8% ÛÎúÖê×´ÖμÖ´Ö (b) 18% ÛÎúÖê×´ÖμÖ´Ö, 8% ×®Ö×Ûú»Ö
(c) 18% ™ÓüÝÖÙü®Ö, 8% ×®Ö×Ûú»Ö (d) 18% ™ÓüÝÖÙü®Ö, 8% ÛÎúÖê×´ÖμÖ´Ö
95. œü»Ö¾Öë »ÖÖêÆêü ÛúÖ †×«üŸÖßμÖ ÝÖãÞÖ Æîü ‡ÃÖÛúß/Ûêú ˆ““Ö
(a) †Ö‘ÖÖŸÖ¾Ö¬μÖÔŸÖÖ (b) ŸÖ®μÖŸÖÖ
(c) ÛúšüÖê¸üŸÖÖ (d) †¾Ö´ÖÓ¤üÛú (›îüØ´¯ÖÝÖ) »ÖõÖÞÖ
Series-A 18 KAU-
96. Correct sequence of elements of 18 – 4 – 1 HSS tool is (a) W, Cr, V (b) Mo, Cr, V (c) Cr, Ni, C (d) Cu, Zn, Sn 97. Pure iron is a substance of (a) Ferrite (b) Pearlite (c) Austenite (d) Ferrite and Cementite 98. Which metal coating is used in the mirror? (a) Lead (b) Tin (c) Gold (d) Brass 99. Which of the following fundamental components of atom is uncharged? (a) Proton (b) Neutron (c) Electron (d) Positron 100. Which tool is used for rapid machining of hard metals? (a) Cemented Carbide (b) High Speed Steel (c) Stellites (d) None of these 101. Purpose of normalizing is to (a) improve strength (b) increase hardness (c) remove internal stresses (d) None of these 102. Which of the following metals does not have hexagonal close packed structure? (a) Magnesium (b) Zinc (c) Cadmium (d) Copper 103. Which element makes stainless steel corrosion resistant? (a) Vanadium (b) Chromium (c) Carbon (d) Sulphur 104. The process of formation of new grains on heating metals is called (a) Recrystallization (b) Oxidation (c) Microstructure (d) Hardening 105. Brass is an alloy of (a) Copper and Zinc (b) Copper and Tin (c) Arsenic and Tin (d) Gold and Tin 106. Which of the following has maximum ductility? (a) Copper (b) Mild Steel (c) Cast Iron (d) 18-4-1 Steel 107. Paramagnetic alpha iron changes to gamma iron at following temperature : (a) 768 °C (b) 1440 °C (c) 908 °C (d) 1539 °C 108. Eutectoid steel contains following percentage of carbon (a) 0.02 (b) 0.30 (c) 0.63 (d) 0. 109. The material having same elastic property in all the directions are called (a) Ideal materials (b) Uniform materials (c) Isotropic materials (d) Practical materials 110. The ability of material to resist softening at higher temperature is known as (a) Creep (b) Hot tempering (c) Hot hardness (d) Fatigue 111. The slowest cooling rate is achieved when steel is quenched in (a) fused salt (b) air (c) brine (d) mixture of water and oil
Series-A 20 KAU-
112. Toughness is related to (a) Moment of inertia (b) Hardness (c) Energy absorbed before fracture (d) Fatigue loading 113. Which among the followings is the most effective strengthening mechanism of non-ferrous materials? (a) Solid solution hardening (b) Strain hardening (c) Grain size refinement (d) Precipitation hardening 114. Which of the following is the an amorphous material? (a) Lead (b) Brass (c) Glass (d) Silver 115. Which of the following is a case hardening process? (a) Carburizing (b) Nitriding (c) Cynading (d) All of these 116. The chisel used for cutting steel sheets is usually (a) Annealed (b) Normalised (c) Hardened (d) Hardened and Tempered 117. Addition of Nickel to Steel helps in improving (a) Fatigue resistance (b) Creep resistance (c) Corrosion resistance (d) Cost reduction 118. The machinability of steel can be improved by alloying the steel with (a) Copper (b) Chromium (c) Nickel (d) Sulphur 119. If T is the recrystallization temperature, the cold working of steel is done at (a) greater than T °C (b) equal to T °C (c) less than T °C (d) None of these 120. Pure iron at room temperature has following micro structure : (a) γ-iron (b) δ-iron (c) Cementite (d) α-iron 121. Which of the following materials is not desirable for rivets making? (a) Mild steel (b) Cast iron (c) Aluminium (d) Copper 122. When a nut is tightened by placing a washer below it, the bolt will be subjected to (a) Tensile stress (b) Compressive stress (c) Shear stress (d) None of these 123. Nichrome is used in (a) Gas turbine (b) Air craft engine (c) Heater element (d) Brake lining 124. In case of straight turning operation, length of work piece is 120 mm and feed rate is 0.25 mm/sec. How long will it take to complete the turning operation? (a) 8 minute (b) 10 minute (c) 12 minute (d) None of these 125. In leaf springs, the longest leaf is known as (a) Lower leaf (b) Master leaf (c) Upper leaf (d) None of these
KAU-05 21 Series-A
112. “Öß´Ö›Ìü¯Ö®Ö ×®Ö´®Ö ÃÖê ÃÖÓ²Ö×®¬ÖŸÖ Æîü :
(a) •Ö›ÌüŸ¾Ö †Ö‘ÖæÞÖÔ (b) ÛúšüÖê¸üŸÖÖ
(c) ŸÖ®ÖÖ¾Ö ´Öë ™æü™ü®Öê ÃÖê ¯ÖÆü»Öê †¾Ö¿ÖÖê×ÂÖŸÖ ‰ú•ÖÖÔ (d) ÁÖÖÓ×ŸÖ ³ÖÖ¸ü
113. †»ÖÖîÆü ¯Ö¤üÖ£ÖÖí ´Öë ¿Ö׌ŸÖ ¯ÖϤüÖ®Ö Ûú¸ü®Öê Ûúß ÃÖ²ÖÃÖê ¯ÖϳÖÖ¾Öß ×¾Ö×¬Ö ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ÃÖß Æîü?
(a) šüÖêÃÖ ‘ÖÖê»Ö ÛúšüÖê¸üßÛú¸üÞÖ (b) ×¾ÖÛéú×ŸÖ ÛúšüÖê¸üßÛú¸üÞÖ
(c) ÛúÞÖ ´ÖÖ¯Ö ¿Öã¨üßÛú¸üÞÖ (d) †¾ÖõÖê¯ÖÞÖ ÛúšüÖê¸üßÛú¸üÞÖ
114. ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ÃÖß †×ÛÎúÙü»ÖßμÖ ¬ÖÖŸÖã Æîü?
(a) ÃÖßÃÖÖ (b) ¯ÖßŸÖ»Ö (c) ÛúÖÑ“Ö (d) “ÖÖѤüß
115. ‡®Ö´Öë ÃÖê ÛúÖî®Ö ÃÖß ÃÖŸÖÆü ÛúšüÖê¸üßÛú¸üÞÖ ¯ÖÏ×ÛÎúμÖÖ Æîü?
(a) ÛúÖ²ÖæÔ¸üևؕÖÝÖ (b) ®ÖÖ‡™Òüև؛üÝÖ (c) ÃÖÖ‡®Öև؛üÝÖ (d) μÖê ÃÖ³Öß
116. Ùüᯙ ¿Öß™ü ÛúÖê ÛúÖ™ü®Öê ´Öë ¯ÖÏμÖãŒŸÖ ”êû®Öß ÃÖÖ´ÖÖ®μÖŸÖμÖÖ
(a) †®Öß»›ü ÆüÖêŸÖß Æî …ü (b) ®ÖÖò´ÖÔ»ÖÖ‡•›ü ÆüÖêŸÖß Æîü …
(c) ÛúšüÖê¸üßÛéúŸÖ ÆüÖêŸÖß Æîü … (d) ÛúšüÖê¸üßÛéúŸÖ ‹¾ÖÓ ™êü´¯Ö¸ü›Ëü ÆüÖêŸÖß Æîü …
117. ‡Ã¯ÖÖŸÖ ´Öë ×®Ö×Ûú»Ö ×´Ö»ÖÖ®Öê ÃÖê ÃÖã¬ÖÖ¸ü ÆüÖêŸÖÖ Æîü
(a) ±îú×™üÝÖ ¯ÖÏןָüÖê¬Ö®Ö ´Öë (b) ÛÎúß¯Ö ¯ÖÏןָüÖê¬Ö®Ö ´Öë
(c) •ÖÓÝÖ ¯ÖÏןָüÖê¬Ö®Ö ´Öë (d) ´Öæ»μÖ ‘Ö™üÖ®Öê ´Öë
118. ‡Ã¯ÖÖŸÖ Ûúß ´Ö¿Öß®Ö®Ö õÖ´ÖŸÖÖ ²ÖœÌüÖ®Öê Ûêú ×»Ö‹ ‡Ã¯ÖÖŸÖ ´Öë ×´Ö»ÖÖμÖÖ •ÖÖŸÖÖ Æîü
(a) ŸÖÖѲÖÖ (b) ÛÎúÖê×´ÖμÖ´Ö (c) ×®Ö×Ûú»Ö (d) ÝÖÓ¬ÖÛú (ÃÖ»±ú¸ü)
119. μÖפü ‘T’ ü׸ü×ÛÎúÙü»ÖÖ‡•Öê¿Ö®Ö ŸÖÖ¯Ö´ÖÖ®Ö Æîü, ŸÖÖê ‡Ã¯ÖÖŸÖ Ûêú ×»ÖμÖê †ŸÖ¯ŸÖ ºþ¯ÖÞÖ ×ÛúμÖÖ •ÖÖŸÖÖ Æîü
(a) T °C ÃÖê †×¬ÖÛú ¯Ö¸ü (b) T °C Ûêú ²Ö¸üÖ²Ö¸ü ¯Ö¸ü
(c) T °C ÃÖê Ûú´Ö ¯Ö¸ü (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
120. ÛúõÖ ŸÖÖ¯Ö´ÖÖ®Ö ¯Ö¸ü ¿Öã¨ü »ÖÖîÆü Ûúß ÃÖæõ´Ö ÃÖÓ¸ü“Ö®ÖÖ ×®Ö´®Ö×»Ö×ÜÖŸÖ Æîü :
(a) ÝÖÖ´ÖÖ †Ö‡¸ü®Ö (b) ›êü»™üÖ †Ö‡¸ü®Ö (c) ÃÖß´Öê®™üÖ‡™ü (d) ‹»±úÖ †Ö‡¸ü®Ö
121. ×®Ö´®Ö ´Öë ÃÖê ÛúÖî®Ö ÃÖÖ ¯Ö¤üÖ£ÖÔ ×¸ü¾Öê™ü ²Ö®ÖÖ®Öê Ûêú ×»Ö‹ ˆ¯ÖμÖãŒŸÖ ®ÖÆüà Æîü?
(a) ´Öé¤ãü ‡Ã¯ÖÖŸÖ (b) œü»Ö¾ÖÖÑ »ÖÖêÆüÖ (c) ‹»μÖã×´Ö×®ÖμÖ´Ö (d) ŸÖÖѲÖÖ
122. •Ö²Ö ‹Ûú ®Ö™ü ÛúÖê ®Öß“Öê ¾ÖÖ¿Ö¸ü ¸üÜÖÛú¸ü ÛúÃÖÖ •ÖÖŸÖÖ Æîü, ŸÖÖê ²ÖÖê»™ü ´Öë »ÖÝÖŸÖÖ Æîü
(a) ŸÖ®ÖÖ¾Ö ¯ÖÏ×ŸÖ²Ö»Ö (b) ÃÖÓ¯Öß›ü®Ö ¯ÖÏןֲֻÖ
(c) †¯Öºþ¯ÖÞÖ ¯ÖÏ×ŸÖ²Ö»Ö (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
123. ®ÖÖ‡ÛÎúÖò´Ö ÛúÖ ¯ÖÏμÖÖêÝÖ ×ÛúμÖÖ •ÖÖŸÖÖ Æîü
(a) ÝÖîÃÖ ™ü¸ü²ÖÖ‡®Ö ´Öë (b) ‹†¸ü ÛÎúÖ°™ü ‡Ó•Ö®Ö ´Öë
(c) Æüß™ü¸ü ‹»Öß´Öë™ü ´Öë (d) ²ÖÎêÛú †ÃŸÖ¸ü (»ÖևخÖÝÖ) ´Öë
124. ÃÖ߬Öß ÜÖ¸üÖ¤ü®Ö Ûúß ‹Ûú ¯ÖÏ×ÛÎúμÖÖ ´Öë ÛúÖμÖÔÜÖÞ›ü Ûúß »Ö´²ÖÖ‡Ô 120 mm ¾Ö ±úß›ü ¤ü¸ü 0.25 mm/sec Æîü … ÜÖ¸üÖ¤ü®Ö ¯ÖÏ×ÛÎúμÖÖ
ÛúÖê ¯Öæ¸üÖ Ûú¸ü®Öê ´Öë ×ÛúŸÖ®ÖÖ ÃÖ´ÖμÖ »ÖÝÖêÝÖÖ?
(a) 8 ×´Ö®Ö™ü (b) 10 ×´Ö®Ö™ü
(c) 12 ×´Ö®Ö™ü (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
125. »Öß±ú ØïÖÏÝÖ ´Öë ÃÖ²ÖÃÖê ²Ö›Ìüß »Öß±ú ÛúÖê ÛúÆüÖ •ÖÖŸÖÖ Æîü
(a) ×®Ö“Ö»Öß »Öß±ú (b) ´ÖÖÙü¸ü »Öß±ú
(c) ‰ú¯Ö¸üß »Öß±ú (d) ˆ¯Ö¸üÖêŒŸÖ ´Öë ÃÖê ÛúÖê‡Ô ®ÖÆüà
