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Calculations for the force, area, and pressure for two different diameters of a bottle. The calculations are based on the given diameters, heights, and atmospheric pressure. The document also includes the conversion of units from centimeters to meters and pascal to newtons.
Typology: Exercises
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DIAMETRO DEL PRIMER GLOBLO D 1 = 23 cm A= π D 2 4
π ( 23 cm) 2 4
1661.902514 cm 2 4 =415.4756284 cm 2 =0.04154756284 m 2 Con la altura que me dio del primer diámetro fue más la suma de la altura de referencia de cuando le soplamos ala botella h 1 =21.5 cm+ 5 cm=0.215 m+0.05 m=0.265 m Patm=101.325 Pa Pman=ρgh=
kg m
m s
kg m 3 ∗m s 2 ∗m=Pa Pabs=Patm+ Pman Pabs=101.325 Pa+2599.65 Pa=2700.975 Pa P=
=F=(2700.975 Pa)(0.04154756284 m 2 )=112.2189285 N 1 Pa=
m 2 F=
m 2 ∗m 2 =N
DIAMETRO DEL SEGUNDO GLOBLO D 2 = 19 cm A= π D 2 4
π ( 19 cm) 2 4
1134.114948 cm 2 4 =283.52874 cm 2 =0.028352874 m 2 Con la altura que me dio del segundo diámetro fue más la suma de la altura de referencia de cuando le soplamos ala botella h 2 = 12 cm+ 5 cm=0.12 m Patm=101.325 Pa Pman=ρgh=
kg m
m s
kg m 3 ∗m s 2 ∗m=Pa Pabs=Patm+ Pman Pabs=101.325 Pa+1177.2 Pa=1278.525 Pa P=
=F=(1278.525 Pa)(0.028352874 m 2 )=36.24985312 N