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Analog CMOSLecture 12, Slides of Analog Electronics

ECE515 course in IIITD, lecture slide-13 regarding differential amplifier

Typology: Slides

2016/2017

Uploaded on 11/08/2017

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ECE 315/515
Analog CMOS Circuit Design
Lecture 12
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ECE 315/

Analog CMOS Circuit Design

Lecture 12

2 Outline

  • Mid-term examination
    • 2:30-4:30 p.m., September 20, 2017
    • Allowed items: Course textbooks; Calculator
  • Basic Differential Pair
    • Impact of Finite Output Impedance of Current Source
    • Impact of Asymmetries in the Circuit
    • Common-mode rejection ratio
  • Differential Pair with MOS Loads
  • Glibert Cell

• M

1 and M 2 are “in parallel”

  • Can be reduced to one composite device with twice the width, bias current and transconductance
  • “Common - mode gain” of the circuit is ( λ = γ = 0)
  • Input CM variations disturb bias points (introduces common- mode gain), and affect small-signal gain and output swings Impact of Finite O/P Impedance Current Source

Impact of R D Mismatch & Finite O/P Impedance

  • Since the circuit is not fully symmetric, change in Vin,CM results in variation in differential output
  • RD1 = RD , RD2 = RD + ΔRD, where ΔRD denotes a small mismatch and circuit is otherwise symmetric
  • M 1 and M 2 operate as one source follower, changing V P by (a ssume λ = γ = 0)
  • Common-mode response depends on output impedance of tail current source and asymmetries in the circuit
  • Two effects:
    • Variation of output CM level (in the absence of mismatches)
    • Conversion of input CM variations to output differential components (more severe)
  • Analyze common-mode response considering mismatches Impact of R D Mismatch & Finite O/P Impedance

Common-mode to differential conversion

  • CM to differential conversions become significant at high frequencies
  • Total capacitance shunting the tail current source introduces larger tail current variations
  • This capacitance arises from parasitics of the current source and source-bulk junctions of M 1 and M 2
  • Thus,
  • We now obtain the output voltages as
  • The differential component at the output is Impact of Transistor Mismatch
  • The circuit converts input CM variations to a differential error by a factor of
  • ACM-DM denotes common-mode to differential-mode conversion and Δg m = g m - g m Impact of Transistor Mismatch

Differential Pair with MOS Loads

  • Differential pairs can employ diode-connected or current- source loads
  • For diode-connected loads, small-signal differential gain is (half-circuit analysis):  N and P subscripts denote NMOS and PMOS respectively

Differential Pair with MOS Loads

  • Expressing g mN and g mP in terms of device dimensions,
  • For current-source loads, the gain is

Differential Pair with MOS Loads

  • gm of load devices M 3 and M 4 can be lowered by reducing their current instead of ( W/L ) P for the same overdrive voltage
  • For I D

= I

D

= 0.8 I

D

= 0.8 I

DID3 and ID4 are reduced by a factor of 5  For a given overdrive, g mP is lowered by the same factor  Differential gain is five times that of the case without auxiliary PMOS current sources (assume λ = 0)

Cascode Differential Pair

  • Small-signal voltage gain of differential pair with current-source loads can be increased via cascoding
  • Increases output impedance of both NMOS and PMOS devices
  • But at the cost of lower voltage headroom
  • The gain is calculated using the half-circuit technique

Gilbert Cell

  • Differential pair whose gain is controlled by a control voltage
  • Behaves as a Variable Gain Amplifier (VGA)
  • Used where signal amplitude experiences large variations and hence inverse changes in gain are required
  • Control voltage V cont controls the tail current and hence gain
  • A v

= V

out

/ V

in is variable

  • Zero for ID3 = 0
  • Maximum defined by voltage headroom limitations and device dimensions

Gilbert Cell

  • An amplifier whose gain can be continuously varied from a negative to a positive value
  • Figure shows two differential pairs that amplify the input by opposite gains
  • Here, V out

/ V

in = - g m

R

D and V out

/ V

in = +g m

R

D

  • If I 1 and I 2 vary in opposite directions, so do | Vout1 / Vin | and | V out

/ V

in