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Calculation of Force, Area, and Pressure for Two Different Diameters of a Bottle - Prof. p, Exercises of Calculus

Calculations for the force, area, and pressure for two different diameters of a bottle. The calculations are based on the given diameters, heights, and atmospheric pressure. The document also includes the conversion of units from centimeters to meters and pascal to newtons.

Typology: Exercises

2020/2021

Uploaded on 09/30/2021

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CALCULOS DE LA FUERZA, EL AREA, EL Pabs , Pman. Para cada
diámetro del globo
DIAMETRO DEL PRIMER GLOBLO
D1=23 cm
A=π D2
4=π(23 cm)2
4=1661.902514 cm2
4=415.4756284 cm2=0.04154756284m2
Con la altura que me dio del primer diámetro fue más la suma de la altura de referencia de
cuando le soplamos ala botella
h1=21.5 cm+5cm=0.215 m+0.05 m=0.265 m
Patm=101.325 Pa
Pman=ρgh=
(
1000 kg
m3
)(
9,.81 m
s2
)
(
0.265 m
)
=2599.65 Pa
kg
m3m
s2m=Pa
Pabs=Patm+Pman
P=F
A=F=PA=N
P=F
A=F=(2700.975 Pa )(0.04154756284 m2)=112.2189285 N
1Pa=N
m2
F=N
m2m2=N
pf3

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CALCULOS DE LA FUERZA, EL AREA, EL Pabs , Pman. Para cada

diámetro del globo

DIAMETRO DEL PRIMER GLOBLO D 1 = 23 cm A= π D 2 4

π ( 23 cm) 2 4

1661.902514 cm 2 4 =415.4756284 cm 2 =0.04154756284 m 2 Con la altura que me dio del primer diámetro fue más la suma de la altura de referencia de cuando le soplamos ala botella h 1 =21.5 cm+ 5 cm=0.215 m+0.05 m=0.265 m Patm=101.325 Pa Pman=ρgh=

kg m

3 )(^9 ,^.^

m s

2 )(^ 0.265^ m)=2599.65^ Pa

kg m 3 ∗m s 2 ∗m=Pa Pabs=Patm+ Pman Pabs=101.325 Pa+2599.65 Pa=2700.975 Pa P=

F

A

=F=PA=N

P=

F

A

=F=(2700.975 Pa)(0.04154756284 m 2 )=112.2189285 N 1 Pa=

N

m 2 F=

N

m 2 ∗m 2 =N

DIAMETRO DEL SEGUNDO GLOBLO D 2 = 19 cm A= π D 2 4

π ( 19 cm) 2 4

1134.114948 cm 2 4 =283.52874 cm 2 =0.028352874 m 2 Con la altura que me dio del segundo diámetro fue más la suma de la altura de referencia de cuando le soplamos ala botella h 2 = 12 cm+ 5 cm=0.12 m Patm=101.325 Pa Pman=ρgh=

kg m

3 )(^9 ,^.^

m s

2 )(^ 0.12^ m)=1177.2^ Pa

kg m 3 ∗m s 2 ∗m=Pa Pabs=Patm+ Pman Pabs=101.325 Pa+1177.2 Pa=1278.525 Pa P=

F

A

=F=PA=N

P=

F

A

=F=(1278.525 Pa)(0.028352874 m 2 )=36.24985312 N