



Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
A mathematical theorem (Theorem 1) that improves Bessel's inequality in inner product spaces. The theorem states that under certain conditions, the square of the semi-norm of a vector x in a linear space X with respect to a positive hermitian form (·, ·)2 is greater than or equal to the square of the semi-norm of x with respect to another positive hermitian form (·, ·)1, minus the sum of the products of the inner products of x with certain orthornormal families in X. The proof of the theorem relies on Lemma 1 and the properties of hermitian forms.
Typology: Study notes
1 / 5
This page cannot be seen from the preview
Don't miss anything!
S.S. DRAGOMIR
Abstract. A monotonicity property of Bessel’s inequality in inner product
spaces is given.
Let X be a linear space over the real or complex number field K. A mapping
(·, ·) : X × X → K is said to be a positive hermitian form if the following conditions
are satisfied:
(i) (αx + βy, z) = α (x, z) + β (y, z) for all x, y, z ∈ X and α, β ∈ K;
(ii) (y, x) = (x, y) for all x, y ∈ X;
(iii) (x, x) ≥ 0 for all x ∈ X.
If ‖x‖ := (x, x)
1 (^2) , x ∈ X denotes the semi-norm associated to this form and
(ei) i∈I is an orthornormal family of vectors in X, i.e., (ei, ej ) = δij (i, j ∈ I), then
one has the following inequality [15]:
(1.1) ‖x‖
2 ≥
i∈I
|(x, ei)|
2 for all x ∈ X,
which is well known in the literature as Bessel’s inequality.
Indeed, for every finite part H of I, one has:
x −
i∈H
(x, ei) ei
2
x −
i∈H
(x, ei) ei, x −
j∈H
(x, ej ) ej
= ‖x‖
2 −
i∈H
|(x, ei)|
2 −
j∈H
|(x, ej )|
2
i,j∈H
(x, ei) (ej , x) δij
= ‖x‖
2 −
i∈H
|(x, ei)|
2 ,
for all x ∈ X, which proves the assertion.
The main aim of this paper is to improve this result as follows.
The following theorem holds.
Theorem 1. Let X be a linear space and (·, ·) 2
1 two hermitian forms on
X such that ‖·‖ 2 is greater than or equal to ‖·‖ 1 , i.e., ‖x‖ 2 ≥ ‖x‖ 1 for all x ∈
X. Assume that (ei) i∈I is an orthornormal family in (X; (·, ·) 2 ) and (fi) i∈J is an
Date: January 05, 2000.
1991 Mathematics Subject Classification. Primary 26D15; Secondary 46C99.
Key words and phrases. Bessel’s inequality, Inner product spaces.
1
2 S.S. DRAGOMIR
orthornormal family in (X; (·, ·) 1 ) such that for any i ∈ I there exists a finite K ⊂ J
so that
(F) ei =
j∈K
αj fj , αj ∈ K (j ∈ K) ,
then one has the inequality:
(2.1) ‖x‖
2 2
i∈I
|(x, ei) 2
2 ≥ ‖x‖
2 1
j∈J
(x, fj ) 1
2 ≥ 0 ,
for all x ∈ X.
In order to prove this fact, we require the following lemma.
Lemma 1. Let X be a linear space endowed with a positive hermitian form (·, ·)
and (gk) k=1,n be an orthornormal family in (X; (·, ·)). Then
x −
n ∑
k=
λkgk
2
≥ ‖x‖
2 −
n ∑
k=
|(x, gk)|
2 ≥ 0 ,
for all λk ∈ K and x ∈ X (k = 1, ..., n).
Proof. We will prove this fact by induction over “n”.
Suppose n = 1. Then we must prove that
‖x − λ 1 g 1 ‖
2 ≥ ‖x‖
2 − |(x, g 1 )|
2 , x ∈ X, λ 1 ∈ K.
A simple computation shows that the above inequality is equivalent with
|λ 1 |
2 − 2 Re (x, λ 1 g 1 ) + |(x, g 1 )|
2 ≥ 0 , x ∈ X, λ 1 ∈ K.
Since Re (x, λ 1 g 1 ) ≤ |(x, λ 1 g 1 )|, one has
|λ 1 |
2 − 2 Re (x, λ 1 g 1 ) + |(x, g 1 )|
2 ≥ |λ 1 |
2 − 2 |λ 1 | |(x, g 1 )| + |(x, g 1 )|
2
≥ (|λ 1 | − |(x, g 1 )|)
2 ≥ 0
for all λ 1 ∈ K and x ∈ X, which proves the statement.
Now, assume that (2.2) is valid for “(n − 1)”. Then we have:
x −
n ∑
k=
λkgk
2
(x − λngn) −
n− 1 ∑
k=
λkgk
≥ ‖x − λngn‖
2 −
n− 1 ∑
k=
|(x − λngn, gk)|
2
= ‖x − λngn‖
2 −
n− 1 ∑
k=
|(x, gk)|
2 ≥ ‖x‖
2 − |(x, gn)|
2 −
n− 1 ∑
k=
|(x, gk)|
2
= ‖x‖
2 −
n ∑
k=
|(x, gk)|
2 ,
for all λk ∈ K, x ∈ X (k = 1, ..., n) , and the proof of the lemma is complete.
4 S.S. DRAGOMIR
and since ‖y‖ 2 ≥ ‖y‖ 1 , the inequality (2.3) is obtained.
Remark 1. For a different proof of (2.3), see also [5].
Now, we will give some natural applications of the above theorem.
(1) Let (X; (·, ·)) be an inner product space and (ei) i∈I an orthornormal family
in X. Assume that A : X → X is a linear operator such that ‖Ax‖ ≤ ‖x‖
for all x ∈ X and (Aei, Aej ) = δij for all i, j ∈ I. Then one has the
inequality
‖x‖
2 −
i∈I
|(x, ei)|
2 ≥ ‖Ax‖
2 −
i∈I
|(Ax, Aei)|
2 ≥ 0
for all x ∈ X.
The proof follows by the hermitian forms (x, y) 2 = (x, y) and (x, y) 1
(Ax, Ay) for x, y ∈ X and for the family (fi) i∈I = (ei) i∈I
(2) If A : X → X is such that ‖Ax‖ ≥ ‖x‖ for all x ∈ X, then, with the
previous assumptions, we also have
0 ≤ ‖x‖
2 −
i∈I
|(x, ei)|
2 ≤ ‖Ax‖
2 −
i∈I
|(Ax, Aei)|
2 ,
for all x ∈ X.
(3) Suppose that A : X → X is a symmetric positive definite operator with
(Ax, x) ≥ ‖x‖
2 for all x ∈ X. If (ei) i∈I is an orthornormal family in X
such that (Aei, Aej ) = δij for all i, j ∈ I, then one has the inequality
0 ≤ ‖x‖
2 −
i∈I
|(x, ei)|
2 ≤ (Ax, x) −
i∈I
|(Ax, ei)|
2 ,
for all x ∈ X.
The proof follows from the above theorem for the choices (x, y) 1 = (Ax, y)
and (x, y) 2 = (x, y) , x, y ∈ X. We omit the details.
For other inequalities in inner product spaces, see the papers [1]-[14] and [7]-[6]
where further references are given.
References
[1] S.S. DRAGOMIR, A refinement of Cauchy-Schwartz inequality, G.M. Metod. (Bucharest),
8 (1987), 94-95.
[2] S.S. DRAGOMIR, Some refinements of Cauchy-Schwartz inequality, ibid, 10 (1989), 93-95.
[3] S.S. DRAGOMIR and B. MOND, On the Boas-Bellman generalisation of Bessel’s inequality
in inner product spaces, Italian J. of Pure and Appl. Math., 3 (1998), 29-38.
[4] S.S. DRAGOMIR and B. MOND, On the superadditivity and monotonicity of Gram’s in-
equality and related results, Acta Math. Hungarica, 71 (1-2) (1996), 75-90.
[5] S.S. DRAGOMIR and B. MOND, On the superadditivity and monotonicity of Schwartz’s
inequality in inner product spaces, Contributions Macedonian Acad. Sci. and Arts, 15 (2)
(1994), 5-22. [6] S.S. DRAGOMIR, B. MOND and Z. PALES, On a supermultiplicity property of Gram’s
determinant, Aequationes Mathematicae, 54 (1997), 199-204.
[7] S.S. DRAGOMIR, B. MOND and J.E. PE CARI ˇ C, Some remarks on Bessel’s inequality in´
inner product spaces, Studia Univ. “Babes-Bolyai”, Math., 37 (4) (1992), 77-86.
[8] S.S. DRAGOMIR and J. SANDOR, On Bessel’s and Gram’s inequalities in prehilbertian
spaces, Periodica Math. Hungarica, 29 (3) (1994), 197-205.
BESSEL’S INEQUALITY 5
[9] S.S. DRAGOMIR and J. S ANDOR, Some inequalities in prehilbertian spaces,´ Studia Univ.
“Babe¸s-Bolyai”, Mathematica, 1, 32 , (1987), 71-78.
[10] W.N. EVERITT, Inequalities for Gram determinants, Quart. J. Math., Oxford, Ser. (2),
8 (1957), 191-196.
[11] T. FURUTA, An elementary proof of Hadamard theorem, Math. Vesnik, 8( 23 )(1971), 267-
[12] C.F. METCALF, A Bessel-Schwartz inequality for Gramians and related bounds for deter-
minants, Ann. Math. Pura Appl., (4) 68 (1965), 201-232.
[13] D.S. MITRINOVI ´C, Analytic Inequalities, Springer-Verlag, Berlin-Heidelberg and New York,
[14] C.F. MOPPERT, On the Gram determinant, Quart. J. Math., Oxford, Ser (2), 10 (1959),
161-164.
[15] K. YOSHIDA, Functional Analysis, Springer-Verlag, Berlin, 1966.
School of Communications and Informatics, Victoria University of Technology, P.O.
Box 14428, Melbourne City MC, Victioria 8001, Australia
E-mail address: sever.dragomir@vu.edu.au
URL: http://rgmia.vu.edu.au/SSDragomirWeb.html