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CH 8: Interval Estimation (Part 1: for mean), Exams of Statistics

(A) Interval estimate (Confidence Interval): An estimate of a population parameter that provides an interval believed to contain the value of the parameter.

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2021/2022

Uploaded on 09/27/2022

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CH 8: Interval Estimation (Part 1: for mean)
1. Basic Concepts
(A) Interval estimate (Confidence Interval): An estimate of a population parameter that
provides an interval believed to contain the value of the parameter. Note: the interval
estimate has the form: point estimate ±margin of error.
(B) Confidence level: The probability of including the population parameter within the
confidence interval at 100(1 α)%. Say 95%, 99%, etc.
(C) αis called the level of significance. In this case, it is the probability that the interval
estimation procedure will generate an interval that does not contain the parameter.
(D) Why does it work?
2. Case I: 100(1 α)% confidence interval estimation of the mean µ(σknown).
(A) formula:
x±Zα/2
σ
n(eq8.1)
Note: We assume: (a) The population is normally distributed or nis large; (b) The
population standard deviation σis known. (c) Zα/2is called the critical value and
Zα/2σ
nis the margin of error for the estimation.
(B) Zα/2notation:
Zα/2= the right-tail (upper tail) probability α/2 point of the standard normal; i.e., the
area to the right of Zα/2is α/2.
EX 1 Find the values of Zα/2for 90%, 95% and 99%
(1) 90%
(2) 95%
(3) 99%
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CH 8: Interval Estimation (Part 1: for mean)

  1. Basic Concepts

(A) Interval estimate (Confidence Interval): An estimate of a population parameter that provides an interval believed to contain the value of the parameter. Note: the interval estimate has the form: point estimate ± margin of error.

(B) Confidence level: The probability of including the population parameter within the confidence interval at 100(1 − α)%. Say 95%, 99%, etc. (C) α is called the level of significance. In this case, it is the probability that the interval estimation procedure will generate an interval that does not contain the parameter. (D) Why does it work?

  1. Case I: 100(1 − α)% confidence interval estimation of the mean μ (σ known).

(A) formula: x ± Zα/ 2

σ √ n

(eq8.1)

Note: We assume: (a) The population is normally distributed or n is large; (b) The population standard deviation σ is known. (c) Zα/ 2 is called the critical value and Zα/ 2 √σn is the margin of error for the estimation.

(B) Zα/ 2 notation:

Zα/ 2 = the right-tail (upper tail) probability α/2 point of the standard normal; i.e., the area to the right of Zα/ 2 is α/2. EX 1 Find the values of Zα/ 2 for 90%, 95% and 99% (1) 90%

(C) Using the formula EX 2 The computer paper is expected to have a standard deviation of 0.02inch. 100 sheets are selected and the mean is 10.998 inches. Set up a 95% confidence interval estimates of the population mean paper length.

  1. Case II: 100(1 − α)% confidence interval estimation of the mean μ (σ unknown).

(A) Formula:

x ± tα/ 2

s √ n

(eq8.2)

where s is the sample standard deviation. (B) Student’s t distribution: Let x 1 , x 2 ,... xn be a random sample from a normal population with mean μ and standard deviation σ, then t =

x − μ √^ s n

is called the t-distribution with

(n − 1) degrees of freedom.

(C) tα/ 2 notation

(D) How to read the t-table:

(E) How to use (eq8.6)

Step 1: Find the sample proportion ¯p =

x n

Step 2: Find the critical value Zα/ 2. Step 3: Compute the confidence interval.

EX 4 A company wants to determine the frequency of occurrence of invoices error. Suppose that in a sample of 100 sales invoices, 10 contain errors. Construct a 90% confidence interval for the true proportion of error.

EX 5 Out of 268 interviewed, 83 people said that they would buy a certain product. Use a 95% confidence interval to estimate the true proportion of the customer who would buy the product.